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AP Chemistry : Acid-Base Reactions

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Example Question #51 : Acid Base Reactions

A titration is a drop-by-drop mixing of an acid and a base in order to determine the concentration of an unknown solution, via addition of a solution with known concentration. A titration curve can be graphed showing the relationship between the mixture pH and the amount of known solution added.

What would the titration curve look like for a strong base being titrated with a strong acid?

Possible Answers:

A decreasing sigmoidal curve

A negatively sloped line

An increasing sigmoidal curve

A positively sloped line

Correct answer:

A decreasing sigmoidal curve

Explanation:

There are two things to consider here.

1. Since the solution is originally a strong base, the pH will be originally elevated. As a strong acid is added to the solution, the pH will decrease. As a result, the titration curve will be decreasing as the volume of titrant increases.

2. The titration curve will never be a straight line. Eventually, the strong acid will be much larger in volume than the original base; however, the pH will eventually even out at the pH of the added titrant.

Since we are titrating a strong base with a strong acid, the titration curve will be represented by a decreasing sigmoidal curve.

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Example Question #104 : Reactions And Equilibrium

Where does the flattest region of a titration curve of the titration of a weak acid with a strong base occur?

Possible Answers:

At the pKa of the acid

At a pH of 7

At a pH greater than 7

At the pKb of the base

Correct answer:

At the pKa of the acid

Explanation:

In this question, titration curve would graph the pH of acid solution versus the amount of base added. Since the base is strong and the acid is weak, we can conclude that the pH will be slightly greater than 7 at the equivalence point. The equivalence point is found in the steepest region of the curve.

The half-equivalence point is the flattest region of the titration curve and is most resistant to changes in pH. This corresponds to the pKa of the acid. Within this region, adding base (changing the x-value) results in very little deviation in the pH (the y-value). This region is also the buffer region for the given acid.

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Example Question #52 : Acid Base Reactions

You have a solution of weak base with unknown concentration. What would be a good acid with which to titrate the weakly alkaline solution, in order to determine its concentration?

Possible Answers:

Citric acid

Sodium hydroxide

Hydrofluoric acid

Stearic acid

Nitric acid

Correct answer:

Nitric acid

Explanation:

When you titrate a weak base, you want to titrate it with a strong acid. Hydrofluoric acid, citric acid, and stearic acid are all weak acids, and sodium hydroxide is a strong base. The best choice it nitric acid, a strong acid.

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Example Question #2 : Titrations And Indicators

You have a 500mL solution of a monoprotic acid with unknown concentration. You titrate it to completion with 36mL of 0.4M NaOH solution. What is $[HX]$ ?

Possible Answers:

$2.88*10^{-2}M$

$5.56*10^{-2}M$

$1.44*10^{-2}M$

$2.88\hspace{1 mm}M$

There is not enough information to solve

Correct answer:

$2.88*10^{-2}M$

Explanation:

If we are working with a monoprotic acid, our chemical equation is:

$NaOH+HX\rightarrow NaX+H_2O$

Now we will calculate the moles of $HX$ in our solution:

$36\hspace{1 mm}mL\times \frac{1\hspace{1 mm}L}{1000\hspace{1 mm}mL}\times \frac{0.4\hspace{1 mm}moles\hspace{1 mm}NaOH}{1\hspace{1 mm}L}\times\frac{1\hspace{1 mm}moles\hspace{1 mm}HX}{1\hspace{1 mm}mole\hspace{1 mm}NaOH}=1.44\times 10^{-2}\hspace{1 mm}moles\hspace{1 mm}HX$

Now we will determine the concentration from the amount of moles and the volume

$\frac{1.44\times 10^{-2}\hspace{1 mm}moles\hspace{1 mm}HX}{500\hspace{1 mm}mL}\times\frac{1000\hspace{1 mm}mL}{1\hspace{1 mm}L}=2.88\times 10^{-2}\hspace{1 mm}M$

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Example Question #3 : Titrations And Indicators

0.458g of an unknown diprotic acid is dissolved in water. It is then titrated with 21.5ml of a 0.500M NaOH solution to reach the second equivalence point. Determine the molecular weight of this unknown acid.

Possible Answers:

$170.4\frac{g}{mol}$

$35.3\frac{g}{mol}$

$42.6\frac{g}{mol}$

$85.2\frac{g}{mol}$

$21.3\frac{g}{mol}$

Correct answer:

$85.2\frac{g}{mol}$

Explanation:

To find the molecular weight, we must determine the number of moles that correspond to the 0.458g sample. At the equivalence point, the moles of hydronium ions will equal the moles of hydroxide ions.

We need to use the molarity and volume of the NaOH that was added to find the number of moles of base added. This will tell us the moles of hydroxide ions.

