Algebra II : Algebra II
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Example Questions
Example Question #251 : Algebra Ii
Find the mean of the following data set.
To determine the mean, sum all the numbers and divide the sum by the total numbers in the data set.
Divide this number by five.
The mean is:
Example Question #58 : Mean
If Richard scored an 80, 20, 30, and 50 on four of his five exams, what score must he make on his last exam to pass the class, assuming that the passing score is 80 out of 100 possible points?
In order to solve for Richard's final grade, we will need to set up an equation such that the average of all five scores will equal to eighty.
Let the unknown test score represent 
Multiply by five on both sides to eliminate the denominator.
Simplify both sides.
Subtract 180 from both sides of the equation.
Since this score is beyond the highest possible score that Richard earn on his last exam, he cannot pass no matter what his grade is.
The answer is:
Example Question #59 : Mean
Suppose Billy has two dollars. Susie has a fourth of what Billy has. Katie has about a third of what Susie has. What is the approximate mean of the three amounts?
Set up variables using the first letter of each person's name to identify the actual amount of money for the three individuals.
Katie's amount is rounded to the nearest cent.
Add the three values and divide the quantity by three to obtain the mean.
Divide this total by three.
The mean is:
Example Question #151 : Data Properties
Determine the mean of the set of numbers:
The mean is the average of all the numbers provided in the set of data.
Add all the numbers.
Since there are six numbers, divide this sum by six.
The answer is:
Example Question #61 : Mean
Solve for the mean:
The mean is the average of all the numbers in the data set.
Add all the numbers.
Divide this number by the total amount of numbers in the data set.
Reduce this fraction.
The answer is:
Example Question #61 : Mean
Determine the mean of the set of data:
Add all the numbers in the data set.
Convert all numbers and fractions to a least common denominator.
The least common denominator is 12 because this is the least number divisible by every denominator.
Since all the denominators are common, we can add and subtract the numerators.
Divide this number by four, or multiply by one-fourth, since there are four numbers in the data set.
The mean is:
Example Question #62 : Mean
Sarah is to compete in 4 areas at a gymnastics competition . On high bar, floor, and on vault, she scored a 9.4, 8.9, and a 9.8. The maximum score is 10. If placing top three in the competition requires her to score at least a 9.5 overall, what must she score on balance beam?
The average is already known. What is not known is Sarah's balance beam score.
Set up an equation such that the quantity of the four scores including the unknown score divided by four is equal to 9.5. Let the score of the balance beam routine be 
Multiply both sides by four to eliminate the denominator and simplify the numerator.
Subtract 28.1 from both sides to determine the unknown variable.
Sarah's score must be a 
The answer is:
Example Question #63 : Mean
Bob scores a 5, 6, and 7 on three of four tests. The highest possible score is a ten. What must he score on his next test to average an overall score of 8?
Set up an equation such that the average of Bob's three grades and his unknown fourth test grade is equal to eight.
Multiply both sides of the equation by four.
Simplify both sides.
Subtract 18 from both sides.
Bob is unable to average an 8 overall score since he would have to make a 14 on his final test grade, which is impossible since 10 is the highest score he can earn.
The answer is:
Example Question #252 : Algebra Ii
Determine the mean of the numbers:
In order to determine the mean of the set of numbers, sum the numbers provided and divide the sum by the total amount of numbers.
Divide this number by seven.
The mean is:
Example Question #161 : Data Properties
If Bob scores a 60, 80, and 90 on three of five tests in his class, what is the minimum average of Bob's fourth and fifth test scores in order for Bob to earn an overall score of 80 in his class?
The test scores of Bob's fourth and fifth tests are unknown. Let Bob's fourth test score be 
Simplify the equation. Multiply by five on both sides.
Subtract 
The sum of Bob's fourth and fifth test must add up to this value.
To average the test scores, simply divide both sides by two. This will be the minimum average of both test four and five.
The answer is:
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