We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

Create An Account

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #886 : Functions And Lines

Find the midpoint of a line segment with the endpoints $\small (-3,-12)$ and $\small (27,-30)$ .

Possible Answers:

$\small (-15,9)$

$\small (15,-9)$

$\small (-12,-21)$

$\small (16,10)$

$\small (12,-21)$

Correct answer:

$\small (12,-21)$

Explanation:

This kind of problem can be quickly solved for by using the midpoint formula:

$\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$ where $\small (x_1,y_1)$ and $\small (x_2,y_2)$ . Either of the endpoints may be assigned as either coordinate point.

Substituting in the information,

$\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\left(\frac{-3+27}{2}, \frac{-30-12}{2}\right)$

$\left(\frac{24}{2}, \frac{-42}{2}\right)$

${\color{Blue} (12,-21)}$

Report an Error

Example Question #9 : Midpoint Formula

What is the midpoint of a line that connects the points (1,5) and (-7,9) ?

Possible Answers:

(-3,7)

(-3,2)

(-4,7)

(-4,-2)

(4,2)

Correct answer:

(-3,7)

Explanation:

The midpoint formula is $\left(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2}\right)$ .

Therefore, all we need to do is plug in the points given to us to find the midpoint.

In this case, $x_{1}=1,x_{2}=-7,y_{1}=5,y_{2}=9$ .

To find the -value for the midpoint, we add: 1+(-7)=1-7=-6 . Then we divide by : -6/2=-3 .

To find the -value for the midpoint, we add: 5+9=14 . Then we divide by : 14/2=7 .

So our solution is (-3,7) .

Report an Error

Example Question #887 : Functions And Lines

Find the midpoint of the line segment with the endpoints of (-2, 3) and (4, 1)

Possible Answers:

(2, 1)

(-1, -2)

(1, 2)

(-8, 3)

(2, 4)

Correct answer:

(1, 2)

Explanation:

To find the midpoint of a line segment, take the two endpoints and use the following formula:

$\(\frac{x_{1} + x_{2}}{2},\frac{y_{1} +y_{2}}{2})$

Using this formula, we know

$(x_{1}, y_{1}) \text{ and } (x_{2}, y_{2})$

is the same as

$(-2, 3) \text{ and } (4,1)$

Using substitution, we get

$\(\frac{-2+4}{2},\frac{3+1}{2})$

$( \frac{2}{2}, \frac{4}{2})$

(1, 2)

Therefore, the midpoint of the line segment formed by the endpoints $(-2, 3) \text{ and } (4,1)$ is (1, 2) .

Report an Error

Example Question #888 : Functions And Lines

Find the midpoint of the line segment with the following endpoints: $(0,1)\&(2,7)$ .

Possible Answers:

(1,3)

(1,4)

(4,1)

(3,1)

(3,7)

Correct answer:

(1,4)

Explanation:

To find the midpoint of this segment, we plug the values of our respective coordinates into the midpoint formula:

$\left(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2}\right)$

$\left(\frac{0+2}{2},\frac{7+1}{2}\right)$

Simplify.

(1,4)

Report an Error

Example Question #889 : Functions And Lines

Find the point located exactly halfway between the points and

Possible Answers:

(3,27)

(27,3)

(-3,-27)

(-27,-3)

Correct answer:

(27,3)

Explanation:

Find the point located exactly halfway between the points and

We can find the midpoint of any pair of points via the following:

$M=(\frac{x_2-x_1}{2},\frac{y_2-y_1}{2})$

All we need to do is plug in our given points.

We'll call point 2 and point 1

So,

$M=(\frac{63-9}{2},\frac{43-37}{2})=(\frac{54}{2},\frac{6}{2})=(27,3)$

Report an Error

Example Question #891 : Functions And Lines

Two points, (1,2) and (2,5) , are connected to form a line. What is the midpoint?

Possible Answers:

$(\frac{3}{2},\frac{7}{2})$

$(\frac{3}{2},3)$

$(\frac{1}{2},\frac{3}{2})$

$(\frac{1}{2},\frac{7}{2})$

$(\frac{3}{2},4)$

Correct answer:

$(\frac{3}{2},\frac{7}{2})$

Explanation:

Write the midpoint formula. The midpoint is the center of the line segment.

$\textup{Midpoint} = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Substitute the values of the coordinates.

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) = (\frac{1+2}{2},\frac{2+5}{2})=(\frac{3}{2},\frac{7}{2})$

The midpoint is: $(\frac{3}{2},\frac{7}{2})$

Report an Error

Example Question #4171 : Algebra 1

Find the midpoint of the line segment formed by the points

(-1, -3) and (3, 3).

