ACT Math : Algebra

Study concepts, example questions & explanations for ACT Math

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Example Questions

Example Question #11 : How To Factor An Equation

A certain number squared, plus four times itself is equal to zero. 

Which of the following could be that number?

Possible Answers:

Correct answer:

Explanation:

The sentence should first be translated into an equation. 

We will call the "certain number" .

This gives us .

So solve this we can factor out an  to get .

This makes the zeros of the equation evident. We know that when  the entire expression will equal zero, making the equation true. We also know that when , the quantity  will be , which also satisfies the equation.

Therefore, the two possible solutions are  and .

Example Question #491 : Algebra

If , and , which of the following is a possible value of ?

Possible Answers:

-12

-4

-2

-6

-8

Correct answer:

-12

Explanation:

The given expression is a quadratic equation; therefore, we can factor the equation 

Use the format of the standard quadratic equation:

Since , we know that the quadratic's roots will resemble the following:

We also know that one of those signs has to be negative, since our two last terms multiply to equal the variable , and  is negative in our quadratic. Now, we need to find two numbers that when multiplied together equal -24, and equal 10 when they are added together. Let's start by finding the factors of 24. The factors of 24 are 24 and 1, 12 and 2, 8 and 3, 6 and 4. Since one of those factors will be negative in our factored equation, we need to find the two factors whose difference is 10.

This means that the numbers in the factored equation are 12 and -2; thus, we may write the following:

.

By the zero multiplication rule, either portion of that equation can equal 0 for the result to be 0; thus, we have the following two expressions:

 

Subtract 12 from both sides of the equation:

Calculate the value of the variable in the second equation.

Add 2 to both sides of the equation.

Since we want a negative answer for our variable, the correct answer is:

Example Question #1 : How To Find The Solution For A System Of Equations

What is the sum of the x, y, and z coordinates of the point that satisfies this system of equations:

 

2x + 3y + 4z = 20

x = y – z

–3x + 2y + 2z = 23

 

Possible Answers:

–6

4

0

–10

Correct answer:

4

Explanation:

Multiplying the second equation by 2 and subtracting it from the first gives the equation:

5y + 2z = 20

 

Multiplying the first equation by 3, multiplying the third equation by 2, and then adding those equations gives:

13y + 16z = 106

 

Now we have a system of two equations and two unknowns. 

Multiply the equation 5y + 2z = 20 by 8, and then subtract this from 13y + 16z = 106

 

This yields –27= –54, so y = 2. Then using the equation 5y + 2z = 20, z = 5. Then using any of the original three equations, x = –3.

 

The point of intersection is (-3, 2, 5), and the sum of these coordinates is 4.

 

 

Example Question #1 : Systems Of Equations

The cost of a movie ticket and a candy bar is $5. The cost of two tickets and a candy bar is $8.75. How much is a candy bar?

Possible Answers:

$2.50

$7.50

$3.75

$0.75

$1.25

Correct answer:

$1.25

Explanation:

We start by setting up a system of equations. The price of one ticket and one candy bar is $5, so t+c=5. The price of two tickets and one candy bar is $8.75, so 2t+c=8.75. We can use the first equation to find out that c=5-t. We then substitute that value into the second equation, giving us 2t+(5-t)=8.75. This simplifies to 2t-t+5=8.75, so t+5=8.75, and finally t=3.75. We use the final value for t in the first equation, so 3.75+c=5. We solve for c, and get c=1.25.

Example Question #2 : Systems Of Equations

Jacob is 3 years older than Sarah, and Caroline is twice as old as Sarah. If Caroline is 28 years old, how many years old is Jacob?

Possible Answers:
14
20
17
21
15
Correct answer: 17
Explanation:

One can describe the ages of Jacob, Sarah, and Caroline with the letters J, S, and C, respectively. From the information in the problem, J = S + 3, and C = 2S. Since C = 28, S = 28/2 = 14, and J = 14 + 3 = 17. Jacob is 17 years old.

Example Question #2 : Systems Of Equations

If ab = 24, a + b = 10, and a < b, what is the value of ab?

Possible Answers:

6

–2

–4

2

4

Correct answer:

–2

Explanation:

Solving the second equation for b and substituting b = 10 – a into the equation ab = 24 gives us

a(10 – a) = 10a – a2 = 24

which can be set up and solved as the following quadratic equation:

a1 – 10a +24 = 0

(a – 6) (a – 4) = 0

a = 6, a = 4

a must be 4 and b must be 6, since a < b; therefore, 4 – 6 = –2.

Example Question #5 : Systems Of Equations

Josh is counting his money.  He has only quarters and nickels.  He has two more quarters than nickels. He counts his money to discover he has $1.40.  How many total coins does he have?

Possible Answers:

None of the answers are correct

3

5

7

8

Correct answer:

8

Explanation:

The general formula for money problems is V1 x N1 + V2 x N2 = $Value where V is the value of the coin and N is the number of coins for each separate type of coin involved.  $Value is the total value of all the money when counted.  With this problem N = number of nickels and

Q = N + 2 is the number of quarters.  Substituting into the general formula we get

0.25(N + 2) + 0.05N = 1.40.  Solving for N yields N = 3, therefore Q = 5.  So the answer to the question is actually N + Q = 3 + 5 = 8 total coins.

Example Question #1 : Systems Of Equations

A business makes $5 million less the second year than the first year.  In the third year the business makes twice as much as in the second year.  If the business makes $15 million in the third year how much did it make in the first?

Possible Answers:

$15 milion 

$12.5 million

None of the other answers 

$5 million

$10 million

Correct answer:

$12.5 million

Explanation:

This problem is probably best solved by developing a series of equations.  To relate the second and third years we can set up the equation 15 = 2x where x is the amount of money made in the second year, which is two times less than the amount of money made in the third.  By dividing each side by two we see that the business made 7.5 million dollars in the second year.  To relate the first and second years we can set up the equation x – 5 = 7.5 where x is the amount of money made in the first year.  By adding 5 to both sides of the equation we are able to see that the business made 12.5 million dollars in the first year.  

Example Question #3 : Systems Of Equations

Timesheetact

If Sally makes $9.50 an hour, what was her gross pay for the week if she gets paid time-and-a-half for any hours above 40?

Possible Answers:

$451.25

$493.75

$355.50

$380.00

$564.25

Correct answer:

$451.25

Explanation:

Sally works 40 regular hours and 5 overtime hours. Her regular hourly pay becomes 40 * 9.50 = $380.00, and her overtime pay becomes 5 * 9.50 * 1.5 = $71.25, so her weekly gross (before taxes) pay is $451.25

Example Question #7 : Systems Of Equations

Sally sells cars for a living.  She has a monthly salary of $1,000 and a commission of $500 for each car sold.  How much money would she make if she sold seven cars in a month?

Possible Answers:

$4,500

$5,500

$3,500

$5,000

$4,000

Correct answer:

$4,500

Explanation:

The commission she gets for selling seven cars is $500 * 7 = $3,500 and added to the salary of $1,000 yields $4,500 for the month.

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