All SAT Math Resources
Example Questions
Example Question #41 : Expressions
Billy began lifting weights in February. After 6 months, he can lift 312 lbs, a 20% increase in the amount he could lift in February. How much weight could Billy lift in February?
Example Question #733 : Algebra
A metal rod is 36 inches long and divided into 3 sections. The middle section is twice as long as the first section. The third section is 4 inches shorter than the first section. How long are the sections?
None of the above answers
The first piece is 6 inches, the second piece is 10 inches and the third piece is 20 inches
First piece is 20 inches, the second piece is 10 inches and the third piece is 6 inches
The first piece is 15 inches, the second piece is 15 inches and the third piece is 6 inches
First piece is 10 inches, the middle piece is 20 inches, and third piece is 6 inches long.
First piece is 10 inches, the middle piece is 20 inches, and third piece is 6 inches long.
Assume the first section equals inches, then the second(or the middle section) must be equal to and the third piece must be equal to .
and now you solve for which equals 10. Hence the middle piece must be equal to 20 inches and the third piece is only 6 inches long.
Example Question #24 : How To Evaluate Algebraic Expressions
A B
1 2
2 4
3 10
5 34
Using the table above, please select the answer below that expresses the relationship between A and B.
By testing the answers, it can be seen that the only equation to satisfy all cases in the table above is
Example Question #42 : Expressions
Fred has $100 in quarters and nickels. He initially has 260 quarters. He then exchanges some of his nickels for the dimes of a friend. He is left with a total of 650 coins (consisting of quarters, dimes and nickels) still worth $100. How many nickels does Fred have now?
Fred has $100 in quarters and nickels initially. We are also told that he has 260 quarters. This is worth $65. Thus Fred initially has $35 in nickels or 700 nickels.
Fred now exchanges some of his nickels for the dimes of a friend. He ends up with 650 coins. We know that Fred started with 960 coins (700 nickels + 260 quarters). He ends up with 650 coins. The number of quarters remains unchanged, meaning he now has 390 nickels and dimes. These must have the same value as the initial 700 nickels, though, since he didn't lose any money.
Now we can finally set up our solution:
Thus Fred has 80 nickels and 310 dimes.
An alternative solution step is to notice that turning nickels into dimes always occurs in exactly one way: 2 nickels to 1 dime. Every time you do this conversion, you will lose exactly one coin. We then notice that the number of coins drops from 960 to 650, or drops by 310 coins. We thus need to get rid of 310 coins. Since we're only allowed to change nickels into dimes (and lose 1 coin each time), we simply do this 310 times to reach the requisite number of coin losses. We are left with the proper number of coins with the proper value immediately. Since every replacement replaced 2 nickels, we also lost nickels. Our final number of nickels is thus nickels.
Example Question #43 : Expressions
Let , what is the value of ?
Example Question #737 : Algebra
Tim went to the hardware store to buy nails and screws. The screws were being sold for $.07 each and the nails were being sold in packs of 40 for $1.30.
If Tim spent $14.80, how many nails did he buy?
Nails are sold in packs of 40 for $1.30.
Screws are $0.07 each.
Since the total is $14.80, we must have a 0 in the hundredths place. This means that the number of screws must be a multiple of 10 (otherwise it won't be a 0). Now we are essentially dealing with screws in packs of 10 for $0.70.
Now we have 5 values of to check. If is divisible by 7, then we have the right answer.
What we find is that for is divisible by 7.
Thus our answer is 6 boxes or 240 nails.
Example Question #44 : Expressions
Twenty percent of a number, , is four greater than the product of that number and six. Which of the following algebraic equations could be used to find ?
The "is" in the question means "equal," so whatever comes before "is" must be equal to whatever comes after. We will find an expression for the information before "is" and an expression for the information after "is," and then we will set these two expressions equal.
Twenty percent of a number can be represented as 0.2n, because 20% expressed as a decimal is 0.2, and because twenty percent "of" a number means the product of that number and twenty percent.
Four greater than the product of a number and six means that we must first find the product of that number and six, and then increase this value by 4.
The product of a number and six means that we must multiply this number by six, which can be represented by 6n. Increasing 6n by 4 can be modeled by the expression 6n + 4, or 4 + 6n (because of the commutative property of addition).
Setting the two expressions equal gives us 0.2n = 4 + 6n .
Example Question #45 : Expressions
Based on the chart, which equation represents the table data?
The easiest way to solve this problem is to guess-and-check the answer choices. The equation that can be used to match the table will be correct.
We can see that the values in the table match the equation for each given value. Thus, this must be our answer.
We can also determine certain characteristics from the table itself. For example, as x increases, y(x) decreases. This tells us that there is likely a negative coefficient, which can help narrow down the answer options.
Example Question #46 : Expressions
An elementary school class consists of boys and girls. What fraction of the class is female?
There are B+G total students in the elementary school class, so G out of B+G are girls.
Example Question #47 : Expressions
What is the sixth term of the sequence:
Each term equals the previous term multiplied by .
The fifth term in the sequence is .
The sixth term in the sequence is thus .