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Algebra II : Simplifying Exponents

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Example Questions

Example Question #181 : Simplifying Exponents

Multiply: $(3^2)^{-3} \cdot 27$

Possible Answers:

$\frac{1}{27}$

$\frac{1}{3}$

$\frac{1}{54}$

$\frac{1}{18}$

Correct answer:

$\frac{1}{27}$

Explanation:

The powers of the term enclosed by the parentheses can be multiplied by the power rule.

$(3^2)^{-3} \cdot 27 = 3^{-6}\cdot 27$

We can rewrite as three cubed.

$3^{-6}\cdot 27 = 3^{-6}\cdot 3^3$

Add the powers using the additive rule.

$3^{-6+3} = 3^{-3} = \frac{1}{3^3} = \frac{1}{27}$

The answer is: $\frac{1}{27}$

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Example Question #182 : Simplifying Exponents

Divide the exponents: $\frac{3^{-13}}{3^{-3}}\div 9^{-4}$

Possible Answers:

$\frac{1}{3}$

$\frac{1}{9}$

$\frac{1}{27}$

$\frac{1}{2}$

$\frac{4}{9}$

Correct answer:

$\frac{1}{9}$

Explanation:

Evaluate the first fraction. Since both bases on the numerator and denominator are alike, we can use the subtraction rule of exponents in order to simplify the exponents.

$\frac{3^{-13}}{3^{-3}} = 3^{-13-(-3)} = 3^{-10}$

Rewrite the expression.

$\frac{ 3^{-10}}{9^{-4}}$

Change the base of the denominator to 3^2 .

$\frac{ 3^{-10}}{9^{-4}} = \frac{ 3^{-10}}{3^{2(-4)}} = \frac{ 3^{-10}}{3^{-8}}$

Simplify by using the subtraction rule.

$\frac{ 3^{-10}}{3^{-8}} = 3^{-10-(-8)} = 3^{-2} = \frac{1}{3^2} = \frac{1}{9}$

The answer is: $\frac{1}{9}$

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Example Question #183 : Simplifying Exponents

Divide the exponents. $\frac{12}{12^{-1}}\div 3^{-1}$

Possible Answers:

243

432

$\frac{1}{3}$

Correct answer:

432

Explanation:

The first fraction can be rewritten as:

$\frac{12}{12^{-1}} = 12^{1-(-1)} = 12^{1+1} = 12^2 = 144$

The second term is the same as:

$3^{-1} = \frac{1}{3^1} =\frac{1}{3}$

Divide the two numbers.

$144\div \frac{1}{3} = 144 \times \frac{3}{1} = 432$

The answer is: 432

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Example Question #183 : Multiplying And Dividing Exponents

Evaluate: $3(9)(\frac{1}{27})^{50}$

Possible Answers:

$\frac{1}{3^{53}}$

$\frac{1}{3^{51}}$

$\frac{1}{3^{101}}$

$\frac{1}{27^{49}}$

$\frac{1}{27^{51}}$

Correct answer:

$\frac{1}{27^{49}}$

Explanation:

Multiply the integers together.

$3(9)(\frac{1}{27})^{50}=27(\frac{1}{27})^{50}$

We can rewrite the fraction to base 27 using a negative exponent.

$27(27)^{-1(50)} = 27^1 \cdot 27^{-50}$

Recall the additive property of exponents. We can sum the exponents when similar bases are multiplied.

$27^{1+(-50)} = 27^{-49} = \frac{1}{27^{49}}$

The answer is: $\frac{1}{27^{49}}$

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Example Question #184 : Simplifying Exponents

Divide: $\frac{x^{-18}}{x^{-30}} \div x^{-6}$

Possible Answers:

$x^{18}$

$\frac{1}{x^{55}}$

$\frac{1}{x^{42}}$

$\frac{1}{x^6}$

x^6

Correct answer:

$x^{18}$

Explanation:

Solve the first term. The fraction of this expression can be rewritten using the subtraction rule of exponents.

$\frac{x^{-18}}{x^{-30}} = x^{-18-(-30)} = x^{-18+30} = x^{12}$

Divide this by $x^{-6}$ .

$\frac{x^{12}}{x^{-6}}$

Repeat the process.

$x^{12-(-6)} = x^{18}$

The answer is: $x^{18}$

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Example Question #185 : Simplifying Exponents

Divide: $\frac{8^{16}}{4^{24}}$

Possible Answers:

$\frac{1}{8}$

$\frac{1}{4}$

$\frac{1}{256}$

$\frac{1}{32}$

Correct answer:

Explanation:

Convert the bases so that the numerator and denominators have the common base. We can convert both bases to base 2.

