All SSAT Upper Level Math Resources
Example Questions
Example Question #2 : How To Find The Perimeter Of A Rectangle
Perimeter of a rectangle is 36 inches. If the width of the rectangle is 3 inches less than its length, give the length and width of the rectangle.
inches
inches
inches
inches
inches
inches
Let:
The perimeter of a rectangle is , where is the length and is the width of the rectangle. The perimeter is known so we can set up an equation in terms of and solve it:
So we can get:
inches
inches
Example Question #3 : How To Find The Perimeter Of A Rectangle
The length and width of a rectangle are and , respectively. Give its perimeter in terms of .
The perimeter of a rectangle is , where is the length and is the width of the rectangle. In order to find the perimeter we can substitute the and in the perimeter formula:
Example Question #801 : Geometry
The length of a rectangle is and the width of this rectangle is meters shorter than its length. Give its perimeter in terms of .
The length of the rectangle is known, so we can find the width in terms of :
The perimeter of a rectangle is , where is the length and is the width of the rectangle.
In order to find the perimeter we can substitute the and in the perimeter formula:
Example Question #5 : How To Find The Perimeter Of A Rectangle
A rectangle has a length of inches and a width of inches. Which of the following is true about the rectangle perimeter if ?
Its perimeter is less than 7 feet.
Its perimeter is between 7.2 and 7.4 feet.
Its perimeter is between 7 and 8 feet.
Its perimeter is between 8 and 9 feet.
Its perimeter is more than 8 feet.
Its perimeter is between 7 and 8 feet.
Substitute to get and :
The perimeter of a rectangle is , where is the length and is the width of the rectangle. So we have:
inches
Now we should divide the perimeter by 12 in order to convert to feet:
feet
So the perimeter is 7 feet and 6 inches, which is between 7 and 8 feet.
Example Question #801 : Geometry
Which of these polygons has the same perimeter as a rectangle with length 55 inches and width 15 inches?
A regular heptagon with sidelength two feet
The other answer choices are incorrect.
A regular octagon with sidelength two feet
A regular pentagon with sidelength two feet
A regular hexagon with sidelength two feet
The other answer choices are incorrect.
The perimeter of a rectangle is twice the sum of its length and its width; a rectangle with dimensions 55 inches and 15 inches has perimeter
inches.
All of the polygons in the choices are regular - that is, all have congruent sides - and all have sidelength two feet, or 24 inches, so we divide 140 by 24 to determine how many sides such a polygon would need to have a perimeter equal to the rectangle. However,
,
so there cannot be a regular polygon with these characteristics. All of the choices fail, so the correct response is that none are correct.
Example Question #1 : How To Find The Area Of A Rectangle
Mark wants to seed his lawn, which measures 225 feet by 245 feet. The grass seed he wants to use gets 400 square feet of coverage to the pound; a fifty-pound bag sells for $45.00, and a ten-pound bag sells for $13.00. What is the least amount of money Mark should expect to spend on grass seed?
The area of Mark's lawn is . The amount of grass seed he needs is pounds.
He has two options.
Option 1: he can buy three fifty-pound bags for
Option 2: he can buy two fifty-pound bags and four ten-pound bags for
The first option is the more economical.
Example Question #2 : How To Find The Area Of A Rectangle
The width and height of a rectangle are and , respectively. Give the area of the rectangle in terms of .
The area of a rectangle is given by multiplying the width times the height. As a formula:
Where:
is the width and is the height. So we can get:
Example Question #2 : How To Find The Area Of A Rectangle
The base length of a parallelogram is equal to the side length of a square. The base length of the parallelogram is two times longer than its corresponding altitude. Compare the area of the parallelogram with the area of the square.
The area of a parallelogram is given by:
Where is the base length and is the corresponding altitude. In this problem we have:
or
So the area of the parallelogram would be:
The area of a square is given by:
weher is the side length of a square. In this problem we have , so we can write:
Then:
or:
Example Question #3 : How To Find The Area Of A Rectangle
How many squares with the side length of 2 inches can be fitted in a rectangle with the width of 10 inches and height of 4 inches?
Solution 1:
We can divide the rectangle width and height by the square side length and multiply the results:
rectangle width square length =
rectangle heightsquare length =
Solution 2:
As the results of the division of rectangle width and height by the square length are integers and do not have a residual, we can say that the squares can be perfectly fitted in the rectangle. Now in order to find the number of squares we can divide the rectangle area by the square area:
Rectangle area = square inches
Square area = square inches
So we can get:
Example Question #802 : Geometry
A rectangle has the area of 80 square inches. The width of the rectangle is 2 inches longer that its height. Give the height of the rectangle.
The area of a rectangle is given by multiplying the width times the height. That means:
where:
width and height.
We know that: . Substitube the in the area formula:
Now we should solve the equation for :
The equation has two answers, one positive and one negative . As the length is always positive, the correct answer is inches.
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