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SSAT Middle Level Math : Ratio and Proportion

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Example Questions

Example Question #191 : Ratio And Proportion

Melissa ran sprints for $180\textup{ seconds}$ , and Megan ran sprints for $5\textup { minutes}$ . How many more minutes did Megan run than Jessica?

Possible Answers:

$5\textup { minutes}$

$2\textup { minutes}$

$6\textup { minutes}$

$4\textup { minutes}$

$3\textup { minutes}$

Correct answer:

$2\textup { minutes}$

Explanation:

The first thing we need to do is put our seconds into minutes because our final answer is asking for minutes. We know that 1min=60sec . We can set up a proportion and cross multiply to solve.

$\frac{1min}{60sec}=\frac{x}{180sec}$

60sec(x)=180sec(1min)

Then we can divide to isolate the .

$\frac{60sec(x)}{60sec}=\frac{180sec(1min)}{60sec}$

x=3min

Now we need to subtract to find our difference.

5min-3min=2min

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Example Question #192 : Ratio And Proportion

Megan studied for $120\textup { minutes}$ everyday from Monday-Friday. How many total hours did she spend studying?

Possible Answers:

$11\textup { hours}$

$10\textup { hours}$

$14\textup { hours}$

$12\textup { hours}$

$13\textup { hours}$

Correct answer:

$10\textup { hours}$

Explanation:

The first thing we need to do is put our minutes into hours because our final answer is asking for hours. We know that 1hr=60min . We can set up a proportion and cross multiply to solve.

$\frac{1hr}{60min}=\frac{x}{120min}$

60min(x)=120min(1hr)

Then we can divide to isolate the .

$\frac{60min(x)}{60min}=\frac{120min(1hr)}{60min}$

x=2hr

Now we need to multiply $2\times5$ because Megan studied for hours each day.

$2hr\times5=10hr$

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Example Question #193 : Ratio And Proportion

How many $\textup{meters}$ are in $10\textup{ centimeters?}$

Possible Answers:

$.1\textup { meter}$

$1\textup { meter}$

$.01\textup { meter}$

$.001\textup { meter}$

$10\textup { meters}$

Correct answer:

$.1\textup { meter}$

Explanation:

To solve this problem we can make proportions.

We know that $1\ centimeter= .01\ meters$ and we can use as our unknown.

$\frac{1\ centimeter}{.01\ meter}=\frac{10\ centimeters}{x\ meters}$

Next, we want to cross multiply and divide to isolate the on one side.

$1\ centimeter\times x\ meters=.01\ meter\times10\ centimeters$

$x\ meters=\frac{.01\ meter\times 10\ centimeters}{1\ centimeter}$

The centimeters will cancel and we are left with $.1\ meters$

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Example Question #194 : Ratio And Proportion

How many $\textup{ meters}$ are in $3\textup{ centimeters?}$

Possible Answers:

$300\textup { meters}$

$.03\textup { meters}$

$.003\textup { meters}$

$3\textup { meters}$

$30\textup { meters}$

Correct answer:

$.03\textup { meters}$

Explanation:

To solve this problem we can make proportions.

We know that $1\ centimeter= .01\ meters$ and we can use as our unknown.

$\frac{1\ centimeter}{.01\ meter}=\frac{3\ centimeters}{x\ meters}$

Next, we want to cross multiply and divide to isolate the on one side.

$1\ centimeter\times x\ meters=.01\ meter\times 3\ centimeters$

$x\ meters=\frac{.01\ meter\times 3\ centimeters}{1\ centimeter}$

The centimeters will cancel and we are left with $.03\ meters$

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SSAT Middle Level Math : Ratio and Proportion

Study concepts, example questions & explanations for SSAT Middle Level Math

All SSAT Middle Level Math Resources

Example Questions

Example Question #191 : Ratio And Proportion

Example Question #192 : Ratio And Proportion

Example Question #193 : Ratio And Proportion

Example Question #194 : Ratio And Proportion

All SSAT Middle Level Math Resources

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