Call Now to Set Up Tutoring:

(888) 888-0446

Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

Create An Account

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #2181 : Algebra 1

Solve for :

x+5>3x-3

Possible Answers:

x<2

x<1

x>4

x<4

x>1

Correct answer:

x<4

Explanation:

Subtracting and adding 3 to both sides of the equation of x+5>3x-3 will give you 8>2x . Divide both sides by 2 to get x<4 .

Report an Error

Example Question #52 : Equations / Inequalities

Which value of is in the solution set of the inequality 2x+2>-x+17 ?

Possible Answers:

Correct answer:

Explanation:

Add and subtract 2 from both sides of 2x+2>-x+17 to get 3x>15 . Then, divide both sides by 3 to get a solution of x>5 . The only answer choice that is greater than 5 is 6.

Report an Error

Example Question #53 : Equations / Inequalities

Find the solution set for :

$3.2 \geq -x + 0.6 > -5.1$

Possible Answers:

[-2.6, 5.7)

(-5.7, -2.6]

[-5.7, -2.6)

(-5.7, 2.6]

[2.6, 5.7)

Correct answer:

[-2.6, 5.7)

Explanation:

$3.2 \geq -x + 0.6 > -5.1$

$3.2- 0.6 \geq -x + 0.6 - 0.6 > -5.1 - 0.6$

$2.6 \geq -x > -5.7$

$2.6 \cdot (-1 )\leq -x \cdot (-1 )< -5.7 \cdot (-1 )$

Note the switch in inequality symbols when the numbers are multiplied by a negative number.

$-2.6 \leq x < 5.7$

or, in interval notation, [-2.6, 5.7)

Report an Error

Example Question #2181 : Algebra 1

Solve the inequality:

3+x-5<2

Possible Answers:

No solution

x<4

x<-6

x<10

x<0

Correct answer:

x<4

Explanation:

Combine like-terms on the left side of the inequality: x-2<2 . Next, isolate the variable: $x-2 \boldsymbol{+2} <2 \boldsymbol{+2}$ .

Therefore the answer is x<4 .

Report an Error

Example Question #2182 : Algebra 1

Solve:

$\small x+2\geq 7$

Possible Answers:

$\small x\geq 5$

$\small x< 9$

$\small x> 5$

None of the other answers are correct.

$\small x\leq 9$

Correct answer:

$\small x\geq 5$

Explanation:

Subtract 2 from each side:

$\small x+2-2\geq 7-2$

$\small x\geq 5$

Report an Error

Example Question #2183 : Algebra 1

Solve for :

2x-4 >7

Possible Answers:

x>11

x>5.5

x>22

x>3.5

x>1.5

Correct answer:

x>5.5

Explanation:

This inequality can be solved just like an equation.

Add 4 to both sides:

2x > 11

Then divide by 2:

x > 11/2 = 5.5

Report an Error

Example Question #2186 : Algebra 1

Solve the inequality:

$\small 15x - 4 \le 2x + 8 +x$

Possible Answers:

$\small x \le \frac{11}{14}$

$\small x \le \frac{4}{5}$

$\small x \le \frac{6}{7}$

$\small x \le1$

$\small x \le 0$

Correct answer:

$\small x \le1$

Explanation:

First, combine like terms on a single side of the inequality. On the right side of the inequality, combine the terms to obtain $\small 15x - 4 \le 3x +8$ .

Next, we want to get all the variables on the left side of the inequality and all of the constants on the right side of the inequality. Add 4 to both sides and subtract from both sides to get $\small 12x \le 12$ .

Finally, to isolate the variable, divide both sides by 12 to produce the final answer, $\small x \le1$ .

Report an Error

Example Question #5 : How To Find The Solution To An Inequality With Addition

Solve: x-3<50

Possible Answers:

x<53

x<47

$x\leq 53$

x> 53

$x\leq 47$

Correct answer:

x<53

Explanation:

To solve x-3<50 , isolate the variable by adding three on both sides.

x-3+(3)<50+(3)

The correct answer is: x<53

Report an Error

Example Question #57 : Equations / Inequalities

Solve the following inequality:

4x-7<2x+3

Possible Answers:

x>2

x<5

$x\leq2$

x>5

x<7

Correct answer:

x<5

Explanation:

To solve the inequality, get all terms with on one side and all constants on the other side. We first subtract from both sides

2x-7<3 ,

Now add 7 to both sides

2x<10 .

Now divide both sides by 2

x<5

Report an Error

Example Question #61 : Equations / Inequalities

Solve this inequality:

$12x-5\geq-4x+43$

Possible Answers:

$x\geq6$

$x\geq2$

$x\geq3$

$x\geq4$

Not enough information to be determined.

Correct answer:

$x\geq3$

Explanation:

To solve this inequality, we need to separate the constants from the variables so that they are on opposite sides of the inequality.

We can do this by adding (4x+5) to each side and

$12x-5+(4x+5)\geq-4x+43 + (4x+5)$ .

The constants cancel on the left side, and the variables cancel on the right side.

$16x+0\geq0x+48$

$16x\geq48$

Then, we divide both sides by 16, to get our final answer:

$\frac{16x}{16}\geq\frac{48}{16}$

$x\geq 3$

Report an Error

View Algebra Tutors

James
Certified Tutor

Purdue University-Main Campus, Doctor of Education, Mathematics Teacher Education.

View Algebra Tutors

Nicholas
Certified Tutor

Salem State University, Bachelor of Science, GIS Technology.

View Algebra Tutors

Sophia
Certified Tutor

University of Virginia, Charlottesville, Bachelor, Biochemistry and Sociology.

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

English Tutors in Dallas Fort Worth, Reading Tutors in Denver, GRE Tutors in New York City, Algebra Tutors in Houston, Chemistry Tutors in San Francisco-Bay Area, Algebra Tutors in Miami, Spanish Tutors in Seattle, Math Tutors in Boston, Computer Science Tutors in Denver, Statistics Tutors in Atlanta

Popular Courses & Classes

GRE Courses & Classes in Washington DC, Spanish Courses & Classes in Dallas Fort Worth, GMAT Courses & Classes in Denver, Spanish Courses & Classes in Atlanta, SSAT Courses & Classes in Chicago, MCAT Courses & Classes in Philadelphia, Spanish Courses & Classes in Seattle, SAT Courses & Classes in Washington DC, LSAT Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in Los Angeles

Popular Test Prep

GRE Test Prep in Houston, SAT Test Prep in Boston, LSAT Test Prep in Miami, GMAT Test Prep in Denver, SAT Test Prep in Houston, ACT Test Prep in Dallas Fort Worth, LSAT Test Prep in Seattle, SSAT Test Prep in New York City, SAT Test Prep in San Francisco-Bay Area, SAT Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #2181 : Algebra 1

Example Question #52 : Equations / Inequalities

Example Question #53 : Equations / Inequalities

Example Question #2181 : Algebra 1

Example Question #2182 : Algebra 1

Example Question #2183 : Algebra 1

Example Question #2186 : Algebra 1

Example Question #5 : How To Find The Solution To An Inequality With Addition

Example Question #57 : Equations / Inequalities

Example Question #61 : Equations / Inequalities

All Algebra 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: