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SSAT Upper Level Math : Geometry

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Example Questions

Example Question #391 : Ssat Upper Level Quantitative (Math)

A line segment on the coordinate plane has endpoints (a-5,-b) and (b+8, a-4) . In terms of and , as applicable, give the -coordinate of its midpoint.

Possible Answers:

a + b + 3

$\frac{a + b - 4}{2}$

a - b - 4

$\frac{a + b + 3}{2}$

$\frac{a - b - 4}{2}$

Correct answer:

$\frac{a - b - 4}{2}$

Explanation:

The -coordinate of the midpoint of a line segment is the mean of the -coordinates of its endpoints. Therefore, the -coordinate is

$y= \frac{(a-4)+(-b)}{2} = \frac{a-b-4}{2}$ .

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Example Question #2 : Midpoint Formula

A line segment has the endpoints (6,10) and (-2, -4) . What is the midpoint of the line?

Possible Answers:

(2, 3)

(4,7)

(8,14)

(4,6)

Correct answer:

(2, 3)

Explanation:

To find the midpoint of a line, take the averages of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=(\frac{6+(-2)}{2}, \frac{10+(-4)}{2})=(\frac{4}{2}, \frac{6}{2})=(2,3)$

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Example Question #1 : Midpoint Formula

What is the midpoint of a line segment with endpoints (12,2) and (-2, 1) ?

Possible Answers:

(14,1)

$(5, \frac{3}{2})$

(10, 3)

$(\frac{13}{2}, 0)$

Correct answer:

$(5, \frac{3}{2})$

Explanation:

To find the midpoint of a line, just take the average of the -coordinates and the average of the -coordinates.

$\text{Midpoint}=(\frac{12+(-2)}{2}, \frac{2+1}{2})=(\frac{10}{2}, \frac{3}{2})=(5, \frac{3}{2})$

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Example Question #113 : Coordinate Geometry

What is the midpoint of a line segments with endpoints (2a, -b) and (4a, 5b) ?

Possible Answers:

(6a, 4b)

(3a, 2b)

(-a, -2b)

(3, 4)

Correct answer:

(3a, 2b)

Explanation:

To find the midpoint of a line segment, take the average of the -coordinates, then take the average of the -coordinates.

$\text{Midpoint}=(\frac{2a+4a}{2}, \frac{-b+5b}{2})$

$\text{Midpoint}=(\frac{6a}{2}, \frac{4b}{2})=(3a, 2b)$

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Example Question #3 : Midpoint Formula

A line has the endpoints $(8,8) \text{ and }(2, -1)$ . What is its midpoint?

Possible Answers:

$\left(5, \frac{7}{2}\right)$

$\left(\frac{7}{2}, 5\right)$

(5, 7)

(10, 7)

Correct answer:

$\left(5, \frac{7}{2}\right)$

Explanation:

The coordinates of the midpoint of a line are just the averages of the coordinates of the endpoints.

$\text{Midpoint}=\left(\frac{8+2}{2}, \frac{8-1}{2}\right)=\left(5, \frac{7}{2}\right)$

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Example Question #4 : Midpoint Formula

A line segment has endpoints $(-2, 0) \text{ and }(1, 5)$ . What is the midpoint of this line segment?

Possible Answers:

$\left(-\frac{1}{2}, \frac{5}{2}\right)$

$\left(5, -\frac{1}{2}\right)$

$\left(-\frac{1}{2}, 5\right)$

(-1, 5)

Correct answer:

$\left(-\frac{1}{2}, \frac{5}{2}\right)$

Explanation:

To find the coordinates of the midpoint of a line, take the averages of the x and y coordinates of the endpoints.

$\text{Midpoint}=\left(\frac{-2+1}{2}, \frac{5+0}{2}\right)=\left(-\frac{1}{2}, \frac{5}{2}\right)$

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Example Question #8 : How To Find The Midpoint Of A Line Segment

What is the midpoint of a line if the endpoints of the line are: $(6,9) \textup{ and }(3,-2)$ ?

Possible Answers:

$\left(-\frac{3}{2},\frac{1}{2}\right)$

$\left(-\frac{3}{2},-\frac{11}{2}\right)$

$\left(\frac{9}{2},\frac{7}{2}\right)$

$\left(\frac{7}{2},\frac{9}{2}\right)$

$\left(\frac{3}{2},\frac{11}{2}\right)$

Correct answer:

$\left(\frac{9}{2},\frac{7}{2}\right)$

Explanation:

Write the midpoint formula.

$M=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)$

Substitute the values.

$M=\left(\frac{6+3}{2},\frac{9-2}{2}\right)= \left(\frac{9}{2},\frac{7}{2}\right)$

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Example Question #1 : How To Find The Endpoints Of A Line Segment

A line segment on the coordinate plane has midpoint $\left ( A + 5, B + 7\right )$ . One of its endpoints is $\left ( 10, 6 \right )$ . What is the -coordinate of the other endpoint, in terms of and/or ?

Possible Answers:

2B + 1

2B + 8

2B + 20

B + 8

B + 1

Correct answer:

2B + 8

Explanation:

Let be the -coordinate of the other endpoint. Since the -coordinate of the midpoint of the segment is the mean of those of the endpoints, we can set up an equation as follows:

$\frac{Y + 6 }{2} = B + 7$

$\frac{Y + 6 }{2} \cdot 2= \left ( B + 7 \right )\cdot 2$

Y + 6 = 2B + 14

Y + 6 -6 = 2B + 14 -6

Y = 2B + 8

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Example Question #171 : Geometry

A line segment on the coordinate plane has one endpoint at $\left ( 8, 10 \right )$ ; its midpoint is $\left ( A+B, A- B\right )$ . Which of the following gives the -coordinate of its other endpoint in terms of and ?

Possible Answers:

2 A + 2B- 8

A + B- 8

A + B- 16

A + B+8

2 A + 2B+8

Correct answer:

2 A + 2B- 8

Explanation:

To find the value of the -coordinate of the other endpoint, we will assign the variable . Then, since the -coordinate of the midpoint of the segment is the mean of those of its endpoints, the equation that we can set up is

$\frac{T + 8 }{2} = A + B$ .

We solve for :

$\frac{T + 8 }{2} \cdot 2 =\left ( A + B \right )\cdot 2$

T + 8 =2 A + 2B

T + 8 - 8 =2 A + 2B- 8

T =2 A + 2B- 8

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Example Question #121 : Coordinate Geometry

One endpoint of a line segment on the coordinate plane is the point $\left (2\frac{4}{5}, -1\frac{1}{5} \right )$ ; the midpoint of the segment is the point $\left (6\frac{1}{2}, 4\frac{1}{2} \right )$ . Give the -coordinate of the other endpoint of the segment.

Possible Answers:

$10\frac{1}{5}$

$4 \frac{3}{20}$

$-5\frac{1}{5}$

$9\frac{3}{10}$

$3\frac{7}{10}$

Correct answer:

$10\frac{1}{5}$

Explanation:

In the part of the midpoint formula

$x_{M}= \frac{x_{1} + x_{2} }{2}$ ,

set $x_{M}= 6\frac{1}{2}, x_{2}= 2\frac{4}{5}$ , and solve:

$x_{M}= \frac{x_{1} + x_{2} }{2}$

$6\frac{1}{2}= \frac{x_{1} + 2\frac{4}{5} }{2}$

$6\frac{1}{2} \cdot 2 = x_{1} + 2\frac{4}{5}$

$x_{1} + 2\frac{4}{5} = 13$

$x_{1} = 10\frac{1}{5}$

This is the correct -coordinate.

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All SSAT Upper Level Math Resources

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SSAT Upper Level Math : Geometry

Study concepts, example questions & explanations for SSAT Upper Level Math

All SSAT Upper Level Math Resources

Example Questions

Example Question #391 : Ssat Upper Level Quantitative (Math)

Example Question #2 : Midpoint Formula

Example Question #1 : Midpoint Formula

Example Question #113 : Coordinate Geometry

Example Question #3 : Midpoint Formula

Example Question #4 : Midpoint Formula

Example Question #8 : How To Find The Midpoint Of A Line Segment

Example Question #1 : How To Find The Endpoints Of A Line Segment

Example Question #171 : Geometry

Example Question #121 : Coordinate Geometry

All SSAT Upper Level Math Resources

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