ACT Math : Algebra

Study concepts, example questions & explanations for ACT Math

varsity tutors app store varsity tutors android store varsity tutors amazon store varsity tutors ibooks store

Example Questions

Example Question #1 : How To Find The Slope Of Parallel Lines

What is the slope of a line parallel to the line defined by the equation:

Possible Answers:

Correct answer:

Explanation:

The slope of a line in slope-intercept form is given by the coefficient,  in the equation:

. For two lines to be parallel, they have to have the same slope. Thus we see in our equation that  and so a line that is parallel must also have a slope of 

Example Question #1 : How To Find The Slope Of Parallel Lines

Which of the following is the equation of a line parallel to the line .

Possible Answers:

Correct answer:

Explanation:

Parallel lines have equivalent slopes, so the correct answer is .

Example Question #41 : Lines

Which of the following lines is parallel to:

 

Possible Answers:

Correct answer:

Explanation:

First write the equation in slope intercept form. Add  to both sides to get . Now divide both sides by  to get . The slope of this line is , so any line that also has a slope of  would be parallel to it. The correct answer is  .

Example Question #29 : Coordinate Geometry

Which pair of linear equations represent parallel lines?

Possible Answers:

y=x+2

y=-x+2

y=2x+4

y=x+4

y=-x+4

y=x+6

y=x-5

y=3x+5

y=2x-4

y=2x+5

Correct answer:

y=2x-4

y=2x+5

Explanation:

Parallel lines will always have equal slopes. The slope can be found quickly by observing the equation in slope-intercept form and seeing which number falls in the "m" spot in the linear equation (y=mx+b)

We are looking for an answer choice in which both equations have the same m value. Both lines in the correct answer have a slope of 2, therefore they are parallel.

Example Question #30 : Coordinate Geometry

Which of the following equations represents a line that is parallel to the line represented by the equation ?

Possible Answers:

Correct answer:

Explanation:

Lines are parallel when their slopes are the same.

First, we need to place the given equation in the slope-intercept form.

Because the given line has the slope of , the line parallel to it must also have the same slope.

Example Question #1 : How To Find Out If Lines Are Parallel

Line  passes through the points  and . Line  passes through the point  and has a  of . Are the two lines parallel? If so, what is their slope? If not, what are their slopes?

Possible Answers:

No, the lines are not parallel. Line  has a slope of  and line  has slope .

Yes, the lines are parallel with a slope of .

No, the lines are not parallel. Line  has a slope of  and line  has a slope of .

Yes, the lines are parallel with a slope of .

Correct answer:

Yes, the lines are parallel with a slope of .

Explanation:

Finding slope for these two lines is as easy as applying the slope formula to the points each line contains. We know that line  contains points  and , so we can apply our slope formula directly (pay attention to negative signs!)

.

Line  contains point  and, since the y-intercept is always on the vertical axis, . Thus:

The two lines have the same slope, , and are thus identical.

Example Question #2 : How To Find Out If Lines Are Parallel

Line  is described by the equation . Line  passes through the points  and . Are the two lines parallel? If so, what is their slope? If not, what are their slopes?

Possible Answers:

No, the lines are not parallel. Line  has slope  and line  has slope .

Yes, the lines are parallel, and both lines have slope .

Yes, the lines are parallel, and both lines have slope .

No, the lines are not parallel. Line  has slope  and line  has slope .

Correct answer:

No, the lines are not parallel. Line  has slope  and line  has slope .

Explanation:

We are told at the beginning of this problem that line  is described by  . Since  is our slope-intecept form, we can see that  for this line. Since parallel lines have equal slopes, we must determine if line  has a slope of .

 Since we know that  passes through points  and , we can apply our slope formula:

 

Thus, the slope of line  is 1. As the two lines do not have equal slopes, the lines are not parallel.

Example Question #1 : How To Find The Equation Of A Perpendicular Line

What line is perpendicular to x + 3y = 6 and travels through point (1,5)?

Possible Answers:

y = 6x – 3

y = –1/3x – 4

y = 3x + 2

y = 2/3x + 6

y = 2x + 1

Correct answer:

y = 3x + 2

Explanation:

Convert the equation to slope intercept form to get y = –1/3x + 2.  The old slope is –1/3 and the new slope is 3.  Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

With the new slope, use the slope intercept form and the point to calculate the intercept: y = mx + b or 5 = 3(1) + b, so b = 2

So y = 3x + 2

Example Question #1 : How To Find The Equation Of A Perpendicular Line

What line is perpendicular to and passes through ?

Possible Answers:

Correct answer:

Explanation:

Convert the given equation to slope-intercept form.

The slope of this line is . The slope of the line perpendicular to this one will have a slope equal to the negative reciprocal.

The perpendicular slope is .

Plug the new slope and the given point into the slope-intercept form to find the y-intercept.

So the equation of the perpendicular line is .

Example Question #1 : How To Find The Equation Of A Perpendicular Line

What is the equation of a line that runs perpendicular to the line 2x + = 5 and passes through the point (2,7)?

Possible Answers:

2x + y = 7

2x – y = 6

x/2 – y = 6

x/2 + y = 5

x/2 + y = 6

Correct answer:

x/2 + y = 6

Explanation:

First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6. Rearranged, it is –x/2 + y = 6.

Learning Tools by Varsity Tutors