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SAT Math : x and y Intercept

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Example Question #11 : How To Find X Or Y Intercept

The slope of a line is $m=\frac{4}{3}$ . The line passes through $(2,7)$ . What is the x-intercept?

Possible Answers:

$\left ( -3\frac{1}{4},0\right )$

$(0,4.3)$

None of the available answers

$(0,9\frac{2}{3})$

$(4\frac{1}{3},0)$

Correct answer:

$\left ( -3\frac{1}{4},0\right )$

Explanation:

The equation for a line is:

$y=mx+b$ , or in this case

$y=\frac{4}{3}x+b$

We can solve for $b$ by plugging in the values given

$7=\frac{4}{3}\times 2+b$

$7=2\frac{2}{3}+b$

$b=7-2\frac{2}{3}=4\frac{1}{3}$

Our line is now

$y=\frac{4}{3}x+4\frac{1}{3}$

Our x-intercept occurs when $\dpi{100} y=0$ , so plugging in and solving for $\dpi{100} x$ :

$\dpi{100} 0=\frac{4}{3}x+4\frac{1}{3}$

$\dpi{100} -\frac{13}{3}=\frac{4}{3}x$

$\dpi{100} x=-\frac{13}{4}$

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Example Question #215 : Coordinate Geometry

Determine the x-intercept for the equation: y=3x+9

Possible Answers:

$\frac{1}{3}$

$-\frac{1}{9}$

Correct answer:

Explanation:

The x-intercept is the x-value when the value of y=0 . Substitute this value and solve for .

0=3x+9

-9=3x

$x=\frac{-9}{3}=-3$

The x-intercept is .

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Example Question #601 : Geometry

What is the y intercept of y=12x+3?

Possible Answers:

y=12

y=-3

The line does not cross the y axis.

y=3

$x=\frac{-3}{12}$

Correct answer:

y=3

Explanation:

To find the y intercept, substitute x=0

y=12(0)+3

y=3

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Example Question #217 : Coordinate Geometry

At what point does the line $\pi x + \frac{\pi}{2}y - 2\pi = 0$ intersect the y-axis?

Possible Answers:

(0, 4)

$(\pi, \pi)$

(0.5, 0.5)

None of the given answers

$(\pi, \frac{1}{2}\pi)$

Correct answer:

(0, 4)

Explanation:

We know that in slope-intercept form, y=mx+b , that represents the y-intercept. So, let's rewrite this line and put it in slope-intercept form.

$\pi x + \frac{\pi}{2}y - 2\pi = 0$

$\frac{\pi}{2}y = -\pi x + 2\pi$

$y = \frac{2}{\pi}(-\pi x+2\pi)$

y = -2x +4

Therefore, when x=0 , y=4 . With this in mind, our y-intercept is (0, 4) .

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Example Question #11 : How To Find X Or Y Intercept

Give the area of the triangle on the coordinate plane that is bounded by the -axis, and the lines of the equations y = x and $y = -\frac{4}{3} x + 3$ .

Possible Answers:

$1 \frac{13}{14}$

None of the other choices gives the correct response.

$2 \frac{25}{28}$

$5\frac{11}{14}$

$3 \frac{6}{7}$

Correct answer:

$1 \frac{13}{14}$

Explanation:

It is necessary to find the vertices of the triangle, which can be done by finding the three points at which two of the three lines intersect.

The intersection of the -axis - the line x = 0 - and the line of the equation y = x , is found by noting that if x = 0 , then, by substitution, y = 0 ; this point of intersection is at (0,0) , the origin.

The intersection of the -axis and the line of the equation $y = -\frac{4}{3} x + 3$ is the -intercept of the latter line. Since its equation is written in slope-intercept form y = mx+b , with the -coordinate of the -intercept, this intercept is (0, 3) .

The intersection of the lines with equations y = x and $y = -\frac{4}{3} x + 3$ can be found using the substitution method, setting y = x in the latter equation and solving for :

$x = -\frac{4}{3} x + 3$

$x+ \frac{4}{3} x= -\frac{4}{3} x + 3 + \frac{4}{3} x$

$\frac{7}{3} x=3$

$\frac{3} {7} \cdot \frac{7}{3} x= \frac{3} {7} \cdot 3$

$x= \frac{9} {7} =1\frac{2}{7}$

Since y = x , $y =1\frac{2}{7}$ , making $\left ( 1\frac{2}{7}, 1\frac{2}{7} \right )$ the point of intersection.