$mol_{acid}=mol_{base}=M*V$

$(0.500 \frac{mol}{L})(0.0215L) = 0.01075 mol$

Now, since we are working with a diprotic acid, two moles of base would be required for every one mole of the acid. The moles of acid would be:

$0.01075mol\ NaOH*\frac{1mol\ \text{acid}}{2mol\ NaOH}=0.005375mol\ \text{acid}$

Now that we know the moles of acid in the sample, we can use the given sample mass to find the molecular weight.

$MW = \frac{0.458 g}{ 0.005375 mol} = 85.2 \frac{g}{mol}$

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Example Question #5 : Titrations And Indicators

Litmus paper may be used to estimate the pH of a solution colorimetrically. The specific color change observed is dependent on the pH of the solution in which it is submerged.

Based on the following figure, what color would you expect a piece of litmus paper to turn when exposed to a sodium hydroxide solution made by adding 0.004g of anhydrous sodium hydroxide ( NaOH ) to 1L of water?

Assume the solution's volume is unchanged by the addition of the solid.

Possible Answers:

Yellow

Orange

Blue

Green

Correct answer:

Blue

Explanation:

To determine the predicted color change, the pH of the solution must be determined.

The molar mass of NaOH is approximate $40 \frac{g}{mol}$ .

NaOH is a strong base and dissociate completely in a 1:1 ratio into its counterions ( Na^+ and OH^- ).

The concentration of OH^- determines the pH of the solution and may be found by calculating the number of moles of OH^- dissolved in solution and dividing by the total volume:

$\frac{0.004g}{40g/mol} = 0.0001 mol\; OH^-$

$\frac{0.0001 mol}{1L} = 0.0001 M$

Next, we find the pOH of the solution, from which the pH may be easily determined:

$pOH = -\log[OH^-]$

$pOH = -\log[0.0001] = 4$

pH+pOH = 14

14-4 = pH = 10

According to the given figure, a pH of 10 corresponds to a color change to blue.

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Example Question #1 : Molecular Structure Of Acids And Bases

Put the following acids in order of their INCREASING acid strength: HI, HCl, HBr, HF.

Possible Answers:

HF, HBR, HI, HCl

HCl, HBr, HI, HF

HI, HBr, HCl, HF

HI, HCl, HBr, HF

HF, HCl, HBr, HI

Correct answer:

HF, HCl, HBr, HI

Explanation:

Larger halogen size leads to greater acidity because of weaker H-X interactions.

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Example Question #53 : Acid Base Reactions

Put the following acids in order of their INCREASING acid strength: HCl, HS, HBr, H2Se.

Possible Answers:

HCl, HS, HBr, H2Se

H2Se, HBr, HS, HCl

HBr, H2Se, HCl, H2S

H2S, H2Se, HCl, HBr

H2S, HCl, HBr, H2Se

Correct answer:

H2S, H2Se, HCl, HBr

Explanation:

Acid strength increases from left to right across a period and increases going down a group.

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Example Question #3 : Molecular Structure Of Acids And Bases

Put the following acids in order of their DECREASING acid strength: HOCl, HOBr, HOI, H2O.

Possible Answers:

H2O, HOI, HOBr, HOCl

H2O, HOCl, HOBr, HOI

HOCl, H2O, HOBr, HOI

HOI, HOBr, HOCl, H2O

HOCl, HOBr, HOI, H2O

Correct answer:

HOCl, HOBr, HOI, H2O

Explanation:

Acid strength of an oxy acid increases with increasing electronegativity on the halogen.

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Example Question #54 : Acid Base Reactions

Put the following acids in order of their DECREASING acid strength: HOCl, HO₂Cl, HO₃Cl, HO₄Cl.

Possible Answers:

HO₄Cl, HOCl, HO₂Cl, HO₃Cl

HOCL, HO₂Cl, HO₃Cl, HO₄Cl

HO₄Cl, HO₃Cl, HO₂Cl, HOCl

HO₂Cl, HOCl, HO₃Cl, HO₄Cl

HOCl, HO₄Cl, HO₂Cl, HO₃Cl

Correct answer:

HOCL, HO₂Cl, HO₃Cl, HO₄Cl

Explanation:

For an oxyacid, the acid strength increases as the number of oxygens increase.

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AP Chemistry : Acid-Base Reactions

Study concepts, example questions & explanations for AP Chemistry

All AP Chemistry Resources

Example Questions

Example Question #51 : Acid Base Reactions

Example Question #104 : Reactions And Equilibrium

Example Question #52 : Acid Base Reactions

Example Question #2 : Titrations And Indicators

Example Question #3 : Titrations And Indicators

Example Question #5 : Titrations And Indicators

Example Question #1 : Molecular Structure Of Acids And Bases

Example Question #53 : Acid Base Reactions

Example Question #3 : Molecular Structure Of Acids And Bases

Example Question #54 : Acid Base Reactions

All AP Chemistry Resources

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