All PSAT Math Resources
Example Questions
Example Question #68 : Algebraic Functions
Which of the following is equal to if ?
To solve, we can set the given function equal to six and solve for .
Add 3 to each side:
Take the square root. Remember that the root can be positive OR negative:
Subtract 3 from each side. It will be easiest to separate the equation into two parts:
Now we know that is equal to or . Based on the available answer options, the correct choice must be .
You can also solve this question by checking each answer option separately; you should find the same final answer.
Substitute each of the answer choices to see which one makes the equation equal to 6.
The answer to this question is . No other answer makes the equation equal 6.
Example Question #331 : Algebra
If is an odd integer, and is an even integer, which of the following must be even?
Solve this problem using picked numbers. Choose an odd number to represent and an even number to represent . In this case, we have chosen 3 to represent and 2 to represent .
Substitute into each equation to find the correct answer:
This number is even, and likely the answer we are looking for. Just in case, quickly check the other answers to make sure no others come out even.
This expression gives an odd answer and must be incorrect.
This expression gives an odd answer and must be incorrect.
This expression gives an odd answer and must be incorrect.
This expression gives an odd answer and must be incorrect.
Only the first answer is even. The answer is .
Example Question #72 : How To Find F(X)
If
What is ?
To find f(4), input a 4 in every place you see an x in the equation. That gives you
When you simplify this expression, you get
When you add together each part, you get
Example Question #1191 : Algebra
What is the value of the function f(x) = 6x2 + 16x – 6 when x = –3?
0
96
–108
–12
0
There are two ways to do this problem. The first way just involves plugging in –3 for x and solving 6〖(–3)〗2 + 16(–3) – 6, which equals 54 – 48 – 6 = 0. The second way involves factoring the polynomial to (6x – 2)(x + 3) and then plugging in –3 for x. The second way quickly shows that the answer is 0 due to multiplying by (–3 + 3).
Example Question #1041 : Algebra
Given the functions f(x) = 2x + 4 and g(x) = 3x – 6, what is f(g(x)) when x = 6?
16
192
28
144
12
28
We need to work from the inside to the outside, so g(6) = 3(6) – 6 = 12.
Then f(g(6)) = 2(12) + 4 = 28.
Example Question #13 : Algebraic Functions
A function f(x) = –1 for all values of x. Another function g(x) = 3x for all values of x. What is g(f(x)) when x = 4?
–12
–3
12
3
–1
–3
We work from the inside out, so we start with the function f(x). f(4) = –1. Then we plug that value into g(x), so g(f(x)) = 3 * (–1) = –3.
Example Question #1194 : Algebra
What is f(–3) if f(x) = x2 + 5?
14
–14
4
–4
15
14
f(–3) = (–3)2 + 5 = 9 + 5 = 14
Example Question #1042 : Algebra
For all values of x, f(x) = 7x2 – 3, and for all values of y, g(y) = 2y + 9. What is g(f(x))?
14y2 + 3
14x2 – 3
14x2 + 3
2x + 9
7y2 – 3
14x2 + 3
The inner function f(x) is like our y-value that we plug into g(y).
g(f(x)) = 2(7x2 – 3) + 9 = 14x2 – 6 + 9 = 14x2 + 3.
Example Question #1043 : Algebra
Find
Simply plug 6 into the equation and don't forget the absolute value at the end.
absolute value = 67
Example Question #1044 : Algebra
An outpost has the supplies to last 2 people for 14 days. How many days will the supplies last for 7 people?
Supplies are used at the rate of .
Since the total amount of supplies is the same in either case, .
Solve for days to find that the supplies will last for 4 days.
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