All Algebra 1 Resources
Example Questions
Example Question #181 : Equations / Inequalities
Billy is several years older than Johnny. Billy is one less than twice as old as Johnny, and their ages multiplied together make ninety-one. When will Billy be 1.5 times Johnny's age?
When Johnny is 12 and Billy is 18
When Johnny is 4 and Billy is 6
When Johnny is 2 and Billy is 3
When Johnny is 7 and Billy is 13
When Johnny is 14 and Billy is 21
When Johnny is 12 and Billy is 18
1) Before we can figure out when Billy will be 1.5 times Johnny's age, we have to figure out their current ages. So let's define our variables in terms of the first part of the question.
B = Billy's age and J = Johnny's age
It's easier to solve if we put one variable in terms of the other. If Billy were just twice as old as Johnny, we could write his age as B = 2J.
But Billy is one less than twice as old as Johnny, so B = 2J – 1
2) We know that the two boys' ages multiply together to make ninety-one.
B * J = J(2J – 1) = 91
3) Now we have our factored quadratic. We just need to multiply it out and set everything equal to zero to begin.
4) Now we need to factor back out. We start by multiplying the first coefficient by the final term and listing off the factors.
2 * –91 = –182
1 + –182 = –181
2 + –91 = –89
7 + –26 = –19
13 + –14 = –1
5) Split up the middle term in so that factoring by grouping is possible.
6) Factor by grouping, pulling out "2J" from the first set of terms and "13" from the second.
7) Factor out the "(J-7)" from both terms.
8) Set both parentheses equal to zero and solve.
2J + 13 = 0, J = –13/2
J – 7 = 0, J = 7
Clearly, only of the two solutions works, since Johnny's age has to be positive. Johnny is 7, therefore Billy is 2(7) – 1=13. But we're not done yet!
9) We need to figure out at what point Billy will 1.5 times Johnny's age. Guess and check would be a fairly efficient way to do this problem, but setting up an equation would be even faster. First, though, we need to figure out what our variable is. We know Billy's and Johnny's current ages; we just need to figure out their future ages. One variable is always better than two, so instead of using two different variables to represent their respective future ages, we'll use one variable to represent the number of years we have to add to each of their current ages in order to make Billy 1.5 times older than Johnny. Let's call that variable "x."
1.5(J + x) = B + x
We know the values of J and B, so we can go ahead and fill those in.
1.5(7 + x) = 13 + x
10) Then we solve for x algebraically, with inverse order of operations.
10.5 + 1.5x = 13 + x
0.5x = 2.5
x = 5
J = 7 + 5 = 12
B = 13 + 5 = 18
Example Question #182 : Equations / Inequalities
Find all of the solutions to the following quadratic equation:
None of the above
This requires the use of the quadratic formula. Recall that:
for .
For this problem, .
So,
.
.
Therefore, the two solutions are:
Example Question #183 : Equations / Inequalities
Solve for .
No solution
Write the equation in standard form by first eliminating parentheses, then moving all terms to the left of the equal sign.
First:
Inside:
Outside:
Last:
Now factor, set each binomial to zero, and solve individually. We are lookig for two numbers with sum and product ; these numbers are .
and
or
The solution set is .
Example Question #184 : Equations / Inequalities
Solve for :
Eliminate parentheses, then write this quadratic equation in standard form, with all nonzero terms on one side:
Now factor the quadratic expression using the -method - split the middle term into two terms whose coefficients add up to 11 and have product . These numbers are
Set each factor to 0:
Example Question #185 : Equations / Inequalities
Example Question #186 : Equations / Inequalities
Example Question #187 : Equations / Inequalities
Example Question #188 : Equations / Inequalities
Example Question #189 : Equations / Inequalities
Example Question #190 : Equations / Inequalities
Solve for .
Solve by factoring. We need to find two factors that multiply to eight and add to six.
One of these factors must equal zero in order for the equation to be true.
Certified Tutor