Call Now to Set Up Tutoring:

(888) 888-0446

AP Physics 1 : Universal Gravitation

Study concepts, example questions & explanations for AP Physics 1

Create An Account

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 3 4 5 6 7 Next →

Example Question #61 : Universal Gravitation

Radius of the moon: $1.737*10^{6}m$

Mass of moon: $7.35*10^{22}kg$

Jennifer is piloting her spaceship around the moon. How fast does she need to go to oribit the moon 200km above the surface.

Possible Answers:

$790\frac{m}{s}$

$2506\frac{m}{s}$

$666\frac{m}{s}$

$1590\frac{m}{s}$

Correct answer:

$1590\frac{m}{s}$

Explanation:

The radius of the orbit will be the radius of the moon plus the altitude of the orbit.

$r_{orbit}=altitude+r_{moon}$

Converting to and plugging in values:

$r_{orbit}=2.0*10^{5}+1.737*10^{6}m$

$r_{orbit}=1.94*10^{6}m$

Centripetal force will need to equal universal gravitational force

$m_{ship}\frac{v^2}{r}=G\frac{m_{ship}m_{moon}}{r^2}$

Solving for velocity

$v=\sqrt{\frac{Gm_{moon}}{r}}$

Plugging in values:

$v=\sqrt{\frac{6.674*10^{-11}*7.35*10^{22}}{1.94*10^6}}$

$v=1590\frac{m}{s}$

Report an Error

Example Question #62 : Universal Gravitation

For a planet of mass $2.34*10^{22}kg$ and diameter 12000km what is the force of gravity on an object of mass 12kg ?

Possible Answers:

5.2N

10 N

32 N

.52 N

114 N

Correct answer:

.52 N

Explanation:

To solve this we use the universal gravitation formula

$\frac{Gm_{1}m_{2}}{r^{2}}$

where G is the gravitational constant $6.67408*10^{-11} m^3 kg^{-1} s^{-2}$

and r is the radius of the planet $\frac{12000}{2}=6000km$

plugging everything in we get $F_{g}=.52 N$

Report an Error

Example Question #63 : Universal Gravitation

In a fictional universe, two planets exist: one with a mass of 1500 kg and diameter of 1200m , the other with a mass of 7000kg and diameter of 1600m . The two planets' closest surfaces to one another are separated by a distance of 3000m . Assuming that the gravitational constant in this universe, , is $1000 \frac{N*m^{2}}{kg^{2}}$ , what is the gravitational force between the two planets?

Possible Answers:

54240 N

542.4J

5424 N

5424 J

542.4N

Correct answer:

542.4N

Explanation:

This question tests your understanding of gravitational force between two objects, and your ability to apply the formula for gravitational force.

The formula for gravitational force is as follows: $F_{g}= \frac{GM_{1}M_{2}}{r^{2}}$

In this example, we are asked to explicitly solve for the gravitational force between the two planets in this alternative universe. We are given the values for , $M_{1}$ , and $M_{2}$ . To solve for the gravitational force between the planets, we must first calculate the value of , or the distance between the centers of each planet. We are given the values of the diameters of each of the planets, and therefore, if we divide each value by , we have the values of the radii for each planet. To calculate the distance between the centers of the two planets, we must add the values of each planet's radius together, in addition to the distance between the closest surfaces of the planets. Thus, $r = \frac{1200m}{2} + \frac{1600m}{2} + 3000 m$ . After completing the arithmetic, you find that r= 4400 m .

Now, you have each of the relevant values to plug into the gravitational force formula. The calculation is shown below:

$F_{g}= \frac{GM_{1}M_{2}}{r^{2}}$

$F_{g}= \frac{(1000 \frac{N*m^{2}}{kg^{2}} * 1500 kg * 7000 kg)} {(4400 m)^{2}}$

$F_{g} = \frac{10500000000 N*m^{2}} {19360000 m^{2}}$

$F_{g} = 542.4 N$

Therefore, the gravitational force between the two planets is 542.4N .

Report an Error

Example Question #64 : Universal Gravitation

In a fictional universe, a planet and a star exist: planet (mass 6000 kg , diameter 3000 m ), and star (mass 4000 kg , diameter 2000m ). The star remains in a geosynchronous orbit around the planet. The closest surfaces of the planet and the star are separated by a distance of 4000m . Assume that the gravitational constant, , in this universe is $1500 \frac{N*m^{2}}{kg^{2}}$ . What is the magnitude of the gravitational potential energy between these two bodies?

Possible Answers:

5,538,462 N

5,538,462 J

5,539 N

5,539 J

7,385,602 J

Correct answer:

5,538,462 J

Explanation:

This question tests your understanding of gravitational potential energy between two objects, and your ability to apply the formula for gravitational potential energy.