Possible Answers:

(2, 2)

(-4, -6)

(1, -1)

(1, 0)

(2, 0)

Correct answer:

(1, 0)

Explanation:

To find the midpoint between two points, we use the following formula:

$(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

where (x_1, y_1) and (x_2, y_2) are the points given. So, given the points

(-1, -3) and (3, 3), we can substitute into the formula.

$(\frac{-1 + 3}{2}, \frac{-3 + 3}{2})$

$(\frac{2}{2}, \frac{0}{2})$

(1, 0)

Therefore, the midpoint between (-1, -3) and (3, 3) is (1, 0).

Report an Error

Example Question #893 : Functions And Lines

Find the midpoint of a line segment with the following endpoints:

(2,6)(12,12)

Possible Answers:

(14,18)

(7,9)

(12,6)

(6,8)

Correct answer:

(7,9)

Explanation:

Finding the midpoint of a line segment only requires that we find the midpoint, or average of both the x and y components. In order to do that, we use the following formula:

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

For the points (2,6) and (12,12) plug in the numbers and solve:

$(\frac{2+12}{2},\frac{6+12}{2})=(\frac{14}{2},\frac{18}{2})=(7,9)$

This gives a final answer of (7,9)

Report an Error

Example Question #894 : Functions And Lines

Find the midpoint of the line segment with the following endpoints:

(-2,5)(4,7)

Possible Answers:

(6,1)

(1,6)

(3,5)

(8,9)

Correct answer:

(1,6)

Explanation:

Finding the midpoint of a line segment only requires that we find the midpoint, or average of both the x and y components. In order to do that, we use the following formula:

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

For the points (-2,5) and (4,7) plug in the numbers and solve:

$(\frac{-2+4}{2},\frac{5+7}{2})=(\frac{2}{2},\frac{12}{2})=(1,6)$

This gives a final answer of (1,6)

Report an Error

Example Question #895 : Functions And Lines

Find the midpoint of the line segment with the following endpoints:

(15,5)(3,5)

Possible Answers:

(6,5)

(9,5)

(9,0)

(12,5)

Correct answer:

(9,5)

Explanation:

Finding the midpoint of a line segment only requires that we find the midpoint, or average of both the x and y components. In order to do that, we use the following formula:

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

For the points (15,5) and (3,5) plug in the numbers and solve:

$(\frac{15+3}{2},\frac{5+5}{2})=(\frac{18}{2},\frac{10}{2})=(9,5)$

This gives a final answer of (9,5)

Report an Error

View Algebra Tutors

Timothy
Certified Tutor

University of Michigan-Dearborn, Bachelor of Science, Applied Mathematics.

View Algebra Tutors

Zabian
Certified Tutor

Mercer University, Bachelor of Science, Mathematics and Computer Science.

View Algebra Tutors

Blossom
Certified Tutor

University of Maryland-Baltimore County, Bachelor of Science, Computer Science.

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Algebra Tutors in Los Angeles, English Tutors in Houston, ACT Tutors in Washington DC, ACT Tutors in Boston, Statistics Tutors in Atlanta, ISEE Tutors in New York City, ISEE Tutors in Seattle, Computer Science Tutors in Dallas Fort Worth, LSAT Tutors in Chicago, Chemistry Tutors in Los Angeles

Popular Courses & Classes

SSAT Courses & Classes in Miami, ISEE Courses & Classes in Seattle, LSAT Courses & Classes in Boston, GRE Courses & Classes in San Francisco-Bay Area, GRE Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in Boston, SAT Courses & Classes in Washington DC, ACT Courses & Classes in San Diego, ACT Courses & Classes in Los Angeles, GMAT Courses & Classes in Phoenix

Popular Test Prep

GRE Test Prep in Philadelphia, LSAT Test Prep in Philadelphia, GRE Test Prep in Dallas Fort Worth, MCAT Test Prep in Miami, GMAT Test Prep in Boston, ACT Test Prep in San Diego, ISEE Test Prep in Boston, SSAT Test Prep in Phoenix, SAT Test Prep in San Diego, SAT Test Prep in Washington DC

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #886 : Functions And Lines

Example Question #9 : Midpoint Formula

Example Question #887 : Functions And Lines

Example Question #888 : Functions And Lines

Example Question #889 : Functions And Lines

Example Question #891 : Functions And Lines

Example Question #4171 : Algebra 1

Example Question #893 : Functions And Lines

Example Question #894 : Functions And Lines

Example Question #895 : Functions And Lines

All Algebra 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: