1. Factor the numerator:

2. Factor the denominator:

3. Divide the factored numerator by the factored denominator:

You can cancel out the  from both the numerator and the denominator, leaving you with:

In order to divide these polynomials, you need to first factor them.

and

Now, the expression becomes 

so,

The leading term of the numerator is one exponent higher than the leading term of the denominator. Thus, we know the result of the division is going to be somewhere close to . We can separate the fraction out like this: 

The first term is easily seen to be , which is equal to . The second term can also be written out as:

and combining these, we get our final answer,

Expand:

Step 1: Use the distributive property

Step 2: Combine like terms

The question provides two positive whole numbers that are each multiples of 6 and also 6 numbers apart. This may be translated into variables, where the first number may be represented by "x" and the second number may be represented as "x+6" given that it is 6 numbers greater than x. 

The problem provides the information that the product of these two numbers is 72. Using the new definitions for the numbers, this may be represented as:

(x)(x+6) = 72

This provides an equation that multiplies two polynomials (one with one term, which is a monomial and one with two terms, which is a binomial) and an ability to solve for what x (the first of the two numbers) may be.

Using FOIL, the result is . This may be rewritten as , which will provide the value of x after factoring. 

, where (-6)(12) will provide the product of -72 and the sum of 12 and -6 will yield 6. The results indicate x as having two possible solutions: x=6 and x=-12. Returning back to the question, the goal is to find two positive numbers. This means that x=-12 is not a viable solution and that x=6 is. Now, revisiting the terms used to redefine the two numbers [x and x+6], x has been calculated. After substituting in the x value for the second term, the second number is 12 (6+6=12). 

The final step of the problem is to solve for the sum of these two numbers:
6+12=18

The proper way to multiply polynomials is to essentially apply the distributive property continually.

So  is really the same as , and so on.

Then, simply group together like terms to get the final answer:

When subtracting polynomials, it's helpful to remember that the "minus sign" gets distributed. It's as if the two polynomials are being added and a -1 is in front of the second polynomial.

This -1 will get multiplied to all the terms in the second polynomial that is being subtracted from the first, so it becomes . You may note that by multiplying by -1, every term in the polynomial switches its original sign. The problem then becomes:

From here, in order to simplify, because there's no equal sign, it can be deduced that we are not working toward a solution for x. The original problem is presented as an expression so an expression as an answer will be expected. In order to work towards a final simplified expression, like terms must be collected. This will provide the final answer.

Begin by distributing the subtraction of the second term in this question:

Now, you merely need to combine like terms:

To solve this equation, we substitute  in for every instance of  seen in the original equation .

Therefore the new equation would read 

Now we must square the expression . To do this, you must multiply the expression by itself. Therefore:

We must now plug in our new value for  into our original equation in place of .

Now we must distribute the  into . To do this, you multiply each expression within the parenthesis by :

Therefore, our answer is .

To answer this question, we must distribute the  to the rest of the variables , , and  that are within the brackets.

To distribute a variable or number, you multiply that value with every other value within the brackets or parentheses. So, for this data:

We then simplify the expression by combining the variables we are multiplying together into expressions. For this data:

Be sure to keep all of your operations the same within the problem itself, unless the number being distributed is negative, which will then switch the signs with the brackets from positive to negative or negative to positive. 

Therefore, our answer is .