All ACT Math Resources
Example Questions
Example Question #1 : How To Graph A Line
What is the distance between (7, 13) and (1, 5)?
None of the answers are correct
12
10
7
5
10
The distance formula is given by d = square root [(x2 – x1)2 + (y2 – y1)2]. Let point 2 be (7,13) and point 1 be (1,5). Substitute the values and solve.
Example Question #1 : How To Graph A Line
What is the slope of this line?
The slope is found using the formula .
We know that the line contains the points (3,0) and (0,6). Using these points in the above equation allows us to calculate the slope.
Example Question #2 : How To Graph A Line
What is the amplitude of the function if the marks on the y-axis are 1 and -1, respectively?
0.5
3π
π
2π
1
1
The amplitude is half the measure from a trough to a peak.
Example Question #3 : How To Graph A Line
What is the midpoint between and ?
None of the answers are correct
The x-coordinate for the midpoint is given by taking the arithmetic average (mean) of the x-coordinates of the two end points. So the x-coordinate of the midpoint is given by
The same procedure is used for the y-coordinates. So the y-coordinate of the midpoint is given by
Thus the midpoint is given by the ordered pair
Example Question #4 : How To Graph A Line
If the graph has an equation of , what is the value of ?
is the -intercept and equals . can be solved for by substituting in the equation for , which yields
Example Question #2 : Graphing
The equation represents a line. This line does NOT pass through which of the four quadrants?
Cannot be determined
IV
II
I
III
III
Plug in for to find a point on the line:
Thus, is a point on the line.
Plug in for to find a second point on the line:
is another point on the line.
Now we know that the line passes through the points and .
A quick sketch of the two points reveals that the line passes through all but the third quadrant.
Example Question #2 : How To Graph A Line
Refer to the above red line. A line is drawn perpendicular to that line, and with the same -intercept. Give the equation of that line in slope-intercept form.
First, we need to find the slope of the above line.
The slope of a line. given two points can be calculated using the slope formula
Set :
The slope of a line perpendicular to it has as its slope the opposite of the reciprocal of 2, which would be . Since we want this line to have the same -intercept as the first line, which is the point , we can substitute and in the slope-intercept form:
Example Question #2 : How To Graph A Function
Refer to the above diagram. If the red line passes through the point , what is the value of ?
One way to answer this is to first find the equation of the line.
The slope of a line. given two points can be calculated using the slope formula
Set :
The line has slope 3 and -intercept , so we can substitute in the slope-intercept form:
Now substitute 4 for and for and solve for :
Example Question #1 : How To Graph A Quadratic Function
Best friends John and Elliot are throwing javelins. The height of John’s javelin is described as f(x) = -x2 +4x, and the height of Elliot’s javelin is described as f(x) = -2x2 +6x, where x is the horizontal distance from the origin of the thrown javelin. Whose javelin goes higher?
The javelins reach the same height
John’s
Elliot’s
Insufficient information provided
Elliot’s
When graphed, each equation is a parabola in the form of a quadratic. Quadratics have the form y = ax2 + bx + c, where –b/2a = axis of symmetry. The maximum height is the vertex of each quadratic. Find the axis of symmetry, and plug that x-value into the equation to obtain the vertex.
Example Question #2 : How To Graph A Quadratic Function
Where does the following equation intercept the x-axis?
and
only
and
and
and
and
To determine where an equation intercepts a given axis, input 0 for either (where it intercepts the -axis) or (where it intercepts the -axis), then solve. In this case, we want to know where the equation intercepts the -axis; so we will plug in 0 for , giving:
Now solve for .
Note that in its present form, this is a quadratic equation. In this scenario, we must find two factors of 12, that when added together, equal 7. Quickly, we see that 4 and 3 fit these conditions, giving:
Solving for , we see that there are two solutions,
or