The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an even amount of numbers in the set meaning there are two "middle numbers"- 8 and 13. In order to find the median we take the average of 8 and 13:

$\displaystyle \frac{8+13}{2}=10.5$

The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an even amount of numbers in the set meaning there are two "middle numbers"- 24 and 26. In order to find the median we take the average of 24 and 26:

$\displaystyle \frac{24+26}{2}=25$

The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an odd amount of numbers so we just count from each side until we find the number in the middle.

$\displaystyle 32, 33, 33, 34, 35, {\color{Red} 37}, 38, 41, 42, 45, 47$

This gives us a final answer of 37 for the median.

The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an odd amount of numbers so we just count from each side until we find the number in the middle.

$\displaystyle 19, 27, 29, 30, 32, 33, {\color{Red} 33}, 34, 38, 40, 40, 40, 58$ 

This gives us a final answer of 33 for the median.

The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an odd amount of numbers so we just count from each side until we find the number in the middle.

$\displaystyle 4, 5, 6, 12, 15, 18, {\color{Red} 19}, 23, 26, 27, 31, 39, 41$ 

This gives us a final answer of 19 for the median.

The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an odd amount of numbers so we just count from each side until we find the number in the middle.

$\displaystyle 12, 15, 16, 24, 25, 31, 36$ 

This gives us a final answer of 24 for the median.

The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an odd amount of numbers so we just count from each side until we find the number in the middle.

 $\displaystyle 15, 24, 27, 28, 28, {\color{Red} 39}, 44, 47, 61, 77, 88$

This gives us a final answer of 39 for the median.

The median is the middle number of the set, when it is listed in order from smallest to largest or vice versa. In this case we have an odd amount of numbers so we just count from each side until we find the number in the middle.

$\displaystyle 14, 22, 22, 31, 32, 35, 36, {\color{Red} 37}, 39, 41, 42, 48, 50, 58, 63$

This gives us a final answer of 37 for the median.

Find the median of the following number set:

$\displaystyle 14,15,76,345,222,976,300,117,236,426$

Recall that the median is the middle value of a number set when it is arranged in ascending order. So we must begin by arranging the set in ascending order.

$\displaystyle 14,15,76,117,{\color{DarkOrange} 222,236},300,345,426,976$

In this case, because we have an even number of terms, we do not have a single middle number. This means we need to take the average of the middle two terms to find our median.

$\displaystyle Median=\frac{222+236}{2}=229$

So our answer is 229.

First regroup all numbers in chronological order.

$\displaystyle a=[-5,-1-1,0,-2,-9] = [-9,-5,-2,-1,-1,0]$

Since there is an even amount of numbers in the dataset, 6 numbers total, the median will be the average of the third and fourth numbers.

Find the mean of the two numbers.

$\displaystyle \frac{-2-1}{2}= -\frac{3}{2}$