All Algebra II Resources
Example Questions
Example Question #11 : Multiplying And Dividing Rational Expressions
Simplify:
The numerator is equivalent to
The denominator is equivalent to
Dividing the numerator by the denominator, one gets
Example Question #951 : Linear Equations
(9x2 – 1) / (3x – 1) =
3x + 1
(3x – 1)2
3x
3
3x – 1
3x + 1
It's much easier to use factoring and canceling than it is to use long division for this problem. 9x2 – 1 is a difference of squares. The difference of squares formula is a2 – b2 = (a + b)(a – b). So 9x2 – 1 = (3x + 1)(3x – 1). Putting the numerator and denominator together, (9x2 – 1) / (3x – 1) = (3x + 1)(3x – 1) / (3x – 1) = 3x + 1.
Example Question #62 : Solving Rational Expressions
Simplify:
None of the above
Factor both the numerator and the denominator which gives us the following:
After cancelling we get
Example Question #11 : Multiplying And Dividing Rational Expressions
Simplify:
There is a common factor in the numerator. Pull out the common factor and rewrite the numerator.
Factorize the denominator.
Cancel the term in the numerator and denominator.
The answer is:
Example Question #111 : Rational Expressions
Multiply:
First factor the numerators and denominators of the two fractions. This allows us to re-write the original problem like this:
Now we can cancel terms that appear on both the top and the bottom, since they will divide to be a factor of . This means we can can cancel the top and bottom, the top and bottom , and the top and bottom . This leaves us with the following answer:
Example Question #112 : Rational Expressions
First, completely factor all 4 quadratics:
Now we can cancel all factors that appear on both the top and the bottom, because those will divide to a factor of . We quickly realize that all of the factors can be crossed off. This means that all of the factors have been divided to . This leves us with the following answer:
Example Question #113 : Rational Expressions
Multiply:
First, completely factor everything that can possibly be factored. This includes both numerators and the second denominator:
Now we can cancel everything that appears both on the top and the bottom, since it will divide to be a factor of :
We can simplify this by multiplying and .
This leaves us with the following answer:
Example Question #12 : Multiplying And Dividing Rational Expressions
I would first start by simplifying the numerator by getting rid of the negative exponents: . Then, combine the denominator fractions into one fraction: . At this point, we're dividing fractions so we have to multiply by the reciprocal of the second fraction: . Multiply straight across to get: . Make sure it can't be simplified (it can't)!
Example Question #633 : Intermediate Single Variable Algebra
First, combine the top two fractions. The common denominator between the two is Therefore, you just have to offset the first fraction so that it becomes . Then, combine the numerators to get . So at this point, we have: . This is essentially a dividing fractions problem. When we divide fractions, we have to make the second fraction its reciprocal (flip it!) and then multiply the two. . The 's cross out so your final answer is: .
Example Question #114 : Rational Expressions
Find the quotient of these rational expressions:
None of the other answers.
When you divide by a fraction you must multiply by its reciprocal to get the correct quotient.
Factor where able:
Cancel like terms: