Call Now to Set Up Tutoring:

(888) 888-0446

Precalculus : Convert Polar Equations To Rectangular Form and vice versa

Study concepts, example questions & explanations for Precalculus

Create An Account

All Precalculus Resources

12 Diagnostic Tests 380 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #51 : Polar Coordinates

Write the equation (x^2 -3y +y^2 ) ^2 = 4x^2 + 4y^2 in polar form

Possible Answers:

$r = 2+3 \sin \theta$

$r = 4 + 3 \sin \theta$

$r = 3 \sin \theta$

$r = 2 - 3 \sin \theta$

$r = 4 - 3 \sin \theta$

Correct answer:

$r = 2+3 \sin \theta$

Explanation:

First re-arrange the original equation so that the 4 is factored out on the right side, and put x^2 and y^2 next to each other:

(x^2 + y^2 - 3y)^2 = 4(x^2 + y^2)

Make the substitutions r^2 = x^2 + y^2 and $y = r \sin \theta$ :

$(r^2 - 3 r \sin \theta )^2 = 4r^2$ take the square root of both sides

$r^2 - 3 r \sin \theta = 2 r$ divide both sides by r

$r - 3 \cos \theta = 2$ add $3 \cos \theta$ to both sides

$r = 2 + 3 \cos \theta$

Report an Error

Example Question #52 : Polar Coordinates

Which is equivalent to $y = \frac{1}{2}x^2$ ?

Possible Answers:

$r = \frac{2 \sin \theta }{\cos ^2 \theta}$

$r = \frac{\sin \theta}{ 2 \cos ^ 2 \theta }$

$r = \frac{2 \cos \theta }{\sin ^2 \theta}$

$r = \frac{\cos \theta }{ 2\sin ^2 \theta }$

$r = \frac{\cos ^2 \theta}{ 2 \sin \theta }$

Correct answer:

$r = \frac{2 \sin \theta }{\cos ^2 \theta}$

Explanation:

To convert, substitute $y = r \sin \theta$ and $x = r \cos \theta$ :

$r \sin \theta = \frac{ 1}{2} r^2 \cos ^2 \theta$ divide both sides by r

$\sin \theta = \frac{1}{2} r \cos ^2 \theta$ multiply both sides by 2

$2 \sin \theta = r \cos ^2 \theta$ divide both sides by cosine squared

$\frac{ 2\sin \theta }{ \cos ^2 \theta } = r$

Report an Error

Example Question #53 : Polar Coordinates

Convert to polar form: y = 2x + 1

Possible Answers:

$r = \frac{ 2}{ \sin \theta - \cos \theta }$

$r = \frac{1}{ \sin \theta - 2 \cos \theta }$

$r = \sin \theta - 2 \cos \theta$

$r = \frac{ 1 }{ 2\sin \theta - \cos \theta }$

Correct answer:

$r = \frac{1}{ \sin \theta - 2 \cos \theta }$

Explanation:

Convert by making the substitutions $x = r \cos \theta$ and $y = r \sin \theta$ :

$r \sin \theta = 2 r \cos \theta + 1$ subtract $2 r \cos \theta$ from both sides

$r \sin \theta - 2 r \cos \theta = 1$ factor out r

$r (\sin \theta - 2 \cos \theta ) = 1$ divide

$r = \frac{ 1 }{ \sin \theta - 2 \cos \theta}$

Report an Error

View Pre-Calculus Tutors

Tracy
Certified Tutor

Clarion University of Pennsylvania, Bachelor of Science, Physics.

View Pre-Calculus Tutors

Yaakoub
Certified Tutor

CUNY Queens College, Bachelor of Science, Finance. Vaughn College of Aeronautics and Technology, Bachelor of Science, Electri...

View Pre-Calculus Tutors

Emmanuel
Certified Tutor

Baylor University, Bachelor of Science, Biology, General.

All Precalculus Resources

12 Diagnostic Tests 380 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

LSAT Tutors in Los Angeles, LSAT Tutors in New York City, Spanish Tutors in San Diego, Chemistry Tutors in Atlanta, SSAT Tutors in Houston, Algebra Tutors in Miami, SAT Tutors in Washington DC, English Tutors in New York City, Calculus Tutors in San Francisco-Bay Area, GRE Tutors in Los Angeles

Popular Courses & Classes

GRE Courses & Classes in Houston, SAT Courses & Classes in Seattle, SSAT Courses & Classes in Boston, GMAT Courses & Classes in Houston, GRE Courses & Classes in San Diego, ISEE Courses & Classes in San Francisco-Bay Area, ACT Courses & Classes in Seattle, GRE Courses & Classes in Dallas Fort Worth, Spanish Courses & Classes in Boston, GRE Courses & Classes in New York City

Popular Test Prep

GRE Test Prep in Miami, SSAT Test Prep in San Diego, LSAT Test Prep in Boston, LSAT Test Prep in Chicago, GRE Test Prep in Houston, GMAT Test Prep in Houston, SAT Test Prep in Dallas Fort Worth, GRE Test Prep in Denver, MCAT Test Prep in Washington DC, ACT Test Prep in Seattle

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Precalculus : Convert Polar Equations To Rectangular Form and vice versa

Study concepts, example questions & explanations for Precalculus

All Precalculus Resources

Example Questions

Example Question #51 : Polar Coordinates

Example Question #52 : Polar Coordinates

Example Question #53 : Polar Coordinates

All Precalculus Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: