All Advanced Geometry Resources
Example Questions
Example Question #41 : How To Graph A Function
True or false: The graph of has as a horizontal asymptote the graph of the equation .
True
False
True
is a rational function whose denominator polynomial has degree greater than that of its numerator polynomial (2 and 1, respectively). The graph of such a function has as its horizontal asymptote the line of the equation .
Example Question #161 : Coordinate Geometry
Give the -coordinate of the -intercept of the graph of the function
The graph of has no -intercept.
The -intercept of the graph of is the point at which it intersects the -axis. Its -coordinate is 0; its -coordinate is , which can be found by substituting 0 for in the definition:
,
the correct choice.
Example Question #162 : Coordinate Geometry
True or false: The graph of has as a horizontal asymptote the graph of the equation .
True
False
False
is a rational function whose denominator polynomial has degree greater than that of its numerator polynomial (2 and 1, respectively). The graph of such a function has as its horizontal asymptote the line of the equation .
Example Question #163 : Graphing
Give the -coordinate of the -intercept of the graph of the function
.
The graph of has no -intercept.
The graph of has no -intercept.
The -intercept of the graph of is the point at which it intersects the -axis. Its -coordinate is 0; its -coordinate is , which can be found by substituting 0 for in the definition:
An expression with 0 in the denominator is undefined, so the graph of has no -intercept.
Example Question #164 : Graphing
True or false: The graph of has as a vertical asymptote the graph of the equation .
False
True
True
The vertical asymptote(s) of the graph of a rational function such as can be found by evaluating the zeroes of the denominator after the rational expression is reduced.
First, factor the numerator. It is a quadratic trinomial with lead term , so look to factor
by using the grouping technique. We try finding two integers whose sum is and whose product is ; with some trial and error we find that these are and , so, breaking the linear term:
Regroup:
Factor the GCF twice:
Therefore, can be rewritten as
Cancelling in both halves of the equation:
Set the denominator equal to 0 and solve for :
The graph of therefore has one vertical asymptotes - the line of the equation .
Example Question #163 : Graphing
Give the domain of the function
The set of all real numbers
As a rational function, has as its domain the set of all values for which the denominator is not equal to 0. Solve the equation
First, factor the quadratic trinomial as
by finding two integers with sum and product 25. From trial and error, we find the integers 5 and 5, so the equation can be rewritten as
,
or
By the Square Root Property,
and
.
Therefore, the only value excluded from the domain of is , making the domain .
Example Question #163 : Coordinate Geometry
Give the -coordinate of the -intercept of the graph of the function
The graph of has no -intercept.
The -intercept of the graph of is the point at which it intersects the -axis. Its -coordinate is 0; its -coordinate is , which can be found by substituting 0 for in the definition:
,
the correct response.
Example Question #167 : Graphing
Give the -coordinate(s) of the -intercept(s) of the graph of the function
The graph of has no -intercept.
The -intercept(s) of the graph of are the point(s) at which it intersects the -axis. The -coordinate of each is 0; their -coordinate(s) are those value(s) of for which , so set up, and solve for , the equation:
Add to both sides:
Multiply both sides by 2:
,
the correct choice.
Example Question #165 : Graphing
True or false: The graph of has as a vertical asymptote the graph of the equation .
True
False
False
The vertical asymptote(s) of the graph of a rational function such as can be found by evaluating the zeroes of the denominator after the rational expression is reduced.
First, factor the numerator. It is a quadratic trinomial with lead term , so look to factor
by using the grouping technique. We try finding two integers whose sum is and whose product is ; with some trial and error we find that these are and , so:
Break the linear term:
Regroup:
Factor the GCF twice:
Therefore, can be rewritten as
Cancel the common factor from both halves; the function can be rewritten as
Set the denominator equal to 0 and solve for :
The graph of therefore has one vertical asymptotes, the line of the equations . The line of the equation is not a vertical asymptote.
Example Question #166 : Graphing
Give the -coordinate of the -intercept of the graph of the function
.
The graph of has no -intercept.
The -intercept of the graph of is the point at which it intersects the -axis. Its -coordinate is 0; its -coordinate is , which can be found by substituting 0 for in the definition:
,
the correct choice.