All AP Physics 1 Resources
Example Questions
Example Question #12 : Newton's Second Law
If a object is subjected to a force of , by how much will it accelerate?
In this question, we're being told that an object of a given mass is being subjected to a force. To solve this problem, we'll need to make use of Newton's second law, which states that an object of a given mass will accelerate at a rate that is proportional to the force that is applied. Or, written in equation form:
Plugging in the values given, we obtain:
Example Question #11 : Newton's Second Law
2 objects(named object A and object B) of equal masses and initial kinetic energy collide onto one another. During the collision, object A loses of its kinetic energy, which object B gains. Assume mass of both objects remain unchanged.
Given that object A's mass is and its velocity changes by over a period of seconds, determine the average force applied on object A.
Force is given by:
, where is mass and is acceleration.
We're given mass, but we aren't given acceleration. Since the question asks for average force , we can determine average acceleration .
, where is the change in velocity and is change in time.
In our problem, and
Example Question #12 : Newton's Second Law
A block with a mass of is pushed across a frictionless surface with a force of for a time of . What is the velocity of the block after the push?
Here we must use the following formula:
We can substitute our known values of mass and force and solve for acceleration
Since we know the acceleration and the time it acts upon the object, we can determine the final velocity through the following equation:
Example Question #11 : Newton's Second Law
Consider a block sitting at rest on an inclined plane. Find the maximum inclination angle the plane may have without the block sliding if the coefficients of kinetic and static friction are , respectively.
If the block is to remain at rest on the plane, we know that the sum of the forces acting a long the plane must be equal and opposite. This means that the gravitational force acting along the plane is equal to and opposite of the force of friction. This can be demonstrated as:
This can be rewritten as:
For the block to remain at rest, the force of static friction must exceed (for this problem we will set them equal to each other since it gives us the best approximation); solve for the angle:
Example Question #12 : Newton's Second Law
A force of is applied to a object in space.
What is the acceleration of the object?
Newton's second law states:
Where is the net force exerted upon an object, is the mass of the object and is the acceleration of the object.
We rearrange this equation to show:
Plug in our given values with and :
Example Question #13 : Newton's Second Law
If of force is continuously applied to a box with mass , what will the box's velocity be after given that it's initial velocity was ?
By Newton's second law:
, where is force, is mass, and is acceleration.
This is the acceleration. Since we're assuming this acceleration is constant over time, we can model velocity as:
where is the initial velocity.
Since the initial velocity is in our problem,
After seconds,
Example Question #14 : Newton's Second Law
A train of mass goes from to in . Calculate the deceleration in terms of .
Use work:
All energy will be kinetic.
Convert to :
Plug in values. Force will be negative as it is pointing against the direction of travel:
Solve for :
Use Newton's second law:
Plug in values:
Solve for :
Convert to
Example Question #14 : Newton's Second Law
A train of mass goes from to in . Estimate the coefficient of friction of the steel wheels on the steel rails. Assume the wheels are locked up.
Use work:
All energy will be kinetic.
Convert to :
Plug in values. Force will be negative as it is pointing against the direction of travel:
Solve for :
Use frictional force:
Plug in values:
Solve for
Example Question #21 : Newton's Second Law
Suppose that an astronaut on the moon applies a horizontal force of to a mass that is initially at rest. Considering that the acceleration due to gravity on the moon is and that there is no friction, what is the acceleration of this object?
In this question, we're told that a horizontal force is being applied to an object on the moon. We're given the magnitude of this force and the mass of the object.
We're also given the acceleration due to gravity on the moon, but this is useless information for the purposes of this question. Since the force under consideration is acting horizontally on the object, and the force due to gravity acts vertically, these two forces are treated separately; the vertical acting force of gravity will not affect the horizontal kinematics of the object's movement.
Thus, this reduces to a simple application of Newton's second law, and we can use the following equation:
Rearranging, we can isolate the term for acceleration:
Then plug in the values that we have to solve for our answer:
Example Question #22 : Newton's Second Law
Consider the following system:
Two spherical masses, A and B, are attached to the end of a rigid rod with length l. The rod is attached to a fixed point, p, which is at a height, h, above the ground. The rod spins around the fixed point in a vertical circle that is traced in grey. is the angle at which the rod makes with the horizontal at any given time ( in the figure).
The rod is initially at rest and held in the horizontal position. When it is released, what is the initial instantaneous acceleration of mass A, and in what direction? Assume the rod has a negligible mass. Neglect air resistance and internal frictional forces.
None of the other answers
This problem can be solved using the expression relating torque and angular acceleration:
We can determine the total net torque on the system using the Newton's second law.
Applying this to both masses and assuming a force in the downward direction is positive, we get:
Then using the expression for torque, we get:
Where d is half the length of the rod.
Applying this to both masses and assuming torque in the counterclockwise direction is positive, we get:
Now let's go back to the original equation:
Now we need to calculate the net moment of inertia:
Where r is half the length of the rod:
Going back to the original equation and rearranging for angular acceleration:
Then relating this to linear acceleration using:
Where r is half the length of the rod again:
We have all of our values, so we can calculate the final answer:
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