In complex numbers of the form , a represents the real portion of the number and b represents the imaginary portion of the number. To graph  on a plane in which real numbers are represented by the x-axis and imaginary numbers are represented by the y-axis, place a point a units right of the origin and b units above the origin. The graph shows a point 2 units right and 3 units above the origin, so the complex number represented is .

In complex numbers of the form , a represents the real portion of the number and b represents the imaginary portion of the number. To graph  on a plane in which real numbers are represented by the x-axis and imaginary numbers are represented by the y-axis, place a point a units right of the origin and b units above the origin. The graph shows a point 5 units left and 2 units below the origin, so the complex number represented is .

 In complex numbers of the form , a represents the real portion of the number and b represents the imaginary portion of the number. In the complex number ,  and .

 In complex numbers of the form ,  represents the real portion of the number and  represents the imaginary portion of the number. In the complex number ,  and 

 In complex numbers of the form , a represents the real portion of the number and b represents the imaginary portion of the number. To graph  on a plane in which real numbers are represented by the x-axis and imaginary numbers are represented by the y-axis, place a point a units right of the origin and b units above the origin. The graph shows a point 4 units right and 7 units below the origin, so the complex number represented is .

In complex numbers of the form , a represents the real portion of the number and b represents the imaginary portion of the number. To graph  on a plane in which real numbers are represented by the x-axis and imaginary numbers are represented by the y-axis, place a point a units right of the origin and b units above the origin. The graph shows a point 8 units left and 1 unit above the origin, so the complex number represented is .

To solve this inequality, it is best to break it up into two separate inequalities to eliminate the absolute value function:

 or .

Then, solve each one separately:

Combining these solutions gives: 

The inequality compares an absolute value function with a negative integer. Since the absolute value of any real number is greater than or equal to 0, it can never be less than a negative number. Therefore,  can never happen. There is no solution. 

Divide both sides by 3.

Consider both the negative and positive values for the absolute value term.

Subtract 2 from both sides to solve both scenarios for .

We start by finding the midpoint of the interval, which is enclosed by 60% of 204 and 80% of 204.

We find the midpoint, or average, of these endpoints by adding them and dividing by two:

142.5 is exactly 20.5 units away from both endpoints, 122 and 163. Since we are looking for the range of numbers between 122 and 163, all possible values have to be within 20.5 units of 142.5. If a number is greater than 20.5 units away from 142.5, either in the positive or negative direction, it will be outside of the [122, 163] interval. We can express this using absolute value in the following way: