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ACT Math : How to divide complex fractions

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Example Questions

Example Question #1 : Complex Fractions

Which of the following is equal to $\frac{\left(7+\frac{1}{x}\right)}{\left(14+\frac{2}{x}\right)}$ ?

Possible Answers:

$\frac{x}{2}$

x^2+14x+2

$\frac{1}{2}$

$\frac{7x}{2}$

$\frac{1}{2x}$

Correct answer:

$\frac{1}{2}$

Explanation:

First we must take the numerator of our whole problem. There is a fraction in the numerator with as the denominator. Therefore, we multiply the numerator of our whole problem by $\frac{x}{x}$ , giving us $7+\frac{1}{x}=7x+1$ .

Now we look at the denominator of the whole problem, and we see that there is another fraction present with as a denominator. So now, we multiply the denominator by $\frac{x}{x}$ , giving us $14+\frac{2}{x}=14x+2$ .

Our fraction should now read $\frac{(7x+1)}{(14x+2)}$ . Now, we can factor our denominator, making the fraction $\frac{(7x+1)}{(2(7x+1))}$ .

Finally, we cancel out 7x+1 from the top and the bottom, giving us $\frac{1}{2}$ .

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Example Question #2 : Complex Fractions

Simplify: $\frac{3}{\frac{3}{2}}$

Possible Answers:

$\frac{3}{2}$

$\frac{9}{2}$

$\frac{3}{2}$

Correct answer:

Explanation:

Rewrite $\frac{3}{\frac{3}{2}}$ into the following form:

$3\div \frac{3}{2}$

Change the division sign to a multiplication sign by flipping the 2nd term and simplify.

$3\cdot \frac{2}{3}=2$

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Example Question #1 : How To Divide Complex Fractions

Evaluate: $\frac{\frac{1}{x}}{x^2}$

Possible Answers:

$\frac{1}{2x^2}$

$\frac{1}{x+x^2}$

$\frac{1}{x}$

$\frac{1}{x^3}$

Correct answer:

$\frac{1}{x^3}$

Explanation:

The expression $\frac{\frac{1}{x}}{x^2}$ can be rewritten as:

$\frac{1}{x}\div{x^2}$

Change the division sign to a multiplication sign and take the reciprocal of the second term. Evaluate.

$\frac{1}{x}\cdot\frac{1}{x^2}=\frac{1}{x^3}$

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Example Question #2 : Complex Fractions

Simplify: $\frac{\frac{1}{6}}{3} + \frac{\frac{1}{3}}{6}$

Possible Answers:

$\frac{1}{9}$

$\frac{1}{4}$

$\frac{2}{9}$

$\frac{5}{2}$

Correct answer:

$\frac{1}{9}$

Explanation:

The expression $\frac{\frac{1}{6}}{3} + \frac{\frac{1}{3}}{6}$ can be simplified as follows:

We can simplify each fraction by multiplying the numerator by the reciprocal of the denominator.

$\frac{1}{6}\div3 \rightarrow \frac{1}{6}\cdot \frac{1}{3}=\frac{1}{9}$

$\frac{1}{3}\div 6 \rightarrow \frac{1}{3}\cdot \frac{1}{6}=\frac{1}{9}$

From here we add our two new fractions together and simplify.

$=\frac{1}{18}+\frac{1}{18}=\frac{2}{18}=\frac{1}{9}$

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Example Question #1 : How To Divide Complex Fractions

Simplify the following:

$\frac{7+\frac{1}{3}}{\frac{3}{5}}$

Possible Answers:

$\frac{13}{7}$

$\frac{7}{10}$

$\frac{110}{9}$

$\frac{28}{5}$

$\frac{25}{4}$

Correct answer:

$\frac{110}{9}$

Explanation:

Begin by simplifying your numerator. Thus, find the common denominator:

$\frac{\frac{21}{3}+\frac{1}{3}}{\frac{3}{5}}$

Next, combine the fractions in the numerator:

$\frac{\frac{22}{3}}{\frac{3}{5}}$

Next, remember that to divide fractions, you multiply the numerator by the reciprocal of the denominator:

$\frac{22}{3}\times \frac{5}{3}$

Since nothing needs to be simplified, this is just:

$\frac{22}{3}\times \frac{5}{3}=\frac{110}{9}$

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ACT Math : How to divide complex fractions

Study concepts, example questions & explanations for ACT Math

All ACT Math Resources

Example Questions

Example Question #1 : Complex Fractions

Example Question #2 : Complex Fractions

Example Question #1 : How To Divide Complex Fractions

Example Question #2 : Complex Fractions

Example Question #1 : How To Divide Complex Fractions

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