All SAT Math Resources
Example Questions
Example Question #29 : Systems Of Equations
Bobbie's Boots makes winter boots. Their monthly fixed expenses are $600. The cost for making a pair of boots is $35. The boots sell for $75 a pair.
What is the monthly break-even point?
The break-even point is where the costs equal the revenue.
Costs:
Revenue:
So Costs = Revenue or
Solving for shows the break-even point is achieved when 15 pairs of boots are sold in a month.
Example Question #2021 : Sat Mathematics
Bobbie's Boots makes winter boots. Their monthly fixed expenses are $600. The cost for making a pair of boots is $35. The boots sell for $75 a pair.
To make a profit of $200, how many pairs of boots must be sold?
Profits = Revenue - Costs
Revenue:
Costs:
So
Solving:
for means that 20 pairs of boots must be sold to make $200 profit.
Example Question #31 : Systems Of Equations
Solve the following system of equations:
What is the sum of and ?
This problem can be solved by using substitution. Write the first equation in terms of and substitute it into the second equation.
So and thus and solving for and then .
So the sum of and is 7.
Example Question #32 : Systems Of Equations
Find .
We have 3 unkown variables and only 2 equations. Instead of trying to solve for or , notice that we can substitute 2 in for the entire expression :
Substitution gives:
Subtract 8 from both sides:
Divide by 3:
Example Question #261 : New Sat
An amusement park charges both an entrance fee, and a fee for every ride. This fee is the same for all rides. Lisa went on 6 rides and paid 120 dollars. Tom went on only 4 rides and paid 95 dollars. What was the entrance fee?
We need 2 equations, because we have 2 unkown variables. Let = the entrance fee, and = the fee per ride. One ride costs dollars. We know that Lisa spent 120 dollars in total. Since Lisa went on 6 rides, she spent dollars on rides. Her only other expense was the entrance fee, :
Apply similar logic to Tom:
Subtracting the second equation from the first equation results in:
Divide both sides by 2:
So every ride costs 12.5 dollars. Plugging 12.5 back into one of the original equations allows us to solve for the entrance fee:
Subtract 50 from both sides:
Example Question #2022 : Sat Mathematics
Solve the system of equations.
For this system, it will be easiest to solve by substitution. The variable is already isolated in the second equation. We can replace in the first equation with , since these two values are equal.
Now we can solve for .
Now that we know the value of , we can solve for by using our original second equation.
The final answer will be the ordered pair .
Example Question #33 : Systems Of Equations
Solve for .
Solve the system of equations using substitution.
First, isolate one of the variables. Since we are solving for , we are going to isolate in the second equation.
Replace with in our first equation.
Now we can solve to isolate .
Example Question #33 : Systems Of Equations
A train leaves the station going 60 miles per hour. Twenty minutes later another train leaves going 100 miles per hour. How much time it take from the time the second train leaves the station until it catches up with the first train?
28 minutes
42 minutes
30 minutes
20 minutes
10 minutes
30 minutes
After 20 minutes the first train would have traveled 20 miles. Let x be the amount of time elapsed. When 20 + 60x = 100x you will have the time in hours. 20 = 40x, x = 0.5 hrs. 0.5 hrs = 30 minutes.
Example Question #33 : Systems Of Equations
In the following system of equations, what is the value of m – n?
6
8
2
4
–2
–2
Solve by method of elimination. Multiply the first equation by 8 to eliminate the variable, m. Our first equation will then become .
By adding this new equation
with our second equation
We will see that our m cancel out. We can now solve for n.
Now we have to plug in this value of n into any of our equations to find the value of m.
Let's use the second equation.
Example Question #2023 : Sat Mathematics
Solve for and .
Substitution needs to be used in order to solve this system of equations. From the second equation we know that ,
Substitute that into the first equation and solve.
You get
From there solve for y using the second equation.