All Algebra II Resources
Example Questions
Example Question #31 : Quadratic Equations And Inequalities
Use FOIL to distribute the following:
Make sure you keep track of negative signs when doing FOIL, especially when doing the Outer and Inner steps.
Example Question #32 : Quadratic Equations And Inequalities
Use FOIL to distribute the following:
When the 2 terms differ only in their sign, the -term drops out from the final product.
Example Question #13 : Foil
Simplify the expression using FOIL:
FOIL is a helpful way to remember how to multiply terms when we are multiplying two binomials.
F stands for first. We multiply the two "first" terms in each of the binomials.
O stands for outer. We multiply the outermost terms in the expression.
I stands for inner. We multiply the innermost terms in the expression.
L stands for last. We multiply the two "last" terms in each of the binomials.
F -
O -
I -
L -
Now we combine each part using addition to get:
The two terms in the middle can be combined to get our final answer:
Example Question #194 : Intermediate Single Variable Algebra
Use FOIL:
Recall that using FOIL means multiplying the first terms, then the outside terms, next the inside terms, and finally, the last terms. Therefore, after multiplying all of those, you should get: . Combine your like terms to get a final answer of: .
Example Question #33 : Quadratic Equations And Inequalities
Use FOIL:
Recall that FOIL means multiplying the first terms, then outside terms, next inside terms, and then the last terms. Therefore, when you do those steps, you get: . Simplify the middle terms to get your answer of .
Example Question #34 : Quadratic Equations And Inequalities
To solve this problem, recall that you will be using the FOIL method to mutlply these binomials: . Then, combine like terms to get your answer: .
Example Question #35 : Quadratic Equations And Inequalities
To multiply these binomials, use the FOIL method: . Combine like terms to get your answer of .
Example Question #201 : Intermediate Single Variable Algebra
A cookie company typically sells 150 cookies per week for $1 each. For every $0.05 reduction in cookie price, the company sells 5 additional cookies per week. How much should the company charge per cookie in order to maximize their profits?
This function can be expanded as
where
x=number of $0.05 changes to the initial price which will maximize potential revenue.
Since we are seeking to maximize profit, we need to find the point in this function, where a given number, x, of changes to the original price yields the greatest additional profit by balancing the additional revenue per cookie with the $0.05 decrease in cost.
In other words, we are seeking the vertex of this parabola.
First we convert the profit function into quadratic form by FOILing:
rearranging this, we find that:
Recall that
So, in order to maximize profits, we should reduce each cookie's cost by $.05 5 times.
We should sell each cookie for $0.75
Example Question #1335 : Algebra Ii
Expand .
To FOIL (First, Outer, Inner, Last), we start be multiplying the first terms together:
Then the Outer terms:
Then the Inner terms:
And finally the Last terms:
We then collect each of the answers and put them in descending order of degree of their exponent:
Example Question #202 : Intermediate Single Variable Algebra
Expand .
To FOIL (First, Outer, Inner, Last), we start by multiplying the first term in each grouping together:
Then we multiply the outer terms together (the first term in the first grouping, the last term in the second grouping):
Then we multiply the inner terms together (the second term in the first grouping, the first term in the second grouping):
And finally the last term in each grouping:
We can then collect everything back into our function:
And combine like terms (in this case, both terms with an in them):