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SSAT Middle Level Math : Numbers and Operations

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10 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #21 : Ratio And Proportion

Phil invites sixty friends from his current school, thirty-five of whom are girls, to his birthday party; he also invites his two female cousins. Phil wants the ratio of girls to boys at the party to be two to one, so he decides to also invite some girls from his old school. How many new girls will he need to invite, assuming he does not invite anyone else?

Possible Answers:

Correct answer:

Explanation:

So far, there are 37 girls - 35 classmates and 2 cousins - and 26 boys - 25 classmates and Mike himself. For the ratio of girls to boys to be 2 to 1, the number of girls must be twice the number of boys, or $26 \times 2 = 52$ girls. Mike will need 52-37 = 15 more girls.

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Example Question #1 : Ratios & Proportional Relationships

Write as a unit rate: 330 revolutions in minutes

Possible Answers:

revolutions per minute

Correct answer:

revolutions per minute

Explanation:

Divide the number of revolutions by the number of minutes to get revolutions per minute:

$330\div 15 = 22$ ,

making revolutions per minute the correct choice.

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Example Question #1 : Ratios & Proportional Relationships

If candidate A receives vote for every votes that candidate B receives. At the end of the election candidate B has 320 votes. How many votes did candidate A get?

Possible Answers:

960

320

$106\tfrac{2}{3}$

Correct answer:

$106\tfrac{2}{3}$

Explanation:

In order to solve this problem we need to create a ratio with the given information. It says that for every vote cast for candidate A, candidate B got votes. We can write the following ratio.

$A:B\rightarrow\frac{A}{B}$

Now substitute in the given numbers.

$1:3\rightarrow \frac{1}{3}$

We know that candidate B received 320 votes. Write a new ratio.

$A:320\rightarrow\frac{A}{320}$

Now, use the original relationship to create a proportion and solve for the number of votes that candidate A received.

$\frac{1}{3}=\frac{A}{320}$

Cross multiply and solve for .

3(A)=320(1)

Simplify.

3A=320

Divide both sides of the equation by .

$\frac{3A}{3}=\frac{320}{3}$

Solve.

$A=106\tfrac{2}{3}$

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Example Question #1 : Ratios & Proportional Relationships

If candidate A receives votes for every votes that candidate B receives. At the end of the election candidate B has 320 votes. How many votes did candidate A get?

Possible Answers:

132

160

155

128

282

Correct answer:

128

Explanation:

In order to solve this problem we need to create a ratio with the given information. It says that for every votes cast for candidate A, candidate B got votes. We can write the following ratio.

$A:B\rightarrow\frac{A}{B}$

Now substitute in the given numbers.

$2:5\rightarrow \frac{2}{5}$

We know that candidate B received 320 votes. Write a new ratio.

$A:320\rightarrow\frac{A}{320}$

Now, use the original relationship to create a proportion and solve for the number of votes that candidate A received.

$\frac{2}{5}=\frac{A}{320}$

Cross multiply and solve for .

5(A)=320(2)

Simplify.

5A=640

Divide both sides of the equation by .

$\frac{5A}{5}=\frac{640}{5}$

Solve.

A=128

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Example Question #1 : Ratios & Proportional Relationships

If candidate A receives vote for every votes that candidate B receives. At the end of the election candidate B has 320 votes. How many votes did candidate A get?

Possible Answers:

335

410

Correct answer:

Explanation:

In order to solve this problem we need to create a ratio with the given information. It says that for every vote cast for candidate A, candidate B got votes. We can write the following ratio.

$A:B\rightarrow\frac{A}{B}$

Now substitute in the given numbers.

$1:5\rightarrow \frac{1}{5}$

We know that candidate B received 320 votes. Write a new ratio.

$A:320\rightarrow\frac{A}{320}$

Now, use the original relationship to create a proportion and solve for the number of votes that candidate A received.

$\frac{1}{5}=\frac{A}{320}$

Cross multiply and solve for .

5(A)=320(1)

Simplify.

5A=320

Divide both sides of the equation by .

$\frac{5A}{5}=\frac{320}{5}$

Solve.

A=64

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Example Question #684 : Ssat Middle Level Quantitative (Math)

If candidate A receives votes for every votes that candidate B receives. At the end of the election candidate B has 300 votes. How many votes did candidate A get?

Possible Answers:

180

190

100

Correct answer:

180

Explanation:

In order to solve this problem we need to create a ratio with the given information. It says that for every votes cast for candidate A, candidate B got votes. We can write the following ratio.

$A:B\rightarrow\frac{A}{B}$

Now substitute in the given numbers.

$3:5\rightarrow \frac{3}{5}$

We know that candidate B received 300 votes. Write a new ratio.

$A:300\rightarrow\frac{A}{300}$

Now, use the original relationship to create a proportion and solve for the number of votes that candidate A received.

$\frac{3}{5}=\frac{A}{300}$

Cross multiply and solve for .

5(A)=300(3)

Simplify.

5A=900

Divide both sides of the equation by .

$\frac{5A}{5}=\frac{900}{5}$

Solve.

A=180

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Example Question #685 : Ssat Middle Level Quantitative (Math)

If candidate A receives votes for every votes that candidate B receives. At the end of the election candidate B has 255 votes. How many votes did candidate A get?

Possible Answers:

$127\tfrac{1}{2}$

255

123

237

Correct answer:

$127\tfrac{1}{2}$

Explanation:

In order to solve this problem we need to create a ratio with the given information. It says that for every votes cast for candidate A, candidate B got votes. We can write the following ratio.

$A:B\rightarrow\frac{A}{B}$

Now substitute in the given numbers.

$3:6\rightarrow \frac{3}{6}$

Reduce.

$\frac{3}{6}=\frac{1}{2}$

We know that candidate B received 255 votes. Write a new ratio.

$A:320\rightarrow\frac{A}{255}$

Now, use the original relationship to create a proportion and solve for the number of votes that candidate A received.

$\frac{1}{2}=\frac{A}{255}$

Cross multiply and solve for .

2(A)=255(1)

Simplify.

2A=255

Divide both sides of the equation by .

$\frac{2A}{2}=\frac{255}{2}$

Solve.

$A=127\tfrac{1}{2}$

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Example Question #2 : Ratios & Proportional Relationships

If candidate A receives vote for every votes that candidate B receives. At the end of the election candidate B has 300 votes. How many votes did candidate A get?

Possible Answers:

302

160

310

150

Correct answer:

150

Explanation:

In order to solve this problem we need to create a ratio with the given information. It says that for every vote cast for candidate A, candidate B got votes. We can write the following ratio.

$A:B\rightarrow\frac{A}{B}$

Now substitute in the given numbers.

$1:2\rightarrow \frac{1}{2}$

We know that candidate B received 300 votes. Write a new ratio.

$A:300\rightarrow\frac{A}{300}$

Now, use the original relationship to create a proportion and solve for the number of votes that candidate A received.

$\frac{1}{2}=\frac{A}{300}$

Cross multiply and solve for .

2(A)=300(1)

Simplify.

2A=300

Divide both sides of the equation by .

$\frac{2A}{2}=\frac{300}{2}$

Solve.

A=150

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Example Question #2 : Ratios & Proportional Relationships

If candidate A receives votes for every votes that candidate B receives. At the end of the election candidate B has 320 votes. How many votes did candidate A get?

Possible Answers:

500

357

$325\tfrac{2}{3}$

$533\tfrac{1}{3}$

525

Correct answer:

$533\tfrac{1}{3}$

Explanation:

In order to solve this problem we need to create a ratio with the given information. It says that for every votes cast for candidate A, candidate B got votes. We can write the following ratio.

$A:B\rightarrow\frac{A}{B}$

Now substitute in the given numbers.

$5:3\rightarrow \frac{5}{3}$

We know that candidate B received 320 votes. Write a new ratio.

$A:320\rightarrow\frac{A}{320}$

Now, use the original relationship to create a proportion and solve for the number of votes that candidate A received.

$\frac{5}{3}=\frac{A}{320}$

Cross multiply and solve for .

3(A)=320(5)

Simplify.

3A=1600

Divide both sides of the equation by .

$\frac{3A}{3}=\frac{1600}{3}$

Solve.

$A=533\tfrac{1}{3}$

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Example Question #29 : How To Find A Ratio

If candidate A receives votes for every vote that candidate B receives. At the end of the election candidate B has votes. How many votes did candidate A get?

Possible Answers:

185

137

135

155

Correct answer:

185

Explanation:

In order to solve this problem we need to create a ratio with the given information. It says that for every votes cast for candidate A, candidate B got vote. We can write the following ratio.

$A:B\rightarrow\frac{A}{B}$

Now substitute in the given numbers.

$5:1\rightarrow \frac{5}{1}$

We know that candidate B received votes. Write a new ratio.

$A:37\rightarrow\frac{A}{37}$

Now, use the original relationship to create a proportion and solve for the number of votes that candidate A received.

$\frac{5}{1}=\frac{A}{37}$

Cross multiply and solve for .

1(A)=37(5)

Simplify and solve.

A=185

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SSAT Middle Level Math : Numbers and Operations

Study concepts, example questions & explanations for SSAT Middle Level Math

All SSAT Middle Level Math Resources

Example Questions

Example Question #21 : Ratio And Proportion

Example Question #1 : Ratios & Proportional Relationships

Example Question #1 : Ratios & Proportional Relationships

Example Question #1 : Ratios & Proportional Relationships

Example Question #1 : Ratios & Proportional Relationships

Example Question #684 : Ssat Middle Level Quantitative (Math)

Example Question #685 : Ssat Middle Level Quantitative (Math)

Example Question #2 : Ratios & Proportional Relationships

Example Question #2 : Ratios & Proportional Relationships

Example Question #29 : How To Find A Ratio

All SSAT Middle Level Math Resources

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