The best way to solve this problem is to translate it into an equation, "decreased" meaning subtract and "increased" meaning add:

x – 7 = 10 + 7

x = 24

First find 2%3 = (2 * 3 + 3 * 2)/(6 * 2 * 3) = 12/36 = 1/3, then 3%2 = (2 * 2 + 3 * 3)/(6 * 3 * 2) = 13/36 which is greater.

5 more than 5 = 10

5 + x = 10

Subtract 5 from each side of the equation: x = 5 → 2x = 10

First, we need to find the possible values of k such that f(k) = 0.

We can use the definition of f(x) to write an expression for k.

f(x) = 2x³ + 7x² – 4x

f(k) = 2k³ + 7k² – 4k = 0

In order to solve this equation, we will want to factor as much as we can. We can immediately see that we could take out a k from all three terms.

2k³ + 7k² – 4k = 0

k(2k² + 7k – 4) = 0

Now, we need to factor 2k² + 7k – 4 by grouping. When we multiply the outer two coefficients we get (2)(–4) = –8. The middle coefficient is 7. This means we need to think of two numbers that multiply to give us –8, but add to give us 7. These two numbers are 8 and –1. We can now rewrite 2k² + 7k – 4 as follows:

2k² + 7k – 4 = 2k² + 8k – k – 4

Group the first two terms and the second two terms.

2k² + 8k – k – 4 = (2k² + 8k ) + (–k – 4)

Next, factor out a 2k from the first two terms and a –1 from the last two terms.

(2k² + 8k ) + (–k – 4) = 2k(k + 4) + –1(k + 4)

Then, factor out k + 4 from the 2k and the –1.

2k(k + 4) + –1(k + 4) = (k + 4)(2k – 1)

Thus, 2k² + 7k – 4, when fully factored, equals (k + 4)(2k – 1).

Now, let's go back to the equation k(2k² + 7k – 4) = 0 and substitute (k + 4)(2k – 1) for 2k² + 7k – 4.

k(2k² + 7k – 4) = k(k + 4)(2k – 1) = 0

We now have three factors, and we can set each equal to zero to find the possible values of k.

The first factor is k. This means k = 0 is one value for k.

The next factor is k + 4.

k + 4 = 0

k = –4

The last factor is 2k – 1.

2k – 1 = 0

2k = 1

k = 1/2

The values of k for which f(k) = 0 are 0, –4, and 1/2. However, we are told that k is positive, so this means that k can only be 1/2.

Ultimately, the problem asks us to find g(k). This means we must use the equation for g(x) to find g(1/2).

g(x) = 4x – x³

g(1/2) = 4(1/2) – (1/2)³

= 2 – (1/8)

= 15/8

The answer is 15/8.

We need to translate the information given into an algebraic equation that will help us solve for the integers.

Let x represent the smaller of the two integers. Because they are consecutive even integers, the other integer is equal to x + 2.

We are told that the sum of the two integers is two greater than one-tenth of their product. We can represent the sum of the two integers as x + (x + 2).

To represent one-tenth of the product, we can write (1/10)(x)(x + 2). Two greater than this quantity would be equal to 2 + (1/10)(x)(x + 2). Remember that "two greater" requires us to add 2, while "two times greater" would have required us to multiply by 2. 

Now, we can set the sum equal to two greater than one-tenth the product.

x + (x + 2) = 2 + (1/10)(x)(x + 2)

Multiply both sides by 10 to eliminate the fraction.

10(x + x + 2) = 10(2 + (1/10)x(x + 2))

Distribute the 10 on both sides.

10x + 10x + 20 = 20 + 10(1/10)x(x + 2)

Simplify both sides.

20x + 20 = 20 + x(x + 2)

Distribute the x on the right side.

20x + 20 = 20 + x² + 2x

Subtract 20 from both sides.

20x = x² + 2x

Subtract 20x from both sides.

x² – 18x = 0

Factor out an x.

x(x – 18) = 0

Set each factor equal to zero.

x = 0, or x – 18 = 0, which means x = 0 or 18. However, because we are told that the integers are positive, the value of x must be 18.

The smaller integer is 18. We are asked to find the sum of its factors. To find the factors of 18, we must think of all the pairs of numbers that will multiply to give us 18. The pairs are as follows:

1 and 18, 2 and 9, 3 and 6

This means the factors of 18 are 1, 2, 3, 6, 9, and 18. The sum of these numbers is 1 + 2 + 3 + 6 + 9 + 18 = 39.

The answer is 39.

Since there are twice as many girls as boys, we know that 2b = g.

Since there are 24 total, we know that b + g = 24.

Substituting the first equation into the second equation yields

b + 2b = 24

3b = 24

b = 8

The problem is simple if you do not mix up your values and their meanings. What we know is that for 250 megawatts, we should have 250 times the expenses in each of our categories. Therefore, for our data, we know the following.

For salaries, we have $50,000 * 250 or $12,500,000.

For general expenses, we have $20,000 * 250 or $5,000,000

Therefore, our total is: $12,500,000 + $5,000,000 = $17,500,000

We also could have calculated this by adding $50,000 and $20,000 together to get $70,000 per megawatt. This would be $70,000 * 250 = $17,500,000 as well.

We have to solve the equation 4(3x – 2) = 12. First, we can distribute the left side.

4(3x) – 4(2) = 12

12x – 8 = 12

Then we add 8 to both sides.

12x = 20

Divide both sides by 12.

x = 20/12

Simplify 20/12 by dividing the numerator and denominator by 4.

x = 20/12 = 5/3

The answer is 5/3.