All Algebra 1 Resources
Example Questions
Example Question #321 : Equations / Inequalities
Give the solution to the system of equations below.
No solution
Solve the second equation for , allowing us to solve using the substitution method.
Substitute for in the first equation, and solve for .
Now, substitute for in either equation; we will choose the second. This allows us to solve for .
Now we can write the solution in the notation , or .
Example Question #201 : Grade 8
Solve this system of equations for :
None of the other choices are correct.
Multiply the bottom equation by , then add to the top equation:
Divide both sides by
Example Question #11 : Solve Systems Of Two Linear Equations: Ccss.Math.Content.8.Ee.C.8b
Solve the following system of equations:
no solution
infinitely many solutions
When we add the two equations, the variables cancel leaving us with:
Solving for we get:
We can then substitute our value for into one of the original equations and solve for :
Example Question #52 : How To Find The Solution For A System Of Equations
Solve the following system of equations.
We are given
We can solve this by using the substitution method. Notice that you can plug from the first equation into the second equation and then get
Add to both sides
Add 9 to both sides
Divide both sides by 5
So . We can use this value to find y by using either equation. In this case, I'll use .
So the solution is
Example Question #6 : Equations Based On Word Problems
Adult tickets to the zoo sell for ; child tickets sell for . On a given day, the zoo sold tickets and raised in admissions. How many adult tickets were sold?
Let be the number of adult tickets sold. Then the number of child tickets sold is .
The amount of money raised from adult tickets is ; the amount of money raised from child tickets is . The sum of these money amounts is , so the amount of money raised can be defined by the following equation:
To find the number of adult tickets sold, solve for :
adult tickets were sold.
Example Question #471 : New Sat
Solve the following story problem:
Jack and Aaron go to the sporting goods store. Jack buys a glove for and wiffle bats for each. Jack has left over. Aaron spends all his money on hats for each and jerseys. Aaron started with more than Jack. How much does one jersey cost?
Let's call "" the cost of one jersey (this is the value we want to find)
Let's call the amount of money Jack starts with ""
Let's call the amount of money Aaron starts with ""
We know Jack buys a glove for and bats for each, and then has left over after. Thus:
simplifying, so Jack started with
We know Aaron buys hats for each and jerseys (unknown cost "") and spends all his money.
The last important piece of information from the problem is Aaron starts with dollars more than Jack. So:
From before we know:
Plugging in:
so Aaron started with
Finally we plug into our original equation for A and solve for x:
Thus one jersey costs
Example Question #202 : Systems Of Equations
Solve for only:
Use the elimination process to determine the value of .
Subtract the second equation with the first equation. This will eliminate the x-variable in order to find the y-variable.
The equation becomes:
Use this value and substitute into either the first or second equation and solve for the x-variable.
Let's select the first equation and solve for .
Add six on both sides.
The result will be the same if we substitute into the second equation.
The answer is:
Example Question #56 : How To Find The Solution For A System Of Equations
Solve only for given the two equations:
In order to solve for , multiply the first equation by four in order to eliminate the fractions in front of the coefficients.
The first equation becomes:
The second equation remains the same:
Subtract the second equation with the first equation:
The result is:
Divide by two on both sides.
Simplify both sides.
The answer is:
Example Question #322 : Equations / Inequalities
Solve for only:
In order to solve for the variable, we will need to use the elimination method.
Subtract the first equation with the second equation in order to eliminate the variable to solve for .
After subtracting equation one with equation two:
Use this value and either equation to solve for . Let's choose the first equation.
Subtract twelve from both sides.
Simplify both sides.
The answer is:
Example Question #53 : How To Find The Solution For A System Of Equations
Read, but do not solve, the following problem:
Adult tickets to the zoo sell for $11; child tickets sell for $7. One day, 6,035 tickets were sold, resulting in $50,713 being raised. How many adult and child tickets were sold?
If and stand for the number of adult and child tickets, respectively, which of the following systems of equations can be used to answer this question?
6,035 total tickets were sold, and the total number of tickets is the sum of the adult and child tickets, .
Therefore, we can say .
The amount of money raised from adult tickets is $11 per ticket mutiplied by tickets, or dollars; similarly, dollars are raised from child tickets. Add these together to get the total amount of money raised:
These two equations form our system of equations.