All Algebra 1 Resources
Example Questions
Example Question #132 : Equations Of Lines
Find the equation of the line with slope 1/3 running through the point (15,2).
To solve this problem, we need to remember point-slope formula:
Then we plug in m=1/3 and (x1,y1)=(15,2) and solve:
Example Question #43 : How To Find The Equation Of A Line
Find the equation of the line with slope 4 running through the point (-1,-5).
To solve this problem, we need to remember point-slope formula:
Then we plug in m=4 and (x1,y1)=(-1,-5) and solve:
Example Question #133 : Equations Of Lines
Find the equation of the line with slope -3 running through the point (2,5).
To solve this problem, we need to remember point-slope formula:
Then we plug in m=2 and (x1,y1)=(4,6) and solve:
Example Question #134 : Equations Of Lines
Find the equation of the line with slope -1 running through the point (2,-2).
To solve this problem, we need to remember point-slope formula:
Then we plug in m=-1 and (x1,y1)=(2,-2) and solve:
Example Question #45 : Slope And Line Equations
Find the equation of the line with slope 1/2 running through the point (-8,2).
To solve this problem, we need to remember point-slope formula:
Then we plug in m=1/2 and (x1,y1)=(-8,2) and solve:
Example Question #141 : Equations Of Lines
Find the equation of the line with slope -2 running through the point (1,3).
To solve this problem, we need to remember point-slope formula:
Then we plug in m=-2 and (x1,y1)=(1,3) and solve:
Example Question #47 : Slope And Line Equations
Find the equation of the line with the slope 1/4 running through the point (2,2).
To solve this problem, we need to remember point-slope formula:
Then we plug in m=1/4 and (x1,y1)=(2,2) and solve:
Example Question #51 : How To Find The Equation Of A Line
A line has a y-intercept of and a slope of . Find the equation of this line.
Not enough information
This problem may seem slightly confusing with how the information is given. It's important to pay attention to what is being asked of us: to find the equation of a line.
All we're provided with is the y-intercept and the slope of the line. This is enough information. Normally the point-slope formula is used when in need of finding the equation of a line, but we don't have enough information for that route. In this problem it's helpful to remember the general skeleton of a linear equation:
, where is the slope and is the y-intercept.
Merely substituting in the provided information will yield us the answer.
because the slope is and the y-int is .
Example Question #52 : How To Find The Equation Of A Line
A line passes through the the point with a slope of . Find the equation for this line.
This kind of a problem can be easily solved for by using the point-slope formula because they've provided us with a slope and a point (coordinate).
where is slope and and refer to the point provided.
With the point-slope formula, the equation of the line may be simply solved for via substituting in the known information. The resulting answer will be in the form.
Example Question #53 : How To Find The Equation Of A Line
A line passes through the points and , Find the equation for this line.
The only information provided in this problem is the two points the specified line passes through. Although it may seem like not enough information, but this is enough to solve for the equation of the line through the point-slope formula:
where is slope and and refers to either one of the given points.
We can see that we have fulfilled the requirement for a point, but are still missing the slope. The slope can be attained using the two given points.
The slope of a line is a measure of the rate of change of the incline of a line. Slope is more commonly taught as "rise over run", and may be solved for by using the following formula:
, where m denotes slope. Rise denotes change in the y-axis where run denotes change in the x-axis. This makes sense because rise indicates a vertical change while run indicates a horizontal change.
Upon arbitrarily assigning the points as and , we can substitute the given information and solve for slope.
Now we have both requirements for the point-slope formula and can solve for the equation of the line.
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