Rewrite the bases in terms of the new base using exponents.

$\frac{8^{16}}{4^{24}} = \frac{2^{3(16)}}{2^{2(24)}} = \frac{2^{48}}{2^{48}} =1$

The answer is:

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Example Question #187 : Multiplying And Dividing Exponents

Simplify the following expression using multiplication and division of exponents to its simplest form.

2*x^8*x^9

Possible Answers:

$x^{17}$

$2x^{17}$

$2x^{72}$

$2x^{18}$

$x^{72}$

Correct answer:

$2x^{17}$

Explanation:

In order to multiply exponents with the same base of the form:

$a^{x}*a^{y}$ you must add the two exponents together, where a is the base and and are the exponents. When the base in this case "" is an expression such as you must check to see if they have the same base.

If they do $a^x*a^y=a^{(x+y)}$

In the case of the problem $2 x^{8}*x^{9}$

both x^8 and x^9 share the same base of x so you're able to add the exponents getting thereby getting $2x^{8+9}$ which equals = $2x^{17}$ , which is your final answer.

This can be checked by dividing $2x^{17}$ by either 2x^8 or x^9

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Example Question #2 : Simplifying Exponents

What is the largest positive integer, , such that 2^z is a factor of 16^4 ?

Possible Answers:

Correct answer:

Explanation:

16^4 = (2^4)^4 = 2^1^6 . Thus, is equal to 16.

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Example Question #1 : Simplifying Exponents

Simplify the expression:

$(3x^4y^2)(4xy^2)^{-3}$

Possible Answers:

$\frac{3x}{64y^3}$

$\frac{3x}{64y^4}$

Cannot be simplified

$\frac{3x}{16y^3}$

Correct answer:

$\frac{3x}{64y^4}$

Explanation:

Begin by distributing the exponent through the parentheses. The power rule dictates that an exponent raised to another exponent means that the two exponents are multiplied:

$(3x^{4}y^2)(4xy^2)^{-3}= (3xy^2)(4^{-3}x^{-3}y^{-6})$

Any negative exponents can be converted to positive exponents in the denominator of a fraction:

$\frac{3x^4y^2}{64x^3y^6}$

The like terms can be simplified by subtracting the power of the denominator from the power of the numerator:

$\frac{3x^4y^2}{64x^3y^6}=\frac{3}{64}x^{4-3}y^{2-6}=\frac{3}{64}xy^{-4}$

$\frac{3x}{64y^4}$

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Example Question #1 : Simplifying Exponents

Order the following from least to greatest:

$25^{100}$

$2^{300}$

$3^{500}$

$4^{400}$

$2^{600}$

Possible Answers:

$2^{300}, 2^{600}, 3^{500}, 25^{100}, 4^{400}$

$2^{600}, 2^{300}, 25^{100}, 3^{500}, 4^{400}$

$2^{300}, 25^{100}, 2^{600}, 3^{500}, 4^{400}$

$25^{100}, 2^{300}, 2^{600}, 3^{500}, 4^{400}$

$3^{500}, 4^{400}, 2^{300}, 25^{100}, 2^{600}$

Correct answer:

$2^{300}, 25^{100}, 2^{600}, 3^{500}, 4^{400}$

Explanation:

In order to solve this problem, each of the answer choices needs to be simplified.

Instead of simplifying completely, make all terms into a form such that they have 100 as the exponent. Then they can be easily compared.

2^3^0^0 = (2^3)^1^0^0 = 8^1^0^0 , 3^5^0^0 = (3^5)^1^0^0 = 243^1^0^0 , 4^4^0^0 = (4^4)^1^0^0 = 256^1^0^0 , and 2^6^0^0 = (2^6)^1^0^0 = 64^1^0^0 .

Thus, ordering from least to greatest: 8^1^0^0, 25^1^0^0, 64^1^0^0, 243^1^0^0, 256^1^0^0 .

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Algebra II : Simplifying Exponents

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #181 : Simplifying Exponents

Example Question #182 : Simplifying Exponents

Example Question #183 : Simplifying Exponents

Example Question #183 : Multiplying And Dividing Exponents

Example Question #184 : Simplifying Exponents

Example Question #185 : Simplifying Exponents

Example Question #187 : Multiplying And Dividing Exponents

Example Question #2 : Simplifying Exponents

Example Question #1 : Simplifying Exponents

Example Question #1 : Simplifying Exponents

All Algebra II Resources

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