All SAT Math Resources
Example Questions
Example Question #11 : Probability
A coin is flipped 4 times. What is the probability of getting 4 heads in a row?
The probability a heads will show on any flip is 1/2. To find the probability of 4 consecutive heads, multiply the probability of each individual flip together.
1/2 * 1/2 * 1/2 * 1/2 = 1/16
Example Question #14 : Probability
A restaurant offers two different entrees, four different side dishes, and three desserts. If a customer wants to order a meal special that consists of one entree, two different side dishes, and one dessert, how many different meals are possible?
Our strategy is as follows: We must determine the number of possible entrees, the number of possible combinations of two side dishes, and the number of desserts. Then we must multiply these four numbers together to get the number of all of the possible meals.
Let's label the two different entrees E1 and E2 The customer can choose one of these, so he has two different options for his entree.
Let's label the four different side dishes S1, S2, S3, and S4. The customer can only choose two of these four dishes, and the order in which he chooses doesn't matter. For example, if he were to choose mashed potatoes and broccoili, he would end up with the same meal as if he were to choose broccoli and then mashed potatoes. So we need to consider all of the different pairs that can be selected from these four side dishes. Here are all of the possible combinations:
S1 and S2
S1 and S3
S1 and S4
S2 and S3
S2 and S4
S3 and S4
This means that the customer has six different combinations of two side dishes.
Finally, the customer can choose one dessert from three different choices. This means there are three possibilities for dessert.
So, the customer has two different options for entrees, six different options for the two side dishes, and three different choices for dessert. To find the total number of meals possible, we can multiply these three numbers together.
Number of meals = 2 x 6 x 3 = 36.
The answer is 36.
Example Question #15 : Probability
How many positive four-digit integers have the thousands digit equal to 8 and the units digit (ones digit) equal to 5?
10
99
100
20
200
100
The number of possibilities in a joint event (that is, the entire four-digit integer) is the product of the number of possibilities of each individual event (the number of possibilities for each digit individually). If WXYZ represents a 4-digit integer, the problem tells us that there is only one possible value for W (which is 8) and only possible value for Z (which is 5). We also know that there are ten possibilities each for X and Y (they can be the digits 0-9). So the number of possible values for WXYZ is the product of the possible values for each digit, which is 1 * 10 * 10 * 1 = 100.
Example Question #21 : Probability
Nora is packing for a trip. Of the scarves in her closet, 8 are blue. She will randomly pick one of the scarves to pack. If the probability is 2/5 that the scarf she will pick is blue, how many scarves are in her closet?
13
22
20
16
18
20
We are told that there are 8 blue scarves in the closet, and that the probability of a blue scarf being chosen is 2/5. So, if T represents the total scarves in the closet, we know that 8/T = 2/5.
Cross-multiplying gives:
40 = 2T
And dividing both sides by 2 gives:
20 = T
Therefore, Nora has a total of 20 scarves in her closet.
Example Question #21 : Probability
Two dice are rolled. What is the probability that the product of the numbers rolled is 15?
1/4
1/18
1/36
1/6
1/9
1/18
The only possibility to roll a product of 15 is to roll a 5 on the first dice and a 3 on the other, or a 3 on the first and 5 on the second. There are 36 total possibilities for two dice (6 * 6), 2 possibilities out of 36 gives you 2/36 = 1/18.
Example Question #112 : Statistics
A jar contains three red marbles, four blue marbles, and six green marbles. Jennifer draws a marble and then draws a second one without replacement. What is the probability that she will draw a blue marble and then a green marble?
18/169
24/169
3/26
2/13
4/13
2/13
There are three red marbles, four blue marbles, and six green marbles. This means that there are a total of thirteen marbles.
The probability of drawing a blue marble on the first drawy would be 4/13.
Because Jennifer doesn't replace the marble, after she draws the blue marble, there are only twelve marbles left. This means that the probability of next drawing a green marble would be 6/12 = 1/2.
To find the probability of the two events happening together, we must multiply them. In general, when you want to find the probability of one event AND another, you must multiply.
probability = (4/13)(1/2) = 2/13
The answer is 2/13.
Example Question #21 : How To Find The Probability Of An Outcome
The Sugar Shak has a "make your own sundae" bar. You can choose one of three ice creams (strawberry, chocolate, or vanilla), one of three sauces (strawberry, carmel, or chocolate), and one of four toppings (peanuts, whipped cream, cherry, or M&Ms). How many different sundaes can be made?
40
10
25
18
36
36
We have three choices for ice cream, three choices for sauces, and four choices for toppings. Each selection is an independent event, so the choices are multiplied together: 3 * 3 * 4 = 36.
Example Question #3102 : Sat Mathematics
A bag contains two white marbles, five green marbles, and three red marbles. What is the probability of picking two red marbles if replacement is not allowed?
6/7
2/3
1/5
1/15
3/5
1/15
Probability is a number between 0 (will not happen) and 1 (will definitely happen). Probability is generally a fraction where the numerator is the total of what you want to happen and the denominator is the total count.
Total ways to choose two red marbles: 3 * 2 = 6
Total ways to choose two marbles: 10 * 9 = 90
Therefore, the probability of choosing two red marbles is 6/90 or 1/15
Example Question #22 : How To Find The Probability Of An Outcome
What is the probability of choosing three hearts in three draws from a standard deck of playing cards, if replacement of cards is not allowed?
21/500
57/1000
11/850
13/750
43/250
11/850
The standard deck of cards has 52 cards: 13 cards in 4 suits.
Ways to choose three hearts: 13 * 12 * 11 = 1716
Ways to choose three cards: 52 * 51 * 50 = 132600
Probability is a number between 0 and 1 that is defines as the total ways of what you want ÷ by the total ways
The resulting simplified fraction is 11/850
Example Question #22 : Probability
A number between 1 and 15 is selected at random. What are the odds the number selected is a multiple of 6?
2/15
The answer is not listed
1/7
3/15
3/7
2/15
In the set of 1 to 15, two numbers, 6 and 12, are multiples of 6. That means there are two chances out of 15 to select a multiple of 6.
2/15