All SAT Math Resources
Example Questions
Example Question #1881 : Sat Mathematics
Solve
First multiply by the denominator on each side
Expand left side, and solve for
Example Question #1 : How To Find The Solution To A Rational Equation With Lcd
–2
0
–1
2
1
2
Example Question #2 : How To Find The Solution To A Rational Equation With Lcd
–bm/(m2 + 1)
bm/(m2 + 1)
b/(m2 + 1)
–b/(m2 – 1)
–b/(m + 1)
b/(m2 + 1)
Example Question #3 : How To Find The Solution To A Rational Equation With Lcd
In the equation below, , , and are non-zero numbers. What is the value of in terms of and ?
Example Question #1 : How To Find The Solution To A Rational Equation With Lcd
Solve for x:
The first step is to cancel out the denominator by multiplying both sides by 7:
Subtract 3 from both sides to get by itself:
Example Question #3 : How To Find The Solution To A Rational Equation With Lcd
Solve for and using elimination:
and
and
and
and
and
and
When using elimination, you need two factors to cancel out when the two equations are added together. We can get the in the first equation to cancel out with the in the second equation by multiplying everything in the second equation by :
Now our two equations look like this:
The can cancel with the , giving us:
These equations, when summed, give us:
Once we know the value for , we can just plug it into one of our original equations to solve for the value of :
Example Question #111 : Equations / Inequalities
Give the solution set of the rational equation
Multiply both sides of the equation by the denominator :
Rewrite both expression using the binomial square pattern:
This can be rewritten as a linear equation by subtracting from both sides:
Solve as a linear equation:
Example Question #2 : How To Find The Solution To A Rational Equation With Lcd
Solve:
Multiply by on each side
Subtract on each side
Multiply by on each side
Example Question #1 : Linear / Rational / Variable Equations
Find the solution to the following equation if x = 3:
y = (4x2 - 2)/(9 - x2)
3
no possible solution
0
6
no possible solution
Substituting 3 in for x, you will get 0 in the denominator of the fraction. It is not possible to have 0 be the denominator for a fraction so there is no possible solution to this equation.
Example Question #3 : Linear / Rational / Variable Equations
I. x = 0
II. x = –1
III. x = 1
I only
II only
III only
II and III only
I, II, and III
I only