The lines in question are graphed below, and the triangle they bound is shaded:

Triangle z

If we take the vertical side as the base, its length is seen to be 3; the height is the horizontal distance to the opposite vertex, which is its -coordinate $1 \frac{2}{7}$ . The area is half the product of the two, or

$A = \frac{1}{2} \cdot 3 \cdot 1 \frac{2}{7} = 1 \frac{13}{14}$ .

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Example Question #211 : Coordinate Geometry

Give the area of the triangle on the coordinate plane that is bounded by the lines of the equations x = -4 , y = x and y = 4x- 7 .

Possible Answers:

$72 \frac{5}{6}$

$54 \frac{5}{8}$

$60\frac{1}{6}$

Correct answer:

$60\frac{1}{6}$

Explanation:

It is necessary to find the coordinates of the vertices of the triangle, each of which is the intersection of two of the three lines.

The intersection of the lines of the equations x = -4 and y = x can easily be found by noting that since x = -4 , by substitution, y = -4 , making the point of intersection (-4. -4) .

The intersection of the lines of the equations x = -4 and y = 4x- 7 can be found by substituting for in the latter equation and evaluating :

y = 4 (-4)- 7 = -16 - 7 = -23

The point of intersection is (-4, -23) .

The intersection of the lines of the equations y = x and y = 4x- 7 can be found by substituting for in the latter equation and solving for :

4x- 7 = x

4x- 7 - x + 7 = x - x + 7

3x = 7

$\frac{3x }{3}= \frac{7}{3}$

$x = 2\frac{1}{3}$

y = x , so $y = 2\frac{1}{3}$ , and this point of intersection is $\left ( 2\frac{1}{3}, 2\frac{1}{3} \right )$ .

The lines in question are graphed below, and the triangle they bound is shaded:

Triangle z

We can take the vertical side as the base of the triangle; its length is the difference of the -coordinates:

b = -4 - (-23) = 19

The height is the horizontal distance from this side to the opposite side, which is the difference of the -coordinates:

$h= 2 \frac{1}{3} - (-4) = 6 \frac{1}{3}$

The area is half their product:

$A = \frac{1}{2} bh = \frac{1}{2} \cdot 19 \cdot 6 \frac{1}{3} =60\frac{1}{6}$

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Example Question #21 : How To Find X Or Y Intercept

Give the area of the triangle on the coordinate plane that is bounded by the axes and the line of the equation y = 2 x - 15 .

Possible Answers:

$56 \frac{1}{4}$

225

$112\frac{1}{2}$

Correct answer:

$56 \frac{1}{4}$

Explanation:

It is necessary to find the vertices of the triangle, each of which is a point at which two of the three lines intersect.

The two axes intersect at the origin, making this one vertex.

The other two points of intersection are the intercepts of the line of equation y = 2 x - 15 . Since this equation is in slope-intercept form y = mx+ b , where is the -coordinate of the -intercept, then b = -15 , and the -intercept is the point (0, -15) . The -coordinate of the -intercept, , can be found by setting y = 0 , x= a and solving for :

2 x - 15 = y

2 a - 15 = 0

2 a = 15

$a = \frac{15}{2} = 7 \frac{1}{2}$ .

The three vertices are located at $(0,0), \left ( 7\frac{1}{2}, 0 \right ), (0. -15)$

The line in question is shown below, with the bounded triangle shaded in:

Triangle z

The lengths of its legs are equal to the absolute values of the nonzero coordinates of its two intercepts - $a' = 7 \frac{1}{2}, b' = 15$ . The area of this right triangle is half their product:

$A = \frac{1}{2} a 'b' = \frac{1}{2} \cdot 7\frac{1}{2} \cdot 15 = 56 \frac{1}{4}$ .

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Example Question #23 : How To Find X Or Y Intercept

What is the value of the -intercept for the line given below?

2y=14x+98

Possible Answers:

3.5

Correct answer:

Explanation:

The x-intercept is where the line crosses the x-axis. In other words,

y=0

This gives:

0=14x+98

Subtracting 98 from both sides gives:

-98=14x

Dividing both sides by 14 gives the final answer:

x=-7

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Example Question #24 : How To Find X Or Y Intercept

Give the area of the triangle on the coordinate plane that is bounded by the -axis, and the lines of the equations y = x and $y = -\frac{4}{3} x + 3$

Possible Answers:

$1 \frac{25}{56}$

$3 \frac{6}{7}$

$2 \frac{25}{28}$

$5\frac{11}{14}$

$1 \frac{13}{14}$

Correct answer:

$1 \frac{25}{56}$

Explanation:

It is necessary to find the vertices of the triangle, each of which is a point at which two of the three lines intersect.

The intersection of the -axis - the line y = 0 - and the line of the equation y = x , is found by noting that if y = 0 , then, by substitution, 0 =x ; this point of intersection is at (0,0) , the origin.

The intersection of the -axis and the line of the equation $y = -\frac{4}{3} x + 3$ is found similarly:

$-\frac{4}{3} x + 3 = y$

$-\frac{4}{3} x + 3 = 0$

$-\frac{4}{3} x + 3 - 3 = 0 - 3$

$-\frac{4}{3} x = - 3$

$-\frac{4}{3} x \cdot \left ( -\frac{3} {4} \right ) = - 3 \cdot \left ( -\frac{3} {4} \right )$

$x = \frac{9}{4} = 2 \frac{1}{4}$

This intersection point is at $\left ( 2 \frac{1}{4}, 0 \right )$ .

The intersection of the lines with equations y = x and $y = -\frac{4}{3} x + 3$ can be found using the substitution method, setting y = x in the latter equation and solving for :

$x = -\frac{4}{3} x + 3$

$x+ \frac{4}{3} x= -\frac{4}{3} x + 3 + \frac{4}{3} x$

$\frac{7}{3} x=3$

$\frac{3} {7} \cdot \frac{7}{3} x= \frac{3} {7} \cdot 3$

$x= \frac{9} {7} =1\frac{2}{7}$

Since y = x , $y =1\frac{2}{7}$ , making $\left ( 1\frac{2}{7}, 1\frac{2}{7} \right )$ the point of intersection.

The vertices are at $(0,0),\left ( 2 \frac{1}{4}, 0 \right ),\left ( 1\frac{2}{7}, 1\frac{2}{7} \right )$ .

The lines in question are graphed below, and the triangle they bound is shaded:

Triangle z

If we take the horizontal side as the base, its length is seen to be the -coordinate of the -intercept, $2 \frac{1}{4}$ ; its (vertical) height is the -coordinate of the opposite vertex, $1\frac{2}{7}$ . The area is half the product of the two, or

$A =\frac{1}{2} \cdot 2 \frac{1}{4} \cdot 1 \frac{2}{7} =1 \frac{25}{56}$

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Example Question #25 : How To Find X Or Y Intercept

Given the line 4x + 3y = 12 , what is the sum of the -intercept and the -intercept?

Possible Answers:

Correct answer:

Explanation:

Intercepts occur when a line crosses the -axis or the -axis. When the line crosses the -axis, then y = 0 and x = 3 . When the line crosses the -axis, then x = 0 and y = 4 . The intercept points are (0, 4) and (3, 0 ) . So the -intercept is and the intercept is and the sum is .

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SAT Math : x and y Intercept

Study concepts, example questions & explanations for SAT Math

All SAT Math Resources

Example Questions

Example Question #11 : How To Find X Or Y Intercept

Example Question #215 : Coordinate Geometry

Example Question #601 : Geometry

Example Question #217 : Coordinate Geometry

Example Question #11 : How To Find X Or Y Intercept

Example Question #211 : Coordinate Geometry

Example Question #21 : How To Find X Or Y Intercept

Example Question #23 : How To Find X Or Y Intercept

Example Question #24 : How To Find X Or Y Intercept

Example Question #25 : How To Find X Or Y Intercept

All SAT Math Resources

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