The formula for gravitational potential energy is as follows: $U_{g}= \frac{-GMm}{r}$

In this question, you are asked to solve for the magnitude of the gravitational potential energy between the planet and the star in this alternative universe. We are given the values for , , and . To solve for the gravitational potential energy between the planets, we must first calculate the value of , or the distance between the centers of the planet and the star. We are given the values of the diameters of the planet and the star, and therefore, if we divide each value by , we have the values of the radii for each. To calculate the distance between the centers of each, we must add the values of each radius together, in addition to the distance between the closest surfaces of the two bodies. Thus, $r = \frac{3000m}{2} + \frac{2000m}{2} + 4000 m$ . After completing the arithmetic, you find that r=6500m .

Now, you have each of the relevant values to plug into the gravitational potential energy formula. The calculation is shown below:

$U_{g}= \frac{-GMm}{r}$

Because we are asked to find the magnitude of the value, we can neglect the negative sign.

$U_{g}= \frac{1500\frac{N*m^{2}}{kg^{2}}*6000kg*4000kg}{6500m}$

$U_{g} = \frac{(36000000000 N*m^{2})} {6500 m}$

$U_{g} = 5,538,462 \frac{N}{m} = 5,538,462 J$

Therefore, the magnitude of the gravitational potential energy between the two bodies is 5,538,462 J .

Report an Error

Example Question #65 : Universal Gravitation

Earth radius: 6370km

Earth mass: $5.97*10^{24}kg$

Gravity constant: $6.674*10^{-11}\frac{N*m^2}{kg^2}$

A space ship is in a perfectly circular orbit 450km above the earth. Determine its linear velocity.

Possible Answers:

$7.6*10^3 \frac{m}{s}$

$1.7*10^3 \frac{m}{s}$

$4.8*10^3 \frac{m}{s}$

$5.9*10^3\frac{m}{s}$

$9.8*10^3 \frac{m}{s}$

Correct answer:

$7.6*10^3 \frac{m}{s}$

Explanation:

In orbit, the magnitude of the centripetal force is in magnitude equal to the gravitational force:

$m_{ship}\frac{v^2}{r}=G\frac{m_{ship}m_{earth}}{r^2}$

Where is the linear velocity and is the distance from the center of the earth.

Solve for :

$v=\sqrt{\frac{G*m_{earth}}{r}}$

Plug in values, making sure to convert kilometers to meters to match the units in the answers:

$v=\sqrt{\frac{6.674*10^{-11}*5.97*10^{24}}{(6370+450)*10^3}}$

$v=7.6*10^3 \frac{m}{s}$

Report an Error

← Previous 1 2 3 4 5 6 7 Next →

View AP Physics 1 Tutors

John
Certified Tutor

Arizona State University, Bachelor of Science, Microbiology.

View AP Physics 1 Tutors

Brianna
Certified Tutor

Cedarville University, Bachelor of Science, Civil Engineering.

View AP Physics 1 Tutors

Om
Certified Tutor

Pune University India, Bachelor of Science, Physics. CUNY Graduate School and University Center, Doctor of Philosophy, Nuclea...

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

ACT Tutors in Chicago, Math Tutors in Philadelphia, Chemistry Tutors in Chicago, Biology Tutors in Chicago, Statistics Tutors in Dallas Fort Worth, LSAT Tutors in San Francisco-Bay Area, Reading Tutors in Atlanta, Chemistry Tutors in Boston, Math Tutors in Seattle, GMAT Tutors in Los Angeles

Popular Courses & Classes

SAT Courses & Classes in Boston, GRE Courses & Classes in Los Angeles, Spanish Courses & Classes in San Francisco-Bay Area, ISEE Courses & Classes in San Francisco-Bay Area, SAT Courses & Classes in Chicago, ISEE Courses & Classes in Los Angeles, SSAT Courses & Classes in Seattle, Spanish Courses & Classes in New York City, Spanish Courses & Classes in Phoenix, LSAT Courses & Classes in Dallas Fort Worth

Popular Test Prep

MCAT Test Prep in San Francisco-Bay Area, SAT Test Prep in Chicago, SAT Test Prep in Atlanta, GRE Test Prep in Miami, SSAT Test Prep in Miami, GRE Test Prep in Los Angeles, ISEE Test Prep in Boston, GMAT Test Prep in Seattle, SAT Test Prep in New York City, MCAT Test Prep in Washington DC

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

AP Physics 1 : Universal Gravitation

Study concepts, example questions & explanations for AP Physics 1

All AP Physics 1 Resources

Example Questions

Example Question #61 : Universal Gravitation

Example Question #62 : Universal Gravitation

Example Question #63 : Universal Gravitation

Example Question #64 : Universal Gravitation

Example Question #65 : Universal Gravitation

All AP Physics 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: