ACT Math : Algebra

Study concepts, example questions & explanations for ACT Math

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Example Questions

Example Question #52 : Variables

Simplify:

Possible Answers:

Correct answer:

Explanation:

In order to begin this kind of a problem, it's key to look at parts of the rational expression that can be simplified.

In this case, the denominator is an already-simplified binomial; however, the numerator can be factored through "factoring by grouping." This can be a helpful idea to keep in mind when you come across a polynomial with four terms and simplifying is involved.

 can be simplified first by removing the common factor of  from the first two terms and the common factor of  from the last two terms:

This leaves two terms that are identical  and their coefficients, which can be combined into another term to complete the factoring:

Consider the denominator; the quantity  appears, so the  in the numerator and in the denominator can be cancelled out. The simplified expression is then left as .

Example Question #641 : Algebra

Simplify:

Possible Answers:

Correct answer:

Explanation:

In order to begin this kind of a problem, it's key to look at parts of the rational expression that can be simplified. 

In this case, the denominator is an already-simplified binomial; however, the numerator can be factored. 

The roots will be numbers that sum up to  but have the product of .

The options include:




When these options are summed up:




We can negate the last three options because the first option of  and  fulfill the requirements. Therefore, the numerator can be factored into the following:

Because the quantity  appears in the denominator, this can be "canceled out." This leaves the final answer to be the quantity .

Example Question #641 : Algebra

Solve for x when 6x – 4 = 2x + 5

 

Possible Answers:

0

3

1/4

9/4

Correct answer:

9/4

Explanation:

Solve by simplifying:

         6x – 4 = 2x + 5

         6x = 2x + 9

         4x = 9

         x = 9/4

 

 

Example Question #11 : Binomials

What is the value of the following equation if  and ?

\small 2t^2+4vt+2v^2

Possible Answers:

Correct answer:

Explanation:

Substitute the numbers 3 and –4 for t and v, respectively.

\small 2(3)^2+4(-4)(3)+2(-4)^2

\small 18+(-48)+32=2

Example Question #3 : How To Simplify Binomials

Simplify the following binomial:

Possible Answers:

Correct answer:

Explanation:

The equation that is presented is:

To get the correct answer, you first need to combine all of the like terms. So, you can subtract the  from the , leaving you with:

From there, you can reduce the numbers by their greatest common denominator, in this case, :

Then you have arrived at your final answer.

Example Question #2 : How To Simplify Binomials

Simplify the following binomial expression:

Possible Answers:

Correct answer:

Explanation:

First, combine all of the like terms that you are able:

Then, reduce by the greatest common denominator (in this case, ):

Example Question #54 : Variables

Simplify the following binomial:

Possible Answers:

Correct answer:

Explanation:

The equation presented in the problem is:

First you have to combine the like terms, i.e. combining all instances of  and :

Then, you can factor out the common  to get your answer

 

Example Question #1 : Binomials And Foil

Which of the following expressions is equivalent to: 6x (m2 +yx2 3)?

 

Possible Answers:

6xm2 + 6yx2 -18x

6xm2 + 6yx3 -18

6xm2 + 6yx3 -18x

6xm2 + 7x3 -18

xm2 + 7x3 -18

Correct answer:

6xm2 + 6yx3 -18x

Explanation:

6x (m2 +yx2 3)= 6x∙m2 + 6xyx2 – 6x∙3= 6xm2 + 6yx3 -18x (Use Distributive Property)

 

 

Example Question #642 : Algebra

Which of the following expressions is equivalent to: ?

Possible Answers:

Correct answer:

Explanation:

Use the distributive property to multiply  by all of the terms in :

Example Question #1 : Binomials And Foil

If  and  are constants and  is equivalent to , what is the value of ?

Possible Answers:

Cannot be determined from the given information.

Correct answer:

Explanation:

The question gives us a quadratic expression and its factored form. From this, we know 

At this point, solve for t.

Now, we can plug in  to get

.

Now, use FOIL to get s.

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