Let \(\displaystyle x\) be the number of hours Veronica must work.

Since we know that she is paid \(\displaystyle \$120\) per hour, we can write the following equation:

\(\displaystyle 120x=1920\)

To solve for \(\displaystyle x\), divide both sides by \(\displaystyle 120\).

\(\displaystyle 120x\div120=1920\div120\)

\(\displaystyle x=16\)

Veronica needs to work for \(\displaystyle 16\) hours to earn \(\displaystyle \$1920\).

Let \(\displaystyle x\) be the amount Jimmy had before buying groceries.

Since we know that he spent \(\displaystyle \$45.10\) on groceries, we can write the following equation:

\(\displaystyle x-45.10=3.66\)

To solve for \(\displaystyle x\), add \(\displaystyle 45.10\) to both sides of the equation.

\(\displaystyle x-45.10+45.10=3.66+45.10\)

\(\displaystyle x=48.76\)

Jimmy had \(\displaystyle \$48.76\) before buying groceries.

To solve for \(\displaystyle x\), you will need to get \(\displaystyle x\) on its own. To do so, divide both sides by \(\displaystyle 3\).

\(\displaystyle 3x=-9\) 

\(\displaystyle \frac{3x}{3}=\frac{-9}{3}\)

\(\displaystyle x=-3\)

To solve for \(\displaystyle x\), you will need to get \(\displaystyle x\) on its own. To do so, divide both sides by \(\displaystyle 2\).

\(\displaystyle 4x=\frac{1}{2}\) 

\(\displaystyle 4x\div4=\frac{1}{2}\div4=\frac{1}{2}\times\frac{1}{4}\)

\(\displaystyle x=\frac{1}{8}\)

To solve for \(\displaystyle x\), you will need to get \(\displaystyle x\) on its own. To do so, divide both sides by \(\displaystyle -5\).

\(\displaystyle -5x=\frac{1}{3}\) 

\(\displaystyle -5x\div -5=\frac{1}{3}\div -5=\frac{1}{3}\times-\frac{1}{5}\)

\(\displaystyle x=-\frac{1}{15}\)

Let \(\displaystyle x\) be the number of hours Michael spends practicing.

We know from the question that Catherine spends \(\displaystyle 4\) more hours practicing. We can then write the following expression to show the number of hours Catherine spends practicing in terms of \(\displaystyle x\):

\(\displaystyle x+4\)

Since we also know that Catherine spent \(\displaystyle 15\) hours practicing, we can then write the following equation:

\(\displaystyle x+4=15\)

To solve for \(\displaystyle x\), subtract \(\displaystyle 4\) from both sides.

\(\displaystyle x+4-4=15-4\)

\(\displaystyle x=11\)

Michael spent \(\displaystyle 11\) hours practicing basketball.

In order to solve for \(\displaystyle x\), subtract \(\displaystyle 9\) from both sides of the equation.

\(\displaystyle x+9=8\)

\(\displaystyle x+9-9=8-9\)

\(\displaystyle x=-1\)

In order to solve for \(\displaystyle y\), you will need to add \(\displaystyle 6\) to both sides of the equation.

\(\displaystyle y-6=9\)

\(\displaystyle y-6+6=9+6\)

\(\displaystyle y=15\)

In order to solve for \(\displaystyle y\), you will need to add \(\displaystyle \frac{1}{2}\) to both sides of the equation.

\(\displaystyle y-\frac{1}{2}=-2\)

\(\displaystyle y-\frac{1}{2}+\frac{1}{2}=-2+\frac{1}{2}\)

\(\displaystyle y=-\frac{4}{2}+\frac{1}{2}\)

\(\displaystyle y=-\frac{3}{2}\)

In order to solve for \(\displaystyle y\), add \(\displaystyle 0.8\) to both sides of the equation.

\(\displaystyle y-0.8=1\)

\(\displaystyle y-0.8+0.8=1+0.8\)

\(\displaystyle y=1.8\)