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Algebra 1 : Linear Equations

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10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #441 : Algebra 1

Solve for .

8.3x=11.57

Possible Answers:

0.8

1.8

2.3

1.1

1.3

Correct answer:

1.3

Explanation:

8.3x=11.57 Divide 8.3 on both sides.

x=1.3

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Example Question #442 : Algebra 1

Solve for .

-7.6x=12.16

Possible Answers:

1.6

1.1

2.1

-1.6

-1.1

Correct answer:

-1.6

Explanation:

-7.6x=12.16 Divide -7.6 on both sides. When dividing with a positive number, answer is negative.

x=-1.6

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Example Question #443 : Algebra 1

Solve for .

-9.9x=-227.7

Possible Answers:

-23.3

Correct answer:

Explanation:

-9.9x=-227.7 Divide -9.9 on both sides. When dividing with another negative number, answer is positive.

x=23

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Example Question #442 : How To Solve One Step Equations

Solve for .

$\frac{x}{5.6}=19$

Possible Answers:

108.4

107.4

98.4

106.4

102.4

Correct answer:

106.4

Explanation:

$\frac{x}{5.6}=19$ Multiply 5.6 on both sides.

x=106.4

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Example Question #445 : Algebra 1

Solve for .

$\frac{x}{-25}=71.2$

Possible Answers:

Correct answer:

Explanation:

$\frac{x}{-25}=71.2$ Multiply on both sides. When multiplying with a positive number, answer is negative.

x=-1780

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Example Question #446 : Algebra 1

Solve for .

$\frac{x}{-4.7}=-19.2$

Possible Answers:

88.84

76.92

90.24

-88.24

-90.24

Correct answer:

90.24

Explanation:

$\frac{x}{-4.7}=-19.2$ Multiply -4.7 on both sides. When multiplying with another negative number, answer is positive.

x=90.24

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Example Question #447 : Algebra 1

Solve the equation: $6x= \frac{3}{7}$

Possible Answers:

$\frac{1}{14}$

$\frac{9}{7}$

$\frac{7}{18}$

$\frac{18}{7}$

Correct answer:

$\frac{1}{14}$

Explanation:

In order to solve this equation, divide by six on both sides. This is the same as multiplying one-sixth on both sides.

$6x \cdot \frac{1}{6}= \frac{3}{7}\cdot \frac{1}{6}$

Simplify both sides.

$x=\frac{3}{42} = \frac{1}{14}$

The asnwer is: $\frac{1}{14}$

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Example Question #448 : Algebra 1

Solve the equation: $9x=\frac{3}{2}$

Possible Answers:

$\frac{1}{15}$

$\frac{1}{18}$

$\frac{1}{12}$

$\frac{1}{6}$

$\frac{1}{3}$

Correct answer:

$\frac{1}{6}$

Explanation:

In order to isolate the x-variable, multiply by the reciprocal of the coefficient of the x -variable on both sides of the equation.

$9x \times \frac{1}{9}=\frac{3}{2} \times \frac{1}{9}$

Simplify the fractions.

$x=\frac{3}{18} = \frac{1}{6}$

The answer is: $\frac{1}{6}$

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Example Question #442 : Algebra 1

Solve the equation: $6x=\frac{5}{6}$

Possible Answers:

$\frac{5}{36}$

$-5\frac{1}{5}$

$\frac{5}{12}$

$\frac{1}{5}$

Correct answer:

$\frac{5}{36}$

Explanation:

To isolate the x-variable, we can divide by six or multiply by one-sixth on both sides.

$6x \cdot \frac{1}{6}=\frac{5}{6} \cdot \frac{1}{6}$

Simplify both sides of the equation.

The answer is: $x=\frac{5}{36}$

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Example Question #450 : Algebra 1

Solve the equation: $-3x = \frac{4}{7}$

Possible Answers:

$\frac{4}{21}$

$-\frac{2}{5}$

$\frac{2}{5}$

$-\frac{12}{7}$

$-\frac{4}{21}$

Correct answer:

$-\frac{4}{21}$

Explanation:

Multiply both sides by negative one-third in order to isolate the unknown variable.

$-3x \cdot -\frac{1}{3}= \frac{4}{7} \cdot -\frac{1}{3}$

Simplify both sides.

$x= -\frac{4}{21}$

The answer is: $-\frac{4}{21}$

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Algebra 1 : Linear Equations

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #441 : Algebra 1

Example Question #442 : Algebra 1

Example Question #443 : Algebra 1

Example Question #442 : How To Solve One Step Equations

Example Question #445 : Algebra 1

Example Question #446 : Algebra 1

Example Question #447 : Algebra 1

Example Question #448 : Algebra 1

Example Question #442 : Algebra 1

Example Question #450 : Algebra 1

All Algebra 1 Resources

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