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Algebra 1 : How to use FOIL in the distributive property

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Example Questions

Example Question #11 : How To Use Foil In The Distributive Property

Expand (x+5)(2x-1) :

Possible Answers:

$2x^{2}+9x-5$

$x^{2}+9x-5$

$2x^{2}+4x-5$

$2x^{2}-5x+9$

$x^{2}+4x-5$

Correct answer:

$2x^{2}+9x-5$

Explanation:

To expand (x+5)(2x-1) , you must use the FOIL method to multiply the two expressions distributively. Utilizing the FOIL method gives you (x)(2x)+(x)(-1)+(5)(2x)+(5)(-1) or $2x^{2}+9x-5$ .

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Example Question #11 : How To Use Foil In The Distributive Property

Use FOIL to simplify the expression (4x-3)(x+8)-2 .

Possible Answers:

$4x^{2}+29x-26$

$4x^{2}+29x-22$

x-22

$4x^{2}-11x+26$

$-8x^{2}+58x-48$

Correct answer:

$4x^{2}+29x-26$

Explanation:

FOIL stands for "First, Outside, Inside, Last" and represents a quick way to multiply binomials.

We start with the "first" terms of the expression (4x-3)(x+8) and multiply them together, yielding $4x^{2}$ .

Multiplying the "outside" terms gives us 32x

and the inside gives us -3x .

Finally, multiplying the "last" terms yields (-3)(8) , or .

Simple addition of these terms gives us the expression $4x^{2}+29x-24$ , and subtracting 2 gives us our final answer.

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Example Question #13 : Distributive Property

Expand:

(2x-3)(3x+4)

Possible Answers:

$6x^{2}-x+12$

$x^{2}-x-12$

$6x^{2}-17x-12$

$6x^{2}+17x-12$

$6x^{2}-x-12$

Correct answer:

$6x^{2}-x-12$

Explanation:

To expand (2x-3)(3x+4) , you can use the FOIL method to multiply each term individually. This will give you (2x*3x)+(2x*4)+(-3*3x)+(-3*4) , or $6x^{2}-x-12$ .

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Example Question #14 : Distributive Property

Use the FOIL method to evaluate (6y+5)(y-7) .

Possible Answers:

$6y^{2}-47y-35$

$y^{2}+30y-37$

$6y^{2}-37y-35$

$6y^{2}+5y+7$

Correct answer:

$6y^{2}-37y-35$

Explanation:

FOIL (First, Outside, Inside, Last) refers to a method used to multiply binomials. As the name indicates, our first step is to multiply the first terms of each binomial together. This gives us (6y)(y) , or $6y^{^{2}}$ . Next, we multiply the "outside" terms together, yielding (6y)(-7) or (-42y) , and do the same for the "inside" terms, which yield . Finally, the product of the last terms in each binomial is (5)(-7) , which equals (-35) . Our next step is adding these values together to get $6y^{2}-42y+5y-35$ . So, our final answer is $6y^{2}-37y-35$ .

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Example Question #4821 : Algebra 1

Multiply (x-3)(x+7)

Possible Answers:

$x^{2}+4x-21$

$x^{2}-4x-21$

$x^{2}+4x+21$

$x^{2}-4x+21$

Correct answer:

$x^{2}+4x-21$

Explanation:

Using the FOIL method:

$(x-3)(x+7)=x^{2}+7x-3x-21=x^{2}+4x-21$

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Example Question #16 : Distributive Property

Use the FOIL method to simplify

(2x+4)(x-5)

Possible Answers:

$2x^{2}+10x-20$

$x^{2}-3x-10$

$2x^{2}-6x-20$

$2x^{2}+4x-20$

Correct answer:

$2x^{2}-6x-20$

Explanation:

(2x+4)(x-5)

FIRST: $2x\cdot x=2x^{2}$

OUTER: $2x\cdot-5= -10x$

INNER: $4\cdot x =4x$

LAST: $4\cdot -5 = -20$

Simplify (combinding like terms): $2x^{2}-10x+4x-20$

Answer: $2x^{2}-6x-20$

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Example Question #17 : Distributive Property

Evaluate using FOIL

$(ab+a^{2})(a+b)$

Possible Answers:

$2a^{6}b^{3}$

$2a^{2}b+ab^{2}+a^{3}$

$a^{2}b+ab^{2}+a^{3}$

$2a^{2}b+2ab^{2}+a^{3}$

Correct answer:

$2a^{2}b+ab^{2}+a^{3}$

Explanation:

$(ab+a^{2})(a+b)$

First: $ab\cdot a= a^{2}b$

Outer: $ab\cdot b = ab^{2}$

Inner: $a^{2}\cdot a = a^{3}$

Last: $a^{2}\cdot b = a^{2}b$

Simplify (combind like terms): $a^{2}b+ab^{2}+a^{3}+a^{2}b$

Answer: $2a^{2}b+ab^{2}+a^{3}$

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Example Question #12 : How To Use Foil In The Distributive Property

Factor the polynomial.

$\small x^2+7x-8$

Possible Answers:

$\small (x-4)(x+2)$

$\small (x+4)(x-2)$

$\small (x+8)(x-1)$

$\small (x-8)(x+1)$

Correct answer:

$\small (x+8)(x-1)$

Explanation:

$\small x^2+7x-8$

We need to factor to find terms that multiply to $\small -8$ and add to $\small 7$ .

$-1*8=-8\ \text{and}\ -1+8=7$

Now we can write our factored expression.

$\small x^2+7x-8=(x-1)(x+8)$

We can check our answer using FOIL.

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Example Question #13 : How To Use Foil In The Distributive Property

Expand:

(3x-1)(2x+3)

Possible Answers:

$6x^{2}+11x-3$

$5x^{2}+11x-3$

$6x^{2}+7x-3$

5x+2

$5x^{2}+7x-3$

Correct answer:

$6x^{2}+7x-3$

Explanation:

To multiply (3x-1)(2x+3) , you can use the FOIL method. Using the FOIL method, you must multiply each of the terms individually: (3x)(2x)+(-1)(2x)+(3x)(3)+(-1)(3) . This gives you the end result of $6x^{2}+7x-3$ .

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Example Question #4834 : Algebra 1

Multiply the following binomials.

$(x^{2} - 2)(x+3)$

Possible Answers:

$x^{3} - 3x^{2} - 2x +6$

$x^{2} + x -6$

$x^{3} + 3x^{2} - 2x -6$

$x^{3} - 3x^{2} + 2x -6$

$x^{3} + x -6$

Correct answer:

$x^{3} + 3x^{2} - 2x -6$

Explanation:

Use the FOIL method.

$(x^{2} - 2)(x+3)$

First: x^2*x=x^3

Inside: -2*x=-2x

Ouside: x^2*3=3x^2

Last: -2*3=-6

Sum the terms. No terms can be combined in this example.

x^3+3x^2-2x-6

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Algebra 1 : How to use FOIL in the distributive property

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #11 : How To Use Foil In The Distributive Property

Example Question #11 : How To Use Foil In The Distributive Property

Example Question #13 : Distributive Property

Example Question #14 : Distributive Property

Example Question #4821 : Algebra 1

Example Question #16 : Distributive Property

Example Question #17 : Distributive Property

Example Question #12 : How To Use Foil In The Distributive Property

Example Question #13 : How To Use Foil In The Distributive Property

Example Question #4834 : Algebra 1

All Algebra 1 Resources

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