All AP Physics 1 Resources
Example Questions
Example Question #11 : Torque
You apply a force of to a wrench of length . Determine the torque experienced by the bolt on the other end. Assume the force you apply is perpendicular to the wrench.
None of these
The definition of torque is
Where
is the force
is the distance
Theta is the angle between the direction of the force and the distance.
In this case, , so .
Plugging in our remaining values:
Example Question #1051 : Newtonian Mechanics
There is a steel disk of radius and uniformly distributed mass . Assuming that it is perfectly balanced on it's center, determine how much torque would be needed to accelerate it to in .
Assume
Initial angular momentum is zero
Combine equations:
Solve for
Definition of :
Combine equations:
Plug in values:
Example Question #11 : Torque
A force is applied to the edge opposite the doorhinge of a door of radius perpendicular to the door to produce a torque . Suppose now that the force is doubled, but now acts at a point from the doorhinge at an angle of to the door.
What is the resulting torque in terms of ?
The torque is produced by a force acting at a radius . Since the force and the radius are perpendicular, then the torque equation gives us:
The new torque, which we will call is produced by a force of acting at a radius of at an angle of . Thus the torque equation gives us:
Since , plugging this in to the above gives us
Example Question #1055 : Newtonian Mechanics
Find the torque on a rod that's in length that's hit by a force at a angle.
Torque is given by:
, where is the length of the rod from the pivot point, is the force acting on the rod, and is the angle. Since we have all of these components, we can plug in and solve:
Example Question #14 : Torque
Consider the following system:
Two spherical masses, A and B, are attached to the end of a rigid rod with length l. The rod is attached to a fixed point, p, which is at a height, h, above the ground. The rod spins around the fixed point in a vertical circle that is traced in grey. is the angle at which the rod makes with the horizontal at any given time ( in the figure).
If the rod is spinning clockwise and has a velocity of when passing through the horizontal. At what value of is the net torque on the system 0? Neglect air resistance and internal friction forces.
A system will only have a net torque of 0 when it has no net force or the net force goes through its center of gravity. The only forces applied in this system is from gravity. Therefore, we need to find the orientation at which all gravitational force goes through point p. This occurs when the rod is oriented vertically, thus .
Note: will also result in a net torque of 0. At this orientation, the rod is also vertical with the masses in swapped positions.
Example Question #11 : Torque
A man is tightening a bolt with a wrench. At what angle (with the wrench being the horizontal axis) and at what distance from the bolt should the man push for maximum torque?
in the middle of the wrench
in the middle of the wrench
at the end furthest from the bolt
at the end furthest from the bolt
at the end furthest from the bolt
The equation for torque is . Looking at this equation we can infer that the maximum distance from the center would give maximum torque. Also, any angle besides or will give an absolute value of a number below one, giving us a smaller torque.
Example Question #11 : Torque
A simple pendulum with length with a block of mass attached to one end is initially at rest in the horizontal position. At time , the pendulum is released and allowed to rotate freely. What is the torque torque applied on the pendulum at ?
To calculate the torque on the pendulum, we need to know the position of the pendulum. We can find this using the following expression:
Note that we are using the cosine function because the pendulum begins at it's maximum angle. Plugging in our values:
The pendulum is still horizontal, but now on the other side. Now we can directly calculate the torque placed on the pendulum
Where the radius is the length of the pendulum and the force is the weight of the block (since the pendulum is horizontal).
Example Question #1101 : Ap Physics 1
Suppose that a force is enacted upon a bar that can rotate at its end. Assuming that each case shows the same magnitude of force, which of the following shows a situation that generates the greatest amount of torque?
All of these exhibit the same amount of net torque
For this question, we're given a number of scenarios in which an equal magnitude of force is applied to a rotating bar at a variety of different orientations and locations on the bar. We're then asked to identify which one would generate the most amount of torque.
First, let's recall that torque is a twisting force. That is, it is a force that causes an object to rotate about a pivot point, such as a sea-saw. We can write an expression for torque as follows.
Where is the magnitude of the applied force, is the distance of the applied force from the pivot point, and is the angle between the applied force vector and the surface upon which the force is being applied.
Sometimes, the equation for torque is also expressed as follows.
Where stands for the lever arm, which takes into account both and . Thus, for any given magnitude of force, the torque will be the highest when is greater and when approaches .
With this expression in mind, we can look at each image and make a qualitative assessment of which one will have the greatest torque. We're looking for a diagram in which the force vector is furthest from the pivot point, and is also oriented as close to with respect to the surface of the rotating object. This situation is described by the following picture, thus making it the correct answer.
Example Question #151 : Circular, Rotational, And Harmonic Motion
of force is applied perpendicular to a wrench. Calculate the torque generated.
None of these
Converting to and plugging in values
Example Question #152 : Circular, Rotational, And Harmonic Motion
Marc, Paul, and David all apply forces to a pendulum consisting of a rigid rod. Marc applies a force a distance from the pivot. If David applies a force of a distance from the pivot in the same direction as Marc, how much force must Paul apply in the opposite direction a distance of from the pivot if he is to make the sum of the torques about the pivot equal zero? Assume all three apply forces perpendicular to the rod.
First, we must recall the formula for torque, which is
is the distance from the pivot, called the moment arm. is the force, and is the angle relative to the normal of the object.) Since all the forces are being applied perpendicular to the surface of the rod, . Thus,
The sum of the torques must equal zero, so David's torque plus Marc's torque must be the same as Paul's torque because David and Marc are applying torques in the opposite direction as Paul. This gives us
Dividing both sides by , we get Paul's force to be
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