It is often best to wrok one term at a time before adding. Looking at the first term, notice that we can immediately cancel the  in the numerator by rules of exponents. Also, we can factor out the  in the numerator and cancel it out with the  in the denominator, 

Notice the difference of two squares  in the denominator; It can be factored as follows, 

(It's recommended that you memorize the formula for the difference of two squares, you will see this often).  

Substituting this into the expression, 

Cancel  in the numerator and denominator, 

Now we need to add the two terms. Multiply the second term above and below by  so it has the same denominator as the first term, 

Add the numerators now that they have a common denominator, 

To simplify, it can be easier to start by expanding the function:

We can then cancel terms:

and collect them into a more simplified form:

To start, we can extract a  from both terms in the numerator to give:

Then we cancel the  terms:

First we need to follow the order of operations, and do the multiplication first.  When you multiply like variables together, you add their exponents:

At this point we can no longer add the two remaining terms because their exponents are different, so we're done.

When you multiply two terms with like variables you still multiply the constants together like normal.  In this case it would be:

The exponents would be added together for:

Putting the constant term in front, and the exponent back where it belongs, we have:

Use the distributive property to simplify the expression. The distributive property states that to multiply a sum by a term, you first multiply each part of the sum by that term separately, and then add these terms together. It looks like this in practice:

This means we multiply 5x by both terms, and then add these together.

Multiply the constant terms together, and the x's together to yield:

This expression is now simplified!

When we multiply variables with exponents, we can break up the problem into two parts.  The first is what happens to the numbers in from of the variable, and the other is what happens to the numbers that are exponents for the variable.

First, let's start with the numbers in front of the variable.  To figure this out, we simply multiply the two numbers together, like normal:

Next, let's take a look at the exponents. To figure out the exponents, we would add the two numbers together (remember you can only do this if you're multiplying/dividing; you can't add two variables unless their exponents are the same):

Now we just put the answer for the number in front of the variable and the answer for the exponents back where we found them: 

It would be easier to first expand the function to see what we're working with:

Here we can see that the  will simplify into , and that the two 's in the denominator will cancel with two of the 's in the numerator.  That leaves us with:

When we collect the terms together we end up with:

Since this is a cubed-root of terms that are multiplied together, it can be thought of as taking the cubed-root of each of the following terms -- or "how many groups of 3 are there"

: There is no cubed-root of 6, so it stays inside the root -- 

: there is 1 group of 3 in 4 with 1 left over. So one  goes outside to represent the 1 group of 3, and the "left over"  stays inside the root -- 

: there are 3 groups of 3 in 9 with none leftover. So,  goes outside to represent the 3 groups of 3, and there is nothing left inside -- 

: there are 4 groups of 3 in 14 with 2 left over. So,  goes outside to represent the 4 groups of 3, and the "left over"  stays inside the root -- 

Combining like terms: 

Use the distributive property to simplify the expression. The distributive property states that to multiply a sum by a term, you first multiply each part of the sum by that term separately, and then add these terms together. It looks like this in practice:

This means we multiply -6x² by both terms, and then add these together. Don't forget, the negative sign gets applied to each term within the sum.

Multiply the constant terms together, and the x's together to yield:

This expression is now simplified!