Call Now to Set Up Tutoring:

(888) 888-0446

Algebra II : Solving Equations

Study concepts, example questions & explanations for Algebra II

Create An Account

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #232 : Equations

Solve for .

$\frac{2}{3}(x+3)=24$

Possible Answers:

Correct answer:

Explanation:

There are TWO ways:

Method : (not so preferred)

$\frac{2}{3}(x+3)=24$ Distribute $\frac{2}{3}$ .

$\frac{2x}{3}+2=24$ Subtract on both sides.

$\frac{2x}{3}=22$ Multiply $\frac{3}{2}$ on both sides.

x=33

Method : (preferred)

$\frac{2}{3}(x+3)=24$ Multiply $\frac{3}{2}$ on both sides.

x+3=36 Subtract on both sides.

x=33

Report an Error

Example Question #233 : Equations

Solve for .

$\frac{2}{3}=\frac{x}{12}$

Possible Answers:

Correct answer:

Explanation:

$\frac{2}{3}=\frac{x}{12}$ Cross-multiply.

3x=24 Divide on both sides.

x=8

Report an Error

Example Question #234 : Equations

Solve for .

$\frac{4}{x+12}=\frac{10}{85}$

Possible Answers:

32.8

24.8

35.2

Correct answer:

Explanation:

$\frac{4}{x+12}=\frac{10}{85}$ Cross-multiply. Remember the multiplies the whole expression.

10(x+12)=4*85 Distribute.

10x+120=340 Subtract 120 on both sides.

10x=220 Divide on both sides.

x=22

Report an Error

Example Question #235 : Equations

Solve

2x+5=7

Possible Answers:

x=2

x=1

x=4

x=6

x=-1

Correct answer:

x=1

Explanation:

Solve 2x+5=7 by:

The objective is to solve the equation to find what is equal to, so we need to have a value.

First subtract 5 from both sides , and we will get:

2x=2

Divide both sides by 2 and the solution is:

x=1

Report an Error

Example Question #236 : Equations

Solve:

4x+18=2x-4

Possible Answers:

x=-11

x=11

x=-7

x=10

x=-12

Correct answer:

x=-11

Explanation:

The objective is to solve the equation to find what is equal to, so we need to have a value.

4x+18=2x-4

1. Subtract from both sides, and we will have:

2x+18=-4

2. Subtract 18 from both sides, and we will have:

2x=-22

3. Divide both sides of the equation by 2 and the solution is:

x=-11

Report an Error

Example Question #101 : Solving Equations

Solve:

5x + 14 -2(x+4)=x+3(x+1)-(x-3)

Possible Answers:

No solution

x=1

All real numbers

None of the above

x=22

Correct answer:

All real numbers

Explanation:

To solve:

5x + 14 -2(x+4)=x+3(x+1)-(x-3)

1. First clear the parentheses.

5x + 14 -2x-8=x+3x+3-x+3

2. Add the variables.

3x+ 14-8=3x+3+3

3. Add the integers.

3x+ 6=3x+6

4. Subtract from each side.

6=6

Which is always true, so x can be all real numbers.

Report an Error

Example Question #101 : Solving Equations

Solve the following equation:

$\small x^2+64=-36$

Possible Answers:

$\small x=10, x=-10$

$\small x=10$

No solution

$\small x= 0$

$\small x=-10$

Correct answer:

No solution

Explanation:

To simplify this you need to isolate x by subtracting 64 from both sides then taking the square root to get:

$\small \sqrt{-100}$

you cannot take the square root of a negative number so you answer is no solution.

Report an Error

Example Question #102 : Solving Equations

Solve the following equation:

$\small -12x+36=96$

Possible Answers:

$\small x=-5$

$\small x=5$

$\small x=-6$

$\small x=-12$

$\small x=6$

Correct answer:

$\small x=-5$

Explanation:

This is a simple two step problem in which you need to isolate "x" The first step is to subtract the 36 from both sides. Upon doing this you get:

$\small -12x=60$

The next step is to divide by -12 to get "x" by itself.

Your final answer is:

$\small x=-5$

Report an Error

Example Question #240 : Equations

Solve the following equation for ,

$3x - 2 = \frac{x}{4}$

Possible Answers:

$x = \frac{8}{11}$

$x = \frac{2}{11}$

$x = -\frac{2}{11}$

$x =- \frac{11}{8}$

x = 3

Correct answer:

$x = \frac{8}{11}$

Explanation:

$3x - 2 = \frac{x}{4}$

We can start by multiplying both sides by the denominator

$4\times (3x-2)=4\times \frac{x}{4}$

12x - 8 = x

Isolate terms with on one side of the equation,

12x -x = 8

Collect terms and solve,

11x = 8

$x = \frac{8}{11}$

Report an Error

Example Question #101 : Solving Equations

Solve for a.

$\frac{a-7}{a+3}=\frac{a-9}{a-3}$

Possible Answers:

a=12

a=15

a=10

a=8

a=9

Correct answer:

a=12

Explanation:

Step 1: Cross multiply

(a-7)(a-3)=(a-9)(a+3)

Step 2: FOIL the polynomials

a^2-10a+21=a^2-6a-27

Step 3: Combine like terms & solve

48=4a

12=a

Report an Error

View Algebra 2 Tutors

Allison
Certified Tutor

Asbury University, Bachelor of Education, Mathematics Teacher Education.

View Algebra 2 Tutors

Momeena
Certified Tutor

State University of New York at New Paltz, Bachelors, Mathematics & Elementary Education. State University of New York at New...

View Algebra 2 Tutors

Karin
Certified Tutor

SUNY College at Cortland, Bachelor of Science, Mathematics Teacher Education. New York University, Master of Arts, Educationa...

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

ISEE Tutors in Dallas Fort Worth, LSAT Tutors in Miami, GRE Tutors in Los Angeles, Computer Science Tutors in Denver, Physics Tutors in Dallas Fort Worth, Calculus Tutors in Phoenix, Reading Tutors in Boston, English Tutors in Atlanta, Math Tutors in New York City, Algebra Tutors in Houston

Popular Courses & Classes

SSAT Courses & Classes in New York City, ACT Courses & Classes in Philadelphia, SAT Courses & Classes in San Diego, GRE Courses & Classes in Phoenix, MCAT Courses & Classes in Washington DC, Spanish Courses & Classes in Los Angeles, ACT Courses & Classes in Houston, SSAT Courses & Classes in Washington DC, GMAT Courses & Classes in Washington DC, ISEE Courses & Classes in Seattle

Popular Test Prep

ACT Test Prep in Houston, MCAT Test Prep in Denver, MCAT Test Prep in Philadelphia, GMAT Test Prep in Boston, ACT Test Prep in Philadelphia, LSAT Test Prep in Atlanta, GMAT Test Prep in Chicago, MCAT Test Prep in Seattle, ACT Test Prep in Dallas Fort Worth, MCAT Test Prep in New York City

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra II : Solving Equations

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #232 : Equations

Example Question #233 : Equations

Example Question #234 : Equations

Example Question #235 : Equations

Example Question #236 : Equations

Example Question #101 : Solving Equations

Example Question #101 : Solving Equations

Example Question #102 : Solving Equations

Example Question #240 : Equations

Example Question #101 : Solving Equations

All Algebra II Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: