All Algebra II Resources
Example Questions
Example Question #21 : Graphing Linear Functions
What is the slope of ?
To solve this, first put the linear equation into slope-intercept form:
.
Recall that in slope intercept form
,
the m term is the slope value.
Therefore, the slope is 2.
Example Question #45 : Linear Functions
How many -intercepts does the graph of the function
have?
Four
Two
Zero
One
Cannot be determined
Two
The graph of a quadratic function has an -intercept at any point at which , so, first, set the quadratic expression equal to 0:
The number of -intercepts of the graph is equal to the number of real zeroes of the above equation, which can be determined by evaluating the discriminant of the equation . Set , and evaluate:
The discriminant is positive, so there are two real solutions to the quadratic equation, and the graph of the function has two -intercepts.
Example Question #861 : Algebra Ii
Which of the following graphs correctly depicts the graph of the inequality
Let's start by looking at the given equation:
The inequality is written in slope-intercept form; therefore, the slope is equal to and the y-intercept is equal to .
All of the graphs depict a line with slope of and y-intercept . Next, we need to decide if we should shade above or below the line. To do this, we can determine if the statement is true using the origin . If the origin satisfies the inequality, we will know to shade below the line. Substitute the values into the given equation and solve.
Because this statement is true, the origin must be included in the shaded region, so we shade below the line.
Finally, a statement that is "less than" or "greater than" requires a dashed line in the graph. On the other hand, those that are "greater than or equal to" or "less than or equal to" require a solid line. We will select the graph with shading below a dashed line.
Example Question #1 : Transformations Of Linear Functions
Write the equation from the augmented matrix.
Do the first row first and use x and y to represent your variable.
Example Question #1 : Transformations Of Linear Functions
Solve for in the equation.
Solve for x by isolating the variable.
Example Question #1 : Transformations Of Linear Functions
What is the equation of the line that intersects the point and ?
We are only given the points the line intersects. This can be used to find the slope of the line, knowing that slope is rise/run, or change in /change in or by the formula,
.
By substituting, we get
for the slope.
To find the intercept, we can use the equation , where ---> .
Since both given points are on the line, either can be used to solve for :
-->
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Example Question #1 : Transformations Of Linear Functions
Which line is perpendicular to the line ?
Lines that are perpendicular have negative reciprocal slopes. Therefore, the line perpendicular to must have a slope of . Knowing that the slope of is , only has a slope of .
Example Question #2 : Transformations Of Linear Functions
Which line would never intersect a line with the slope ?
This question is very simple once you realize that a line that will never intersect another line must have the same slope (parallel lines will never intersect). Therefore you must look for the choice that has a slope of . Each answer can be converted to the form or by knowing that in the equation , the slope of the line is simply . In the correct answer, , the slope would be , which simplfies to .
*Note* the y-intercept is irrelevant to finding the correct answer.
Example Question #6 : Transformations Of Linear Functions
If the equation was shifted left three units and up one unit, what is the new equation of the line?
If the equation shifts left three units, the term will become .
The equation shifting up one unit will change the y-intercept of the equation.
Rewrite the equation and distribute to simplify.
The correct equation is:
Example Question #2 : Transformations Of Linear Functions
Write the equation of a line that is parallel and two points lower than the line .
Straight-line equations may be written in the slope-intercept form: .
In this form, equals the slope of the line and corresponds to the y-intercept.
The given line has a slope of and a y-intercept of positive . A line that is parallel to another has the same slope. Therefore, the slope of the new line will have to be .
In order to shift a line down, you must change the y-intercept. Since we are moving the line down by the y-intercept should be because .
If we plug those values into the slope-intercept equation, then we have the answer: .
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