Algebra II : Factoring Polynomials
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Example Question #111 : Factoring Polynomials
Factor 
The first thing we can do is factor a 
Now we can see that each term is the square of something simpler:
We can use our squared terms formula to solve:
Example Question #111 : Factoring Polynomials
Factor
1) In order to start factoring we first want to see if the expression is divisible by any common factor. This allows to greatly simplify factoring in expressions and equations where polynomials have large coefficients.
In this case
is divisible by two, so it can be simplified to
When pulling out a number/factoring you should make sure that the simplified expression is equivalent to the unsimplified expression by doing the reverse of the operation given previously. In this case the 
2) With 
3) The expression can now be simplified to 
Example Question #113 : Factoring Polynomials
Factor:
The simplest way to solve this problem is to identify that it is a difference of two perfect squares. Recall that the factors of 
Looking back at our original function, we can see that both of our terms are perfect squares - 
Therefore, we can treat 
Example Question #114 : Factoring Polynomials
Factor the following polynomial:
The polynomial cannot be factored
The correct answer is 
Example Question #161 : Intermediate Single Variable Algebra
Factor
Cannot be factored further.
This problem is an example of a difference of squares. The formula for such a problem is 
Example Question #161 : Intermediate Single Variable Algebra
Simplify
None of the other answers
Answer cannot be simplified further.
When working with problems like these, you want to put the monomials in a standard format with the highest ordered terms on the left.
So the denominator should read:
The entire expression will then read:
Then factor out a 
The like terms then cancel leaving 
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