MCAT Physical : Nuclear Chemistry and Electrons

Study concepts, example questions & explanations for MCAT Physical

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Example Questions

Example Question #11 : Radioactive Decay

Which of the following types of radioactive decay alters the mass number?

Possible Answers:

Positron emission

All of these will alter the mass number

Alpha decay

Beta decay

Electron capture

Correct answer:

Alpha decay

Explanation:

The mass number is the total number of nucleons (protons and neutrons) in an atom's nucleus. An atom that undergoes alpha decay will lose a helium nucleus. This decreases its mass number by four. All other forms of radioactive decay listed alter the atomic number of the atom, but not the mass number.

Beta emission involves the conversion of a neutron to a proton and an electron, but only expels the electron.

Electron capture involves the conversion of a proton and an electron into a neutron.

Positron emission involves the conversion of a proton to a neutron and a "positron," or positively charged electron.

Example Question #11 : Radioactive Decay

A sample of radioactive material decays from 64 atoms to 4 atoms in 6 hours. What is the half-life of this substance?

Possible Answers:

Correct answer:

Explanation:

The half-life is the time it takes to reduce a sample by one-half of the original quantity. The substance would have to go through four half-life cycles to go from 64 atoms to 4 atoms.

If the total time for four cycles is 6 hours, then the half life is:

Example Question #1 : Orbitals And Hybridization

Electronegativity is an important concept in physical chemistry, and often used to help quantify the dipole moment of polar compounds. Polar compounds are different from those compounds that are purely nonpolar or purely ionic. An example can be seen by contrasting sodium chloride, NaCl, with an organic molecule, R-C-OH. The former is purely ionic, and the latter is polar covalent.  

When comparing more than one polar covalent molecule, we use the dipole moment value to help us determine relative strength of polarity. Dipole moment, however, is dependent on the electronegativity of the atoms making up the bond. Electronegativity is a property inherent to the atom in question, whereas dipole moment is a property of the bond between them.

For example, oxygen has an electronegativity of 3.44, and hydrogen of 2.20. In other words, oxygen more strongly attracts electrons when in a bond with hydrogen. This leads to the O-H bond having a dipole moment.

When all the dipole moments of polar bonds in a molecule are summed, the molecular dipole moment results, as per the following equation.

Dipole moment = charge * separation distance

A single polar bond, such as the O-H bond described in the passage, is made up of two shared electrons. Before they join together in a bond, what subshell corresponds to the second quantum number (L) of the highest energy valence electrons of oxygen and hydrogen, respectively?

Possible Answers:

p and p

s and p

p and s

s and s

d and s

Correct answer:

p and s

Explanation:

The highest energy electrons are those that are in the orbitals most removed from "s," in the order of .

As you add electron shells (n = 1 to n =2 to n = 3 and so on), you add one more of these orbitals. The result is that hydrogen only has an "s" orbital because it has n = 1, but oxygen has "s" and "p" because it has n = 2.

Example Question #1 : Orbitals And Hybridization

Consider the following combustion reaction.

What is the hybridization of carbon as a reactant? What is the hybridization of carbon as a product?

Possible Answers:

Reactant carbon configuration: sp3

Product carbon configuration: sp2

Reactant carbon configuration: sp3

Product carbon configuration: sp3

Reactant carbon configuration: sp

Product carbon configuration: sp3

Reactant carbon configuration: sp3

Product carbon configuration: sp

Correct answer:

Reactant carbon configuration: sp3

Product carbon configuration: sp

Explanation:

In order to find the hybridization of an atom, simply count the number of sigma bonds and lone electron pairs around the atom. The s subshell is filled first, followed by the three p subshells.

Carbon as a reactant (methane) has four hydrogens around it, giving it four bonds. As a result, it displays sp3 hybridization.

As a product (carbon dioxide), carbon is attached to two oxygen atoms. These two sigma bonds give the carbon sp hybridization.

Example Question #1 : Orbitals And Hybridization

Fundamental, or f orbitals, have shapes that are quite complex and difficult to draw. How many suborbitals are there in the f block?

Possible Answers:

Five

Three

Seven

One

Two

Correct answer:

Seven

Explanation:

The f orbital is expressed in the lanthanides and the actinides. These groups contain fourteen elements in each row. Since each suborbital can contain two electrons, the correct answer is fourteen divided by two, or seven.

The trend for suborbitals is determined by the l quantum number. The number of possible values for l determine the number of subshells.

Example Question #1 : Orbitals And Hybridization

How many electrons can fit in the  electron shell?

Possible Answers:

Six

Eight

Ten

Eighteen

Fourteen

Correct answer:

Eighteen

Explanation:

An  shell contains 3s, 3d, and 3p subshells. Any s shell can hold up to two electrons, any p shell can hold six electrons, and any d shell can hold ten electrons.

This question is best solved by using quantum numbers. We are given the principle quantum number. Using this, we can work down to determine how many electrons can fit in this shell. The rules for quantum numbers are given below.

If the principle quantum number is three, then the next quantum number can be zero, one, or two. These correspond to the s, p, and d subshells, respectively.

After that, the next quantum number describes the orbitals within the subshells. Each orbital can carry two electrons, according to the final quantum number.

In total, there are eighteen electrons allowed in all subshells of the third energy level.

Example Question #2 : Orbitals And Hybridization

When writing the electron configuration for a 4p subshell, a student places two electrons in the first orbital before placing any in the other two. Which fundamental concept is the student forgetting?

Possible Answers:

VESPR rules

Pauli exclusion principle

Hund’s rule

Newton’s second law

Heisenberg’s uncertainty principle

Correct answer:

Hund’s rule

Explanation:

Hund's rule states that every orbital in a subshell must be half-filled (occupied by one electron) before a second electron is added to any of them, thus, Hund's rule is the correct answer. The Pauli exclusion principle states that no two electrons may have the same four quantum numbers, and Heisenberg's uncertainty principle says that we cannot simultaneously know the position and momentum of a subatomic particle. Newton's laws and VSEPR rules have nothing to do with quantum mechanics.

Example Question #3 : Orbitals And Hybridization

Which molecule has the shortest bond between two carbons?

Possible Answers:

Butane

Benzene

Ethyne

Ethene

Correct answer:

Ethyne

Explanation:

Bond distance is related to the type of bond between the two atoms. The more bonds between two atoms, the shorter the distance. In other words, a triple bond is shorter than a double bond, and a double bond is shorter than a single bond. Ethyne is the only option that has a triple bond between the carbons, so it has the shortest bond distance.

Example Question #7 : Orbitals And Hybridization

What is the electron configuration of chlorine?

Possible Answers:

Correct answer:

Explanation:

Each period (row) of the periodic table corresponds to a principle quantum number, or electron energy shell. An electron is added for each element as one moves across the period. The first two electrons (groups 1 and 2) are placed in the s subshell. The next six electrons (groups 13 through 18) are placed in the p subshell.

Chlorine has an atomic number of 17, meaning that it will have a total of 17 electrons distributed through these shells and subshells. Start at the 1s subshell and work upward. Note that there is no 1p subshell.

Chlorine: 1s22s22p63s23p5

Another way of writing electron configuration for an element is to first write the noble gas that comes immediately before that element in brackets, and then write the rest of the notation. For example, the bracket notation for chlorine would be: [Ne]3s23p5

Example Question #1 : Nuclear Chemistry

What is the electron configuration of potassium after it obtains a +1 charge? 

Possible Answers:

[Ne]3s1

[Ar]4s23d4

[Ar]4s2

[Ar]

[Ar]4s1

Correct answer:

[Ar]

Explanation:

Potassium (K) is orignially in the electron configuration of [Ar]4s1. To obtain a +1 charge it loses an electron, resulting in a configuration of [Ar]. 

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