Algebra II : Solving Equations

Study concepts, example questions & explanations for Algebra II

varsity tutors app store varsity tutors android store

Example Questions

Example Question #181 : Equations

Solve for \displaystyle x:

\displaystyle 75 = -\frac{x}{5} - 5

Possible Answers:

\displaystyle x = -350

None of the other answers.

\displaystyle x = 350

\displaystyle x = -400

\displaystyle x = 400

Correct answer:

\displaystyle x = -400

Explanation:

\displaystyle 75 = -\frac{x}{5} - 5

Step 1: Multiply both sides of the equation by 5.

\displaystyle \rightarrow 375 = -x - 25

Step 2: Add 25 to both sides of the equation.

\displaystyle \rightarrow 400 = -x

Step 3: Divide both sides of the equation by -1.

\displaystyle \rightarrow x = -400

Example Question #181 : Equations

Solve for \displaystyle x:

\displaystyle \frac{5x}{6} - 2 = 5 - \frac{x}{2} 

Possible Answers:

\displaystyle x = 7

None of the other answers.

\displaystyle x = 6

\displaystyle x = -\frac{21}{4}

\displaystyle x = \frac{21}{4}

Correct answer:

\displaystyle x = \frac{21}{4}

Explanation:

\displaystyle \frac{5x}6 - 2 = 5 - \frac{x}{2}

Step 1: Multiply both sides of the equation by 6.

\displaystyle \rightarrow 5x - 12 = 30 - 3x

Step 2: Add \displaystyle 3x to both sides of the equation, and add 12 to both sides of the equation.

\displaystyle \rightarrow 8x = 42

Step 3: Divide both sides of the equation by 8.

\displaystyle \rightarrow x = \frac{21}{4}

Example Question #2373 : Algebra Ii

Solve for \displaystyle x:

\displaystyle -24 - \frac{2x}{5} = 100 + 3x

Possible Answers:

\displaystyle x = \frac{524}{17}

\displaystyle x = -\frac{524}{17}

None of the other answers.

\displaystyle x = -\frac{620}{17}

\displaystyle x = \frac{620}{17}

Correct answer:

\displaystyle x = -\frac{620}{17}

Explanation:

\displaystyle -24 - \frac{2x}{5} = 100 + 3x

Step 1: Multiply both sides of the equation by 5.

\displaystyle \rightarrow -120 - 2x = 500 + 15x

Step 2: Add \displaystyle 2x to both sides of the equation, and subtract 500 from both sides of the equation.

\displaystyle \rightarrow -620 = 17x

Step 3: Divide both sides of the equation by 17.

\displaystyle \rightarrow x = -\frac{620}{17}

Example Question #181 : Equations

Solve:

\displaystyle 2(3x-1)+4=20

Possible Answers:

\displaystyle x=10

\displaystyle x=13

\displaystyle x=-3

\displaystyle x=1

\displaystyle x=3

Correct answer:

\displaystyle x=3

Explanation:

Take this equation step by step. First, I would do the distributive property so that the equation looks like:

\displaystyle 6x-2+4=20.

Next, combine like terms:

\displaystyle 6x+2=20.

Subtract 2 from both sides so that you get

\displaystyle 6x=18.

Then, divide by 6 so that x=3.

Example Question #52 : Solving Equations

Find \displaystyle x.

\displaystyle 2(x+4)=10

Possible Answers:

\displaystyle x=8

\displaystyle x=10

\displaystyle x=2

\displaystyle x=1

\displaystyle x=-1

Correct answer:

\displaystyle x=1

Explanation:

To find \displaystyle x you must isolate the variable on one side of the equation. In this case, start by dividing both sides of the equation by \displaystyle 2.

\displaystyle \frac{2(x+4)}{2}=\frac{10}{2}

\displaystyle x+4=5

Then, subtract \displaystyle 4 from each side.

\displaystyle x+4-4=5-4

\displaystyle x=5-4

This will leave you with the answer \displaystyle x=1.

Example Question #181 : Equations

Solve this equation: \displaystyle 3x-3=9-(12x-3)

Possible Answers:

\displaystyle x=15/9

\displaystyle x=3

\displaystyle x=3/5

\displaystyle x=9/15

\displaystyle x=1

Correct answer:

\displaystyle x=1

Explanation:

First things first, always do the same operation to each side; never subtract only from one side. We do this because of the equal sign in the middle (each side must remain equal to each other).

\displaystyle 3x-3=9-(12x-3)

First distribute the negative sign on the right side:

\displaystyle 3x-3=9-12x+3)

Now get all the x's on one side by adding 12 to BOTH sides:

\displaystyle 15x-3=9+3

Simplify the right side:

\displaystyle 15x-3=12

Isolate the X variable:

\displaystyle 15x=15

Once more, but this time by division:

\displaystyle x=1

Example Question #51 : Solving Equations

Solve the following equation:

\displaystyle -12=4+5x-20-3x

Possible Answers:

\displaystyle x=2

\displaystyle x=\frac{6}{7}

\displaystyle x=\frac{1}{2}

\displaystyle x=-14

\displaystyle x=\frac{7}{2}

Correct answer:

\displaystyle x=2

Explanation:

Collect like terms and solve for x.

\displaystyle -12=4+5x-20-3x

\displaystyle -12-4+20=5x-3x

\displaystyle 4=2x

\displaystyle x=2

Example Question #53 : Solving Equations

Solve for \displaystyle x:

\displaystyle \frac{ 15 } { 2x + 7 } = 3

Possible Answers:

\displaystyle 19

\displaystyle 3

\displaystyle 6

\displaystyle \frac{ 4}{3}

\displaystyle -1

Correct answer:

\displaystyle -1

Explanation:

To solve, we first need to get x out of the denominator so that we can start to isolate it.

Multiply both sides by \displaystyle 2x+7:

\displaystyle 3(2x + 7 ) = 15

Divide both sides by 3.

\displaystyle 2 x + 7 = 5 

Subtract 7 from both sides.

\displaystyle 2 x = -2 

Divide by 2

\displaystyle x = -1

Example Question #54 : Solving Equations

\displaystyle -2(x + 1 ) = -8

Possible Answers:

\displaystyle 4.5

\displaystyle -5

\displaystyle 3

\displaystyle -17

\displaystyle 15

Correct answer:

\displaystyle 3

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

\displaystyle -2(x + 1 ) = -8

First divide both sides by -2.

\displaystyle x + 1 = 4

Next, subtract 1 from both sides.

\displaystyle x= 3

Example Question #51 : Solving Equations

Solve for \displaystyle x:

\displaystyle 2 = \frac{ 2x - 4 }{ 3 }

Possible Answers:

\displaystyle 9

\displaystyle 5

\displaystyle 1

\displaystyle \frac{ 1}{2}

\displaystyle 20

Correct answer:

\displaystyle 5

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

 \displaystyle 2 = \frac{ 2x - 4 }{ 3 }

First multiply both sides by 3.

\displaystyle 6 = 2x - 4.

Next, add 4 to both sides.

\displaystyle 10 = 2x

Finally, divide both sides by 2.

\displaystyle 5 = x

Learning Tools by Varsity Tutors