The mean of student A is \(\displaystyle \frac{65+60+76+44+90}{5} = 67\)

The range of studnet A is \(\displaystyle 90-44 = 46\)

The mean of student B is \(\displaystyle \frac{70+63+74+60+102}{5} = 73.8\)

The range of studnet B is \(\displaystyle 102-60 = 42\)

The range of student A is more the the range of student B.

Here you need to add up all the numbers and then divide by the total number of numbers present.

So:

\(\displaystyle \small \frac{(77+80+35+76+99+95+86+65+72+56+21)}{11}\)

\(\displaystyle \small =69\)

To find the mean, first we need to solve the function for each of the variables given:

\(\displaystyle f(1)= \frac{(1)^2 +(1)}{2}=1\)

\(\displaystyle f(2)= \frac{(2)^2 +(2)}{2}=3\)

\(\displaystyle f(4)= \frac{(4)^2 +(4)}{2}=10\)

\(\displaystyle f(6)= \frac{(6)^2 +(6)}{2} =21\)

Then we add the numbers up and divide by how many numbers there were:

\(\displaystyle mean = \frac{1+3+10+21}{4}\)

\(\displaystyle mean = \frac{35}{4}\)

To find the mean, first we're going to add all the scores:

\(\displaystyle 8.7+9.2+7.8+8.3+7.2=41.2\)

Next, we divide that by the number of scores we had:

\(\displaystyle \frac{41.2}{5}=8.24\)

In order to find the mean, we would first add all the numbers up and divide by how many numbers we have.  Though we don't yet know the value for \(\displaystyle N\), we do know the mean.

\(\displaystyle mean = \frac{sum}{count}\)

\(\displaystyle 4=\frac{2+5+3+6+N}{5}\)

From here we can clear the denominator by multiplying each side by \(\displaystyle 5\), and we can do most of the addition:

\(\displaystyle 20=16+N\)

Now solving for \(\displaystyle N\):

\(\displaystyle N=4\)

The mean is the average of all the numbers in the data set.

Add all the numbers and divide them by the total amount of numbers given.

\(\displaystyle 12+(-3)+6+(-8)+1 = 8\)

There are five numbers.

Divide the sum by five.

The mean is:  \(\displaystyle \frac{8}{5}\)

The mean is the average of all the numbers given in the data set.

Sum all the numbers.

\(\displaystyle 1+0.1+0.01+3 =4.11\)

Divide this number by four.

\(\displaystyle \frac{4.11}{4}=1.0275\)

The mean is:  \(\displaystyle 1.0275\)

The mean is the sum of the numbers in the data set.

Add all the numbers.  To add the fractions, we will need to find the least common denominator.

Multiply all the denominators together.

\(\displaystyle 5\times 3\times 4 = 60\)

Convert all the numbers with a denominator of 60.  What is multiplied on the bottom must be multiplied on the top as well.

\(\displaystyle \frac{2}{5}+\frac{1}{3}+ \frac{7}{4}+(-2) = \frac{2(4)(3)}{5(4)(3)}+\frac{1(4)(5)}{3(4)(5)}+\frac{7(3)(5)}{4(3)(5)}-\frac{2(4)(3)(5)}{1(4)(3)(5)}\)

Simplify all the fractions.

\(\displaystyle \frac{24}{60}+\frac{20}{60}+\frac{105}{60}-\frac{120}{60} = \frac{29}{60}\)

Divide this fraction by four to find the mean.  Dividing by four is the same as multiplying by one-fourth.

\(\displaystyle \frac{29}{60}\times \frac{1}{4} = \frac{29}{240}\)

The answer is:  \(\displaystyle \frac{29}{240}\)

The mean of a data set is the average of all the numbers provided.

Sum all the numbers.

\(\displaystyle -5+6-9+18 = 10\)

Divide this number by the total numbers in the data set.

\(\displaystyle \frac{10}{4}= \frac{5}{2}\)

The answer is:  \(\displaystyle \frac{5}{2}\)

The mean is the average of all the numbers in the data set.

There are six numbers provided.

Sum all the numbers and divide by six.

\(\displaystyle \frac{9+10+23+56+107+108}{6} = \frac{313}{6}\)

The answer is:  \(\displaystyle \frac{313}{6}\)