AP Physics C: Mechanics : AP Physics C

Study concepts, example questions & explanations for AP Physics C: Mechanics

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Example Questions

Example Question #1 : Understanding Conservation Of Momentum

Two train cars, each with a mass of 2400 kg, are traveling along the same track. One car is traveling with a velocity of  east, while the other travels with a velocity of  west. The two cars collide and stick together as one mass. What is the magnitude and direction of the resulting velocity?

Possible Answers:

Correct answer:

Explanation:

Use the law of conservation of momentum:

Momentum is the product of velocity and mass:

We can expand the summation for the initial and final conditions:

Note that we are working with an inelastic collision, meaning that the two masses stick together after the collision. Because of this, they will have the same final velocity:

Use the given values to fill in the equation and solve for . Keep in mind that we must designate a positive direction and a negative direction. We will use east as positive and west as negative.

Since the final velocity is positive, we can determine that they train cars are traveling toward the east.

 

Example Question #1 : Understanding Conservation Of Momentum

A  bullet is fired at  at a block of wood that is moving in the opposite direction at a speed of . The bullet passes through the block and emerges with the speed of , while the block ends up at rest.

What is the mass of the block?

Possible Answers:

Correct answer:

Explanation:

This problem is a conservation of momentum problem. When doing these types of problems, the equation to jump to is:

It is given to us that  is  or ,  is ,  is unknown,  is .

 is  and  is .

With all this information given, the only unknown is .

Plugging everything in, we get:

 

Example Question #1 : Understanding Elastic And Inelastic Collisions

We have two balls. The first ball has mass 0.54kg and is traveling 7.1m/s to the right. It collides head-on elastically with a second ball of mass 0.95kg traveling 2.8m/s to the left. After the collision, what is the speed and direction of each ball?

1-d_collision

Possible Answers:

 to the left,  to the left

 to the right,  to the right

 to the left,  to the right

 to the left,  to the right

 to the left,  to the right

Correct answer:

 to the left,  to the right

Explanation:

We must use conservation of momentum to tackle this problem.

We are to find  and , the velocities of the balls after the collision. We know the following for the first ball:

and we know the following for the second ball:

.

After plugging these values into our conservation of momentum equation, it is clear that we can't use this equation alone to find  and ; however, since we are dealing with an elastic collision, we can use the relation below.

This relation can be derived using conservation of momentum and conservation of kinetic energy equations. Remember that kinetic energy is only conserved if the collision is elastic. We can use this relation to eliminate either   or  in our conservation of momentum equation.

Plug this into our conservation of momentum equation.

So now  is eliminated and we can solve for .

This is the speed of the second ball, and it is traveling to the right because of the positive value. Use this positive value to find  by using the relation we found earlier.

This is the speed of the first ball and it is traveling to the left due to the negative sign.

 

Example Question #2 : Understanding Elastic And Inelastic Collisions

A 30kg cart travels at 9m/s and it hits another cart of mass 46kg traveling at 4m/s in the opposite direction. After the collision, they stick together to form one cart. Find the speed of this cart

Possible Answers:

Correct answer:

Explanation:

For the 30 kg cart, we know

and for the 46 g cart, we know

.

After the collision, we have .

Use conservation of momentum to solve this problem.

Example Question #3 : Understanding Elastic And Inelastic Collisions

There are two skaters. The male skater with mass 68kg travels 15m/s North. He approaches a 60kg female skater who is travel 12m/s East; they approach each other at right angles. When they meet, they hold on to each other. At what direction and speed do they move after they meet?

Possible Answers:

from the female skater's direction

from the female skater's direction

from the female skater's direction

None of these

 from the female skater's direction

Correct answer:

from the female skater's direction

Explanation:

This is a two-dimensional inelastic collision problem and we use conservation of momentum to solve. We know the following.

Male skater: 

Female skater: ,

First, write down two equations representing conservation of momentum. One equation represents momentum in the x-direction (East-West direction), which is ,and the other gives the momentum in the y-direction (North-South direction), .

Take the y-direction of momentum and divide it by the x-direction momentum.

Simplify.

Plug in the numbers to find the angle

To find the speed at which they move at this angle we can use one of the momentum equations.

Solve for v.

Example Question #5 : Momentum

Object A has mass and initially moves to the right at . It then collides with object B, which has mass  and was initially moving to the right at . If the two objects stick together after the collision, what percentage of the initial kinetic energy has been dissipated?

Possible Answers:

Correct answer:

Explanation:

Relevant equations: 

Use conservation of momentum to determine the final velocity of the objects.

Calculate the total initial kinetic energy of the two objects.

Calculate the total final kinetic energy of the two objects.

Find the difference in kinetic energy.

This is the amount of kinetic energy lost during the inelastic collision. Express this amount as a percentage of the initial kinetic energy.

Example Question #1 : Momentum And Impulse

A baseball player hits a  baseball initially moving at , returning it at a speed of  along the same path. If the ball was in contact with the bat for , what magnitude of force did the ball experience during the moment of contact?

Possible Answers:

Correct answer:

Explanation:

Relevant equations:

Evaluate the impulse based on the mass and change of velocity.

Use the total impulse and time in the second equation.

Solve for the average force.

Example Question #1 : Momentum And Impulse

Which of the following could be used as units of impulse?

Possible Answers:

Correct answer:

Explanation:

Relevant equations:

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

Example Question #1 : Momentum And Impulse

A pitcher throws a 0.15kg baseball at  towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of . Calculate the impulse experienced by the baseball.

Possible Answers:

Correct answer:

Explanation:

To calculate the impulse, know that it is equal to the change in momentum.

Write the impulse equation in terms of mass and velocity.

In our case, the initial velocity of the baseball is  and its final velocity is , where the negative sign indicates that the ball is traveling in the opposite direction. Also, m = 0.15kg. The impulse on the ball can be calculated below.

The negative sign tells that the force on the baseball is opposed to the original momentum.

Example Question #1 : Interpreting Collision Diagrams

Collision

A 5000kg pickup truck with a 500kg load is traveling at a velocity of . It crashes with a 3000kg car traveling in the opposite direction with a velocity of . The truck (together with its load) and the car stick together after they crash. What is their velocity after the collision?

Possible Answers:

Correct answer:

Explanation:

We need to use conservation of momentum to solve this problem.

Initially, the pickup truck moves at . The load moves together with the truck so the load is also moving at .

We can calculate the truck-load momentum as follows:

Note that this is the sum of the truck's momentum AND the load's momentum. We are looking at is as a whole since they are moving together.

The car moves at . Be careful with signs here! The problem says it moves in the opposite direction. We used a positive velocity for the truck/load, so the velocity of the car should be negative if it is moving in the opposite direction. We can also see from the diagram that the car is moving to the left.

Therefore, we have that the momentum for the car as:

We can find the initial momentum of the system (truck, load, and car) via simple addition:

After the collision, we know that all three objects move together, so they all move with the same velocity. Therefore we can express the momentum of the system after the collision as follows:

 is the velocity of the objects after the collision. This is the sum of the momentum of all three objects; we were able to simplify the equation because they all move with the same velocity.

By conservation of momentum we know that the momentum of the system before the collision is equal to the momentum of the system after the collision.

Use this to solve for the final velocity.

 

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