All ACT Math Resources
Example Questions
Example Question #1 : How To Find A Missing Side With Sine
The above circle has a radius of and a center at . . Find the length of chord .
We can solve for the length of the chord by drawing a line the bisects the angle and the chord, shown below as .
In this circle, we can see the triangle has a hypotenuse equal to the radius of the circle (), an angle equal to half the angle made by the chord, and a side that is half the length of the chord. By using the sine function, we can solve for .
The length of the entire chord is twice the length of , so the entire chord length is .
Example Question #4 : How To Find A Missing Side With Sine
What is in the right triangle above? Round to the nearest hundredth.
Recall that the sine of an angle is the ratio of the opposite side to the hypotenuse of that triangle. Thus, for this triangle, we can say:
Solving for , we get:
or
Example Question #2 : How To Find A Missing Side With Sine
A man has set up a ground-level sensor to look from the ground to the top of a tall building. The sensor must have an angle of upward to the top of the building. How far is the sensor from the top of the building? Round to the nearest inch.
Begin by drawing out this scenario using a little right triangle:
Note importantly: We are looking for as the the distance to the top of the building. We know that the sine of an angle is equal to the ratio of the side opposite to that angle to the hypotenuse of the triangle. Thus, for our triangle, we know:
Using your calculator, solve for :
This is . Now, take the decimal portion in order to find the number of inches involved.
Thus, rounded, your answer is feet and inches.
Example Question #1 : How To Find A Missing Side With Sine
Below is right triangle with sides . What is ?
To find the sine of an angle, remember the mnemonic SOH-CAH-TOA.
This means that
.
We are asked to find the . So at point we see that side is opposite, and the hypotenuse never changes, so it is always . Thus we see that
Example Question #26 : Sine
In a given right triangle , hypotenuse and . Using the definition of , find the length of leg . Round all calculations to the nearest tenth.
In right triangles, SOHCAHTOA tells us that , and we know that and hypotenuse . Therefore, a simple substitution and some algebra gives us our answer.
Use a calculator or reference to approximate cosine.
Isolate the variable term.
Thus, .
Example Question #5 : How To Find A Missing Side With Sine
In a given right triangle , hypotenuse and . Using the definition of , find the length of leg . Round all calculations to the nearest tenth.
In right triangles, SOHCAHTOA tells us that , and we know that and hypotenuse . Therefore, a simple substitution and some algebra gives us our answer.
Use a calculator or reference to approximate cosine.
Isolate the variable term.
Thus, .
Example Question #81 : Trigonometry
In a given right triangle , hypotenuse and . Using the definition of , find the length of leg . Round all calculations to the nearest hundredth.
In right triangles, SOHCAHTOA tells us that , and we know that and hypotenuse . Therefore, a simple substitution and some algebra gives us our answer.
Isolate the variable term.
Thus, .
Example Question #1 : How To Find The Sine Of An Angle
What is the sine of ?
Sine can be found using the SOH CAH TOA method. For sine we do .
Example Question #2 : How To Find The Sine Of An Angle
See right triangle ABC. If the length AB is 8 and the length of BC is 6, what is the sine of angle A?
0.6
6
10
1
0.8
0.6
Sine A = Opposite / Hypotenuse = BC / AC
To find AC, use Pythagorean Theorum
AB2 + BC2 = AC2
82 + 62 = AC2
64 + 36 = AC2
100 = AC2
AC = 10
Sine A = BC / AC = 6 / 10 = 0.6
Example Question #3 : How To Find The Sine Of An Angle
Solve for over the interval
Q = 3π or does not exist 2
Q = π or does not exist 2
Q = π or 3π 2 2
Q = π or 2π
Q = 3π or does not exist 2
Substitute x = sinQ and solve the new equation x2 + 3x = –2 by factoring. Be sure to change variables back to Q. As a result, sinQ = –1 or sinQ = –2. This function is bounded between –1 and 1 so sinQ can never be –2 and sinQ is –1 only at 3π/2 or 270 °.
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