All Algebra II Resources
Example Questions
Example Question #132 : Data Properties
Find the mean of the dataset:
Add all the numbers and divide by the number of numbers in the dataset. There are four numbers in this dataset.
Simplify the numerator.
The answer is .
Example Question #133 : Data Properties
Billy has four exams. Each exam has a maximum of 100 points. He scored a 65 and a 60 on his first two exams. What is the minimum score he will need on his next two exams to have a final average of 80?
Billy cannot achieve the score
Set up the equation that will show the mean of Billy's four exams. The left side of the equation must equal to 80 for his final average.
Solve for . This is Billy's bare minimum to achieve his desired score.
Subtract 125 on both sides.
Divide by 2 on both sides.
Billy will need a minimum of on both exams.
Example Question #131 : Data Properties
If a student earned 98, 89, 92, 75, and 90 on five tests, what score does she need to earn to garner an 87 in the class?
Recall that finding the average requires you to add up the terms and then divide by the number of terms. Since we are trying to find the score of the sixth test, we have to remember that there are 6 terms. Therefore, our equation looks like this: . Then, solve for x, which is 78.
Example Question #132 : Data Properties
Find the mean of the following data set:
Find the mean of the following data set:
To find the mean, we simply need to sum our terms and divide by the number of terms. Our total number of terms is 11:
So our mean is 325
Example Question #42 : Mean
Find the mean of this data set:
Find the mean of this data set:
To begin, let's put our numbers in increasing order:
Next, find the sum of our terms, and divide that by the number of terms.
So our answer is 244
Example Question #137 : Data Properties
Find the mean of the following data set:
Find the mean of the following data set:
Let's begin by putting our data in increasing order:
The mean of our data set will be the same as the average. Find the sum of the terms, then divide by the number of terms (15 in this case)
So our answer is 123.
Example Question #161 : Basic Statistics
Sandra has 5 book cases. The four of the cases have 15, 17, 12, and 15 books respectively. How many books does the fifth case have in it if the mean and median number of books in each case is the same.
The median must be 15. 15 is the middle number weather the 5th number if less than 12 or more than 15. If the median is 15 the mean must also be 15.
Once we know that we use the equation of the mean to solve the problem.
Now solve for x
Multiply by 5 on both sides
Subtract 59 on both sides
Example Question #133 : Data Properties
The points per game of 10 basketball players as as follows: 12, 8, 10, 30, 14, 2, 6, 11, 10, 0. What is the mean of the total points among the ten players? (Round to the nearest whole number).
To find the mean of these numbers you must add them all up and divide by the total number of players.
You get:
which rounds to .
Example Question #164 : Basic Statistics
During a class project two students record how much time they spend outdoors (in minutes) after school for a week. The data collected is below.
Student A: 65, 60, 76, 44, 90
Student B: 70, 63, 74, 60, 102
Which of the following is true about the data above?
None of the other answers are correct.
The mean and range of student A greater than the mean and range from student B
The mean and range of student A equal to the mean and range from student B
The mean of student A is greater than the mean of student B
The range of student A is greater than the range of student B
The range of student A is greater than the range of student B
The mean of student A is
The range of studnet A is
The mean of student B is
The range of studnet B is
The range of student A is more the the range of student B.
Example Question #241 : Algebra Ii
A school district has determined that the most vaulable way to evaluate success is by using the mean of all the test scores as the basis. With this in mind, find the mean scores of 77, 80, 35, 76, 99, 95, 86, 65, 72, 56, and 21?
Here you need to add up all the numbers and then divide by the total number of numbers present.
So:
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