There are two forces at play in this scenario: the force of friction and the force of gravity. If the block is stationary, that means that the two forces cancel each other out. Therefore, we can write:

Substituting in expressions for each force, we get:

If you are unsure of whether to use cosine or sine for each force, think about the situation practically. The flatter the slope gets, the less the force of gravity will have an effect on trying to move the block down the plane, hence the use of the sine function. Also, the flatter the slope gets, the greater the normal force will become, hence the use of the cosine function.

There are two forces in play in this scenario: gravity and friction. We can use Newton's second law to form an expression with these forces:

Substituting in expressions for each force, we get:

If you are unsure of whether to use cosine or sine for each force, think about the situation practically. The flatter the slope gets, the less the force of gravity will have an effect on moving the block down the plane, hence the use of the sine function. Also, the flatter the slope gets, the greater the normal force will become, hence the use of the cosine function.

Canceling out mass and rearranging for the coefficient of friction, we get:

We need to develop an expression for the normal force on the block to solve this problem:

If you are unsure of whether to use sine or cosine, think about the system practically: the flatter the system gets, the larger the normal force will become; hence the use of the cosine function.

Rearranging for mass, we get:

Recall that the formula for determining the magnitude of the normal force on an incline is given by:

Here,  is the magnitude of the normal force,  is the mass of the object,  is the gravitational constant, and  is the angle made with the horizontal. 

In our case:

The normal force points perpendicular to the force of gravity (opposite direction) and is equal in magnitude. Because the force of gravity is equal to , we simply multiply our given mass and the force of gravity to get our answer. 

In this question, we're presented with a scenario where a person weighing  at rest is being accelerated upwards. We're then asked to determine this person's new weight while they are undergoing this acceleration.

Let's begin our analysis by first considering the person to be at rest in the elevator. In this situation, it's useful to picture a free-body diagram of the person and all of the forces acting on him/her. While at rest, there is no net force acting on this individual. Since there is no net force in the y-direction, that means that the upward forces must be exactly balanced by the downward forces. The downward force acting on the individual is the force due to gravity, while the upward force is the normal force of the elevator's floor acting on the individual.

Put another way:

Next, let's derive an expression while considering the upward acceleration of the elevator. In such a situation, there is now a net force acting on the individual, and that net upward force is due to the elevator's acceleration. Just as it was while at rest, the downward force acting on the individual in this case is still the force due to gravity, and the upward force acting on the individual is the normal force of the elevator's floor.

Written in equation form, we have:

Notice that we are solving for the new value of the normal force while the elevator is accelerating. The reason why the normal force gives us the person's weight is due to Newton's third law. When the elevator accelerates upward, the elevator exerts a (normal) force on the individual that is equal in magnitude to the person's weight, but with reversed directionality.

Finally, we can calculate the person's mass:

Plugging the relavent values into the above expression that we've derived will give us our answer.

Notice that this value is greater than the  that the person weighs while at rest. This is due to Newton's first law. When the elevator accelerates upward, the person's inertia resists this upward movement, which makes the person feel heavier. You can actually try this out for yourself next time you find an elevator!

One thing to note is that the weight measured was given in pounds instead of Newtons. We could convert the weights, but it turns out that we don't need to.

If your weight measured on Earth is

and the weight on the craft is

we know that on Earth the acceleration is . Using Newton's second law,

and

we can set  equal since the mass never changes only the weight force, and solve for ,

This makes sense that you would weigh more if you were experiencing a larger acceleration. This is interesting because you could not tell if you were standing stationary in a gravitational field or accelerating in a non-inertial reference frame. This is what is known as the Equivalence Principle.

Using Newton's second law, we can determine the answer. 

In our problem,  and .  is the acceleration due to gravity. Therefore,

The reading on a scale is really the normal force . On a flat surface, we see the person has a reading of , or . On an inclined surface, one can show that the normal force has a new magnitude of: 

This will lead the scale to read read:

Plug in values:

Solve for :