All AP Chemistry Resources
Example Questions
Example Question #91 : Compounds And Molecules
Which of the following molecules is not capable of hydrogen bonding?
When hydrogen is bonded to a highly electronegative atom (such as nitrogen, oxygen, and fluorine), the electrons are pulled more closely to the electronegative atom than to the hydrogen nucleus. This results in a partially positive charge on the hydrogen atom, which allows it to attract partially negative charged atoms on other molecules. This type of intermolecular force is called a hydrogen bond.
Carbon and hydrogen have very similar electronegativities, so the electrons are equally shared. This makes methane a nonpolar molecule. As a result, it is incapable of hydrogen bonding with other molecules.
Example Question #5 : Intramolecular Force And Potential Energy
To which of the following atoms can hydrogen be bonded to in order for hydrogen bonding to be exhibited?
Chlorine
Iodine
Bromine
Astatine
Fluorine
Fluorine
Hydrogen bonding only occurs when hydrogen is bound to either oxygen, nitrogen, or fluorine. Only these atoms form a bond with hydrogen polar enough so hydrogen bonding to occur.
Example Question #3 : Intramolecular Force And Potential Energy
For which substance are the intermolecular forces the strongest?
may participate in hydrogen bonding, which is one of the strongest intermolecular forces. Hydrogen bonding increases a substance's boiling point, and lowers its vapor pressure.
Example Question #2 : Intramolecular Force And Potential Energy
A pure sample of an unknown substance is subjected to a series of tests to determine its identity. It is found to have a significantly higher boiling point than a sample of another substance that is approximately the same molecular weight and has a very similar atomic composition.
Which of the following would best account for this difference?
None of the other answers
The configuration of the atoms in the known substance allow for hydrogen bonding.
The configuration of the atoms in the unknown substance is more branched
The configuration of the atoms in the unknown substance makes it much less polar
The configuration of the atoms in the unknown substance allows for hydrogen bonding.
The configuration of the atoms in the unknown substance allows for hydrogen bonding.
Differences in the physcal properties of substances is often due to differences in molecular structure. Intermolecular forces can have profound effects on physical properties such as boiling point. Substances with the same molecular formula can actually behave quite differently based on how the atoms in these substances are connected. Hydrogen bonding is a strong intermolecular force that often leads to higher boiling points in substances that can hydrogen bond when compared to substances of similar molecular weights that cannot hydrogen bond with one another. Thus the presence of hydrogen bonding in the unknown substance is the best answer.
Example Question #1 : Vsepr And Bond Hybridization
What is the molecular shape of the following molecule?
SF6
trigonal bipyramidal
octahedral
hexahedral
linear
seesaw
octahedral
when a central atom of a molecule has 6 electron domains coming off of it (none of which are lone pairs of electrons), it is considered octahedral
Example Question #91 : Compounds And Molecules
What is the shape of the SO2 molecule?
Square planar
Bent
Linear
Octahedral
Trigonal planar
Bent
The answer to this question can be determined by drawing a Lewis structure of the molecule. The S atom is central, with an O atom on each side. Adding in double bonds to each O atom and placing lone pairs on the O atoms give them each an octet, which leaves 2 more lone pairs of electrons to go on the S atom, creating a bent shape.
Example Question #2 : Vsepr And Bond Hybridization
VSEPR theory predicts that a BF3 molecule will be which of the following shapes?
Tetrahedral
Bent
Square planar
Trigonal planar
Trigonal planar
Molecules with three atoms around a central atom such as BF3 are trigonal planar because electron repulsion is minimized by positioning the three attachments toward the corners of an equilateral triangle.
Example Question #1 : Vsepr And Bond Hybridization
Which of the following is not a characteristic of a preferred Lewis structure?
Negative formal charges placed on more electronegative atoms
Less separation between opposite charges
Small or no formal charges
Multiple bonds between atoms
Multiple bonds between atoms
Multiple bonds, although they may be stronger, are not necessarily favored in a Lewis structure. It is dependent on the atoms involved. Thus, this is not a criterion used in determining a preferred Lewis structure.
Example Question #4 : Vsepr And Bond Hybridization
Consider the following reaction, which occurs at high temperatures with a silver catalyst:
What is the change in the geometry of the carbon atom between the reactant and the product?
Tetrahedral to trigonal planar
Trigonal planar to tetrahedral
Square planar to trigonal planar
Tetrahedral to trigonal pyramidal
Square planar to trigonal pyramidal
Tetrahedral to trigonal planar
In the reactant, , the carbon is bound to three hydrogens and one oxygen, and it has no lone pairs, so it has a tetrahedral geometry. In the product, , the carbon is bound to two hydrogens and one oxygen, so it must be double bonded to the oxygen in order to have a complete octet. Therefore, it has a trigonal planar geometry.
Example Question #5 : Vsepr And Bond Hybridization
Figure 1: Ammonia gas formation and equilibrium
What type of geometry does ammonia exhibit?
Bent
Trigonal pyramidal
See-saw
Octahedral
Tetrahedral
Trigonal pyramidal
Ammonia exhibits a tetrahedral electron pair geometry. It has three bonded pairs (between nitrogen and each hydrogen), and one lone pair (on nitrogen). This combination forms a trigonal pyramidal molecular geometry.
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