All Algebra II Resources
Example Questions
Example Question #21 : Linear Functions
Which of the following graphs exhibit a horizontal line?
The horizontal line will always have zero slope.
In the form , the term must be zero for a horizontal line.
The forms and are non-linear.
A constant is a fixed number that will not change.
The equation represents a vertical line.
The only possible answer is:
Example Question #22 : Linear Functions
Which of the following is a horizontal line?
The horizontal lines have slopes of zero. This means that the in the slope-intercept form would leave only the y-intercept as the part of the equation.
The value of is any constant.
The equations that start with are considered vertical lines.
The correct answer is:
Example Question #23 : Linear Functions
Which of the following equations will represent a horizontal line?
The slope intercept form of an equation refers to a linear line with a certain slope and y-intercept.
In order for the line to be horizontal, the slope must equal to zero.
Any equation in the answer choices that has an x-variable is incorrect because this either means that the equation has a existing slope, a vertical line, or it's non-linear.
The best answer is:
Example Question #24 : Linear Functions
Which of the following answers is considered a vertical line?
A vertical line has an undefined slope. This also means that the x-value is fixed for every y-value of the graph.
The slope intercept form for a linear equation is . If , the slope would indicate that the line is horizontal.
Any answer that has a in the equation is incorrect.
The only valid answer is:
Example Question #25 : Linear Functions
Which of the following is an equation perpendicular to a horizontal line?
The horizontal line will have a slope of in the form of .
Recall that perpendicular lines have a slope that is the negative reciprocal of the original slope.
This indicates that the vertical line will have undefined slope. Vertical lines have a fixed x-value that will not change.
The answer that is perpendicular to a horizontal line cannot have a y-variable in the equation.
The equation represents a pair of intersecting lines.
The only possible answer is:
Example Question #21 : Vertical And Horizontal Lines
Which of these lines is the steepest or would be most difficult to walk up if the line represented a ramp?
Slope is defined as rise over run. So a slope of .7 (7/10) is the same as 7 units up and 10 units over. Compare this with the slope of 7 (7/1) which is 7 units up and only 1 unit over. The vertical distance is much greater than the horizontal and thus it is steeper.
Example Question #1 : Graphing Linear Functions
Which equation best matches the graph of the line shown above?
To find an equation of a line, we will always need to know the slope of that line -- and to find the slope, we need at least two points. It looks like we have (0, -3) and (12,0), which we'll call point 1 and point 2, respectively.
Now we need to plug in a point on the line into an equation for a line. We can use either slope-intercept form or point-slope form, but since the answer choices are in point-slope form, let's use that.
Unfortunately, that's not one of the answer choices. That's because we didn't pick the same point to substitute into our equation as the answer choices did. But we can see if any of the answer choices are equivalent to what we found. Our equation is equal to:
which is the slope-intercept form of the line. We have to put all the other answer choices into slope-intercept to see if they match. The only one that works is this one:
Example Question #1 : Graphing Linear Functions
Determine where the graphs of the following equations will intersect.
We can solve the system of equations using the substitution method.
Solve for in the second equation.
Substitute this value of into the first equation.
Now we can solve for .
Solve for using the first equation with this new value of .
The solution is the ordered pair .
Example Question #1 : Graphing Linear Functions
Refer to the line in the above diagram. It we were to continue to draw it so that it intersects the -axis, where would its -intercept be?
First, we need to find the slope of the line.
In order to move from the lower left point to the upper right point, it is necessary to move up five units and right three units. This is a rise of 5 and a run of 3. makes the slope of the line shown .
We can use this to find the -intercept using the slope formula as follows:
The lower left point has coordinates . Therefore, we can set up and solve for in this slope formula, setting :
Example Question #2 : Graphing Linear Functions
Line includes the points and . Line includes the points and . Which of the following statements is true of these lines?
The lines are parallel.
Insufficient information is given to answer this question.
The lines are perpendicular.
The lines are identical.
The lines are distinct but neither parallel nor perpendicular.
The lines are parallel.
We calculate the slopes of the lines using the slope formula.
The slope of line is
The slope of line is
The lines have the same slope, making them either parallel or identical.
Since the slope of each line is 0, both lines are horizontal, and the equation of each takes the form , where is the -coordinate of each point on the line. Therefore, line and line have equations and .This makes them parallel lines